How do human activities contribute to the EXTREME effects of Habagat and Amihan?

The difference in Sansa's and Arya's experiences of the earthquake could be attributed to their geographical locations and the distance from the epicenter.

The intensity of an earthquake tends to decrease as the distance from the epicenter increases. Sansa, residing in Eyrie, which is likely closer to the epicenter, experienced a stronger impact as the earthquake directly caused the Gates of the Moon to collapse.

On the other hand, Arya, residing on the island of Braavos, which is farther away from the epicenter, felt a milder effect. The earthquake was not strong enough to cause significant damage to structures on Braavos, resulting in only a few tiles falling off roofs.

The variation in their experiences can be attributed to the distance and the attenuation of the seismic waves as they traveled from the epicenter to different locations.

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The induced current after the entire loop has entered the uniform magnetic field is 6.5 A.

In the problem statement given, a loop is being pushed at a uniform 0.2-T magnetic field, which is directed out of the page. The resistance of the loop is 0.4Ω. When the loop is entering the magnetic field, its induced current is 1.3 A and the direction of the current is clockwise. The question is asking for the induced current after the entire loop has entered the uniform magnetic field.The formula to find the induced current is given by Faraday's Law of Electromagnetic Induction,i = ε/R where ε is the induced emf, R is the resistance of the loop, and i is the induced current.

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In order to reach the maximum height of 2 meters, Kangaroo should jump with an initial speed of 6.26 m/s.

The three equations of motion are -

first law → v = u +at

second law → S = ut + 1/2 at²

Third law → v² - u² = 2aS

Given is a kangaroo who jumped 2 meters high.

Assume that the kangaroo jumped with an initial velocity of 'u' m/s.

The maximum height achieved is 2 meters.

Acceleration due to gravity will be -9.8 m/s²

At maximum height, the velocity will be zero. Therefore, the final velocity 'v' will be zero. Using third law →

v² - u² = 2aS

- u² = - 2gS  

u² = 2gS

u² = 2 x 9.8 x 2

u² = 39.2

u = 6.26 m/s

Therefore, in order to reach the maximum height of 2 meters, Kangaroo should jump with an initial speed of 6.26 m/s.

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Acceleration due to gravity states that when an object falls freely towards the surface of earth from a certain height, then there is a change in velocity which produces acceleration in the object which is known as acceleration due to gravity denoted by g.

The value of acceleration due to gravity is. g=9. 8m/s2.

How do you measure Acceleration due to gravity on planet X?

Here we have a pendulum so using ruler we can measure the length = L and using pendulum's SHM trials count by stopwatch we can get time period " T " as whole we have here two quantities like L and T

Substituting in equation " 1 " we can find the gravity of the planet " X ".

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Answer:

The work done by the 20 N force is 61.3 J

Explanation:

20 N Force at horizon is: F=20 N*cos 40=15.32 N

The work done by 20 N at horizon is: W=F*S=15.32 N* 4 m=61.3 J

Answer:

The work done by the 20 N force is 61.3 J

Explanation:

A group of stars that form a pattern are called a constellation. This pattern of stars (B) stays together and seems to move as a unit is the correct option, because Asterism is the name for a collection of stars that form a pattern.

It is also known as a constellation, and astronomers use the phrase to describe a region of the sky. An area of the celestial sphere known as a constellation is one in which a collection of discernible stars appears to create a pattern or outline, generally resembling an animal, mythological figure, or inanimate object.

The first constellations probably have their origins in prehistoric times. They were used by people to share tales about their beliefs, encounters, creations, or mythology. Before the current constellations were acknowledged worldwide, various cultures and nations adopted their own constellations, some of which persisted into the first decade of the 20th century. Over time, there have been substantial changes in how constellations are recognised. Many had size or shape changes. Some gained popularity,

Therefore, the correct option is (B).

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Answer:

5.95 m/s to the right

Explanation:

Before the collision, the momentum of the system is given by:

p = m1v1 + m2v2

p = (9.00 kg)(14.0 m/s) + (12.0 kg)(-5.00 m/s)

p = 125.0 kg m/s (to the right)

During the collision, the two masses stick together, so their final velocity will be the same. Let's call this final velocity vf. The momentum of the system after the collision is given by:

p' = (m1 + m2)vf

p' = (9.00 kg + 12.0 kg)vf

p' = 21.0 kg vf

Since momentum is conserved in the collision (there are no external forces acting on the system), we can set p = p' and solve for vf:

125.0 kg m/s = 21.0 kg vf

vf = 5.95 m/s (to the right)

Therefore, the final velocity of the combined masses after the collision is 5.95 m/s to the right.

The incandescent lamp was a major innovation in the field of lighting, allowing for brighter and more controllable light than previous lighting technologies.

The lamp worked by passing an electric current through a filament, which heated up and emitted light.

Thomas Edison's invention of the incandescent lamp in 1879 was a major breakthrough in lighting technology and had a significant impact on many industries, including theatre, film, and photography.

The incandescent lamp also had a profound effect on society, improving quality of life by enabling longer work hours and increased leisure time and spurring further technological advances in lighting and electricity.

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Billy jumps upward with a velocity of 4.2 m/s off a 6m high diving board.  . Billy will take 0.43 sec  to hit the water

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics.

using equation of kinematics

v = u + g*t

sign convention

positive y direction (upward) = +

negative y direction ( downward )  = -

v = u - g*t

0 = 4.2 - ( 9.8 * t )

t = 4.2 / 9.8

t = 0.43 sec

Billy will take 0.43 sec  to hit the water

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Answer:

1120 N

Explanation:

The velocity with which he hits the water can be found with kinematics:

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-9.8 m/s²) (-9.00 m)

v = -13.3 m/s

Or it can be found with conservation of energy.

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × -9.8 m/s² × -9.00 m)

v = -13.3 m/s

Sum of forces on the diver after he hits the water:

∑F = ma

F − mg = m Δv/Δt

F − (74.0 kg) (9.8 m/s²) = (74.0 kg) (0 m/s − (-13.3 m/s)) / (2.50 s)

F = 1120 N

A. X is approximately a binomial random variable because it is the number of successful trials (students giving a positive rating) out of a fixed number of trials (500 students selected) and the trials are independent.

B. To use a Normal approximation, we can use the Central Limit Theorem which states that the sum of a large number of independent and identically distributed random variables will tend to have a normal distribution. So, we can approximate X ~ N(np, npq), where n = 500, p = 0.72, and q = 1 - p = 0.28.

Then, we can find the probability that 400 or more students would give their teacher a positive rating by using the cumulative distribution function (CDF) of a Normal distribution.

P(X >= 400) = P(Z >= (400-np)/sqrt(npq))

where Z is a standard normal variable

We can use a standard normal table or calculator to find P(Z >= (400-np)/sqrt(npq))

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The final speed of the car after the first 4.00 s of acceleration is 13.9 m/s. Therefore, option (b) is correct.

The given problem involves determining the final speed after the first 4 seconds of acceleration. Thus, it is safe to assume that the car accelerated uniformly from rest.

The initial velocity of the car, u = 0 km/hr = 0 m/s

Final velocity of the car, v = 100 km/hr = 27.8 m/s

Time, t = 8.00 s

Acceleration, a = ?

We know that the distance traveled by the car (S) during uniform acceleration can be calculated using the following equation:

S = ut + 1/2 at² ……………….(1)

where u = initial velocity, a = acceleration, t = time, and S = distance traveled.

Substituting the values in the above equation, we get:

100,000 = 0 + 1/2 a (8.00)²a

              = 3.47 m/s²

Now, to determine the final speed of the car after 4 seconds of acceleration, we use the following equation:

v = u + at ……………….(2)

where v = final velocity, u = initial velocity, a = acceleration, and t = time.

Substituting the values in equation (2), we get:

v = 0 + 3.47 m/s² (4.00 s)v

  = 13.9 m/s

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The incorrect statement is a. The ball does not accelerate in the horizontal direction.

When the ball is projected horizontally, it moves forward with a constant horizontal velocity. This means that it does not accelerate in the horizontal direction, so statement a is incorrect. However, in the vertical direction, the ball is subject to the force of gravity, which causes it to accelerate downwards at a rate of 9.8 m/s^2. This means that the ball's vertical velocity changes by 9.8 m/s each second. When the ball hits the ground, it has both a horizontal and vertical velocity, so statement c is also incorrect.

The incorrect statement is a. The ball does not accelerate in the horizontal direction. However, in the vertical direction, the ball is subject to the force of gravity, which causes it to accelerate downwards at a rate of 9.8 m/s^2. When the ball hits the ground, it has both a horizontal and vertical velocity, so statement c is also incorrect.

When a ball is projected horizontally from the top of a cliff and free falls to the ground, it does not accelerate in the horizontal direction, but it does accelerate in the vertical direction due to the force of gravity. When the ball hits the ground, it has both a horizontal and vertical velocity.

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When using the spectroscope to view the spectra of the discharge lamps, what observations are recorded by the wavelengths and colors of all bands.

The spectra of discharge lamp from spectroscope shows the different electromagnetic spectrum, they include the following;

The electromagnetic spectrum consists of radiations of different wavelengths which are indicated by different color bands.

Thus, when using the spectroscope to view the spectra of the discharge lamps, what observations are recorded by the wavelengths and colors of all bands.

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It will take approximately 0.43 seconds for the ball to reach the ground when it is pushed from a height of 0.9 meters above the ground. The statement "the ball takes 1.0 seconds to hit the floor" is incorrect.

The problem requires us to find the time taken by a ball to reach the ground if it is pushed from a height of 0.9 meters above the ground. We can solve this problem using the kinematic equation: h = (1/2) gt² + v₀t + h₀

where

h = height = 0.9 mg = acceleration due to gravity = 9.8 m/s² (approximately)

v₀ = initial velocity = 0

h₀ = initial height = 0 (as it is measured from the ground)

Therefore, the kinematic equation for the given problem is:

0.9 = (1/2) (9.8) t² + 0t + 0.9

Simplifying the above equation, we get:

4.9t² = 0.9-1t² = 0.9/4.9t = √(0.9/4.9)t ≈ 0.43 seconds

Hence, the given statement is incorrect.

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the problem given is that the mass of the chain is 0.032 kg. Below is the step by step explanation to the problem.The balance point of the meter stick moved 14.2 cm from the center, which means that the weight on one side of the stick must have been greater than the other.

Since the stick was balanced before the chain was added, the weight of the chain must have been equal to the weight of the stick that is at a distance of 14.2 cm from the center of the stick.To find the mass of the chain, we need to know the mass of the stick that was at a distance of 14.2 cm from the center. First, we can find the mass of the entire stick. The mass of the meter stick is 0.179 kg.

Since it balances at the center, we can assume that the center of mass of the stick is at the center. Therefore, the mass of each half of the stick is equal to 0.179 kg / 2 = 0.0895 kg.Now, we can find the mass of the half of the stick that is 14.2 cm away from the center. We know that the balance point moved 14.2 cm toward the end with the chain. Therefore, the distance between the balance point and the center of the stick is 14.2 cm. Since the center of mass is at the center of the stick, the distance between the end of the stick and the center of the stick is also 14.2 cm. Therefore, the mass of the half of the stick that is 14.2 cm away from the center is 0.0895 kg × 14.2 cm / 50 cm = 0.025256 kg.Finally, we can find the mass of the chain. Since the weight of the chain is equal to the weight of the half of the stick that is 14.2 cm away from the center, the mass of the chain is also 0.025256 kg. However, this is only the mass of the half of the chain that is on one side of the stick. Therefore, the total mass of the chain is 2 × 0.025256 kg = 0.050512 kg. However, this is the mass of two halves of the chain. Therefore, the mass of the chain is 0.050512 kg / 2 = 0.032 kg.

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The given statement that “rate of crystallization is higher when a solution is more saturated" is true.However, we must first understand the meaning of "crystallization" and "saturation" before answering the question.The process by which a solid forms from a liquid or gas phase is known as crystallization.

A solution is saturated if it contains the maximum quantity of solute that may dissolve in the solvent at a particular temperature and pressure. A solution can be classified as unsaturated if it contains less than the saturation level, and supersaturated if it contains more than the saturation level. What is the relationship between crystallization and saturation.

When a solution reaches its saturation point, the solute is no longer soluble in the solvent. As a result, any extra solute added to the solution will form crystals. Furthermore, when a solution is highly saturated, the crystals will form at a faster rate than when it is not as concentrated. As a result, the statement "rate of crystallization is higher when a solution is more saturated" is true.

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Answer:

(i)  Electric field outside the shell:

For point r>R; draw a spherical gaussian surface of radius r.

Using gauss law, ∮E.ds=q0qend

Since E is perpendicular to gaussian surface, angle betwee E is 0.

Also E being constant, can be taken out of integral.

So, E(4πr2)=q0q

So, E=4πε01r2q

Answer:

jwuwhisbuebeu said that good morning and private s the

Answer:

the answer to this question is a⁵/c²

Answer:

The match is made of wood or paper, mainly cellulose, a carbohydrate. When it burns, carbon and hydrogen combine with oxygen in the air and go off into the atmosphere. The match loses mass, but the mass goes somewhere else—in this case, the atmosphere. When a match burns, its mass decreases

Explanation:

PLEASE GIVE ME BRAINLIEST IF NEW IT SHOULD SAY NEAR MY ANSWER MARK AS BRAINLIEST IF NOT YOULL HAVE TO WAIT A DAY AND BRAINLY WILL REMIND YOU

Answer:…..

Explanation:

The quantity of heat energy supplied to the water from the metal is 2520 J.

The quantity of heat energy needed to increase the temperature of one kilogram of a substance by one degree Celsius is known as the substance's specific heat capacity.

Here,

Mass of the water in the container, m = 50 g = 0.05 kg

Initial temperature of the water, T₁ = 20°C = 293 K

Final temperature of the water, T₂ = 32°C = 305°C

Specific heat capacity of water, C = 4200 J/kgK

The expression for the quantity of heat energy supplied to the water from the metal is given by,

Q = mcΔT

Q = mC(T₂ - T₁)

Applying the values of m, C, T₁ and T₂

Q = 0.05 x 4200 (305 - 293)

Q = 210 x 12

Q = 2520 J

Hence,

The quantity of heat energy supplied to the water from the metal is 2520 J.

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A photon with an energy equal to this negligible kinetic energy would also have a very low energy.

At low particle speeds, the kinetic energy of an electron is given by the equation

KE = 1/2 mv^2, where m is the mass of the electron and v is its speed.

However, as the speed of the electron approaches the speed of light (c), relativistic effects become significant.

The relativistic equation for the kinetic energy of a particle is

KE = (γ - 1)mc^2, where γ is the Lorentz factor given by

γ = 1/√(1 - (v^2/c^2)).

At low speeds, v is much smaller than c, so the term v^2/c^2 is negligible.

Thus, γ is approximately equal to 1, and the kinetic energy equation reduces to KE = (1 - 1)mc^2 = 0.

In other words, at low speeds, the kinetic energy of an electron is effectively zero. Therefore, a photon with an energy equal to this negligible kinetic energy would also have a very low energy.

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Answer:

10 m/s²

Explanation:

Since the body is falling freely from the rest, it will be having an acceleration equal to the acceleration due to gravity.

∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².

Answer:

10 m/s^2 I hope it helps u a lot

The magnitude of  force between the two charges is 4.8 x 10^-2 N.

This can be calculated using Coulomb's law:

F = (k * q1 * q2) / r^2

Plugging in the given values, we get:

F = (9.0 x 10^9 N m^2/C^2) * (2.0 x 10^-4 C) * (8.0 x 10^-4 C) / (0.30 m)^2

Simplifying the expression, we get:

F = 4.8 x 10^-2 N

Therefore, the magnitude of the force between the two charges is 4.8 x 10^-2 N.

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The scientist that described an atom made a solid positively charged substance with electrons dispersed throughout it was: Ernest Rutherford.

In 1911 Ernest Rutherford proposed his atomic model in which he considered the atom as a positively, densely charged center called a nucleus in which the electrons circulate around the core with a negative charge.

He was responsible for many discoveries in the radioactivity's  fields and nuclear physics.

The atom is the smallest part of the composition of matter, it is indivisible and is composed of a nucleus that has protons and neutrons, and around the nucleus there are the electrons.

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Answer:

The answer is "\(0.13562748\)"

Explanation:

Please find the complete question in the attached file.

Using formula:

\(\bold{U_s=\frac{v^2}{rg}}\)

Given:

\(r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}\)

put the value into the above-given formula:

\(U_s= \frac{14.583^2}{160 \times 9.8}\)

    \(= \frac{212.663889}{1568}\\\\=0.13562748\)

When a person focuses on an object at a very far distance from the eye, the focal length of the eye at that time is approximately infinity.

The human eye is a complex optical system that can adjust its focus to objects at different distances. The lens of the eye changes its shape to allow for accommodation, enabling the eye to focus on objects at varying distances. However, when a person looks at an object located at an extremely far distance, such as a distant mountain or star, the light rays entering the eye can be considered nearly parallel.

In this scenario, the lens of the eye becomes relatively flat and reaches its least curved state. As a result, the focal length of the eye approximates infinity. Essentially, the eye's focusing mechanism is optimized for parallel light rays, allowing the incoming light to converge at a point that is virtually at an infinite distance from the eye. This enables clear vision and sharp focus on objects situated at extremely far distances.

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Answer:

the acceleration of the elevator is increasing

Explanation:

For this exercise we propose the solution using Newton's second law

         F -W = m a

         F = m (g + a)

If the net force increases, it implies that the acceleration of the elevator is increasing, since the acceleration of gravity is constant as the ascent is accelerating.

A projectile is launched horizontally with a speed of 85.5 m/s. if the projectile is launched 1.6m above the floor, it will take approximately 0.57 seconds for the projectile to hit the floor.

When a projectile is launched horizontally, its vertical motion is influenced by gravity while its horizontal motion remains uniform. In this case, we are given that the projectile is launched horizontally with a speed of 85.5 m/s and starts 1.6 m above the floor.

Since the horizontal motion is uniform, the time taken for the projectile to hit the floor depends only on its vertical motion. The vertical motion can be treated as a free-falling object under gravity.

We can use the equation of motion for free-falling objects:

h = (1/2) * g * t^2

where h is the vertical distance traveled, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time taken.

In this case, the initial vertical displacement h is 1.6 m, and we want to find the time taken t.

1.6 = (1/2) * 9.8 * t^2

Rearranging the equation and solving for t, we have:

t^2 = (2 * 1.6) / 9.8

t^2 ≈ 0.3265

t ≈ √0.3265

t ≈ 0.57 s

Therefore, it will take approximately 0.57 seconds for the projectile to hit the floor.

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We can use the formula of the capacitance

where C is the capacitance, Q is the charge and V is the voltage.

In our case

Q=480 C

V= 110 V

The value of the capacitor is 4.36 F

ANSWER B) 4.36F