Answer:
Wedge
Explanation:
Scissors are a pair of wedges that are combined together.
How do you calculate the maximum angle at which an object will not slip on an incline? I know that it's arctan(μ) but why? Where does that come from? Thank you in advance!
The maximum angle at which an object will not slip on an incline can be calculated using the coefficient of friction (μ).
Balance of forces on an inclineWhen an object is on an inclined plane, there are two main forces acting on it: the gravitational force pulling it downward (mg) and the normal force (N) exerted by the inclined plane perpendicular to its surface. Additionally, there is a frictional force (F) acting parallel to the surface of the incline.
To prevent slipping, the frictional force must be equal to or greater than the force component pulling the object down the incline. This force component is given by the equation F = mg sin(θ), where θ is the angle of inclination.
The maximum frictional force that can be exerted between two surfaces is given by the equation F = μN, where μ is the coefficient of friction.
For an object not to slip, the maximum frictional force (F) must be equal to or greater than the force component pulling the object down the incline (mg sin(θ)). Therefore, we have:
F ≥ mg sin(θ)
Substituting F = μN, we get:
μN ≥ mg sin(θ)
Since N = mg cos(θ) (the normal force is equal to the component of the gravitational force perpendicular to the incline):
μmg cos(θ) ≥ mg sin(θ)
μ cos(θ) ≥ sin(θ)
Now, divide both sides of the equation by cos(θ):
μ ≥ tan(θ)
Taking the inverse tangent (arctan) of both sides, we get:
θ ≤ arctan(μ)
Therefore, the maximum angle at which an object will not slip on an incline is given by θ = arctan(μ).
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Julie takes a cold glass of dear, doness houd out the register and pusi on the babe hathewwad warme up to room temperature, Julie sees buthles of gas form in the und and me to the face Which conclusion is best supported by Jules onervations? The liquid is a pure sutrance because it is closers O The liquid is a mixture because its temperature res The liquid is a pure substance because it remains lowd when The liquid is a mixture because it has a gas dissolved in a loud
Answer:
D. The liquid is a mixture because it has a gas dissolved in a liquid.
Micro-bats use a form of radar called echolocation to navigate and find their prey such as flying insects. They locate the surrounding objects by bouncing sound wave pulses off these objects and detecting the time delay between the emitted pulses and the reflected pulses. Determine the time delay between the pulse emitted by the micro-bat and the detected pulse reflected from an insect located 10 m away from the micro-bat. Assume the approximate speed of sound waves to be 340 m-s-1
Answer:
t = 5.88 10⁻² s
Explanation:
The speed of the sound wave after it is emitted by the bat is constant, so we can use the uniform motion relationships
v = \(\frac{x}{t}\)
t = \(\frac{x}{v}\)
in this case the distance is that of the sound in going from the bat to the insect and back
x = 2d
x = 2 10
x = 20 m
let's calculate
t = 20/340
t = 5.88 10⁻² s
We can see that the time is very short, so the distance traveled by the two animals has little influence on the result.
in a isovolumetric process the is constant.
Answer:
An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0.
Explanation:
:)
In your business plan, the target market section should clearly identify_____market(s).
A. Both your primary and secondary
B. primary
C. demographic
D. secondary
In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.
How has Physics improved
or affected our society?
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency of 400 Hz. The sound he hears reflected back from the wall is at a frequency of 408 Hz. At what is the speed is the boy riding his bicycle toward the wall? Assume the speed of sound in air is 340 m/s.
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7.a railway truck A of a mass of 2000kg moves westwards with a velocity of 3m/s. It collides with a stationary truck B 1200kg, loaded with electronic equipment of mass 300kg. The two trucks combined after collision. Ignore the effects of friction. 7.1. Write down magnitude and direction of the 'reaction force' to the weight
of truck A.
(2)
7.2. Calculate the velocity of truck B after the collision.
(5)
7.3. Calculate the magnitude of the force that the truck A exert on truck B if
the collision lasts for 0,5 s.
(4)
8. The most common reasons for rear-end collisions are too shortfollowing a
distance, speeding and failing brakes. The sketch below represents one such
Answer:
9. A 1500kg car traveling +6m/s with a 2000kg truck at rest. The vehicles collide, but do not stick together. The car has a velocity -3m/s after the collision. What is the velocity of the truck? a. What type of collision occurred above?
Answer yess it’s not
Explanation:
2.the truck is pulled with the force of 20 500 newtons . the trucks acceleration rate is 4 m/ s2. what is the mass of the car
The mass of the truck pulled with a force of 20500N and accelerated at a rate of 4m/s² is 5125kg
HOW TO CALCULATE MASS OF AN OBJECT:
The mass of an object can be calculated by dividing the force required to pull/push it by its acceleration. That is;Force (N) = mass (kg) × acceleration (m/s²)Mass = Force ÷ accelerationAccording to this question, a truck is pulled with the force of 20,500 newtons and it accelerates at a rate of 4 m/s². The mass of truck can be calculated as follows:Mass = 20500 ÷ 4
Mass = 5125kg
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an example of a household appliance with a low and high power rating
Answer:
Explanation:
There are countless household appliances in every single house. One appliance with a low power rating would be a ceiling fan. On average ceiling fans consume roughly 60w and are found in the majority of houses. On the other side of the spectrum, we have a high power-rating appliance such as a microwave. Microwaves use anywhere between 1000w to 1800w of power in order to function correctly. This is very large power consumption and one of the highest power ratings found for appliances in a household.
The current source has an EMF of 14 V and an internal resistance of 1Ω. Two resistors with resistances of 3Ω are connected to the current source. How much current flows in the circuit?
Answer:
Explanation:
To find the current flowing in the circuit, we can use Ohm's Law and Kirchhoff's circuit laws.
Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):
I = V / R
In this case, the voltage (V) is the electromotive force (EMF) of the current source, which is 14 V. The total resistance (R) in the circuit is the sum of the internal resistance (r) and the resistances of the two resistors (R1 and R2):
R = r + R1 + R2
Given that the internal resistance (r) is 1Ω and each resistor (R1 and R2) has a resistance of 3Ω, we can substitute these values into the equation:
R = 1Ω + 3Ω + 3Ω = 7Ω
Now we can calculate the current (I):
I = V / R = 14 V / 7Ω = 2 A
Therefore, the current flowing in the circuit is 2 Amperes.
A 180-kg load is hung on a wire of length of 4.70 m, cross-sectional area 2.000 10-5 m2, and Young's modulus 8.00 1010 N/m2. What is its increase in length?
i saw it online once but i cant find it so i would look this up on maybe quizlet i use it a lot and it helps
16. Which star gives off more red light? Explain your reasoning,
17. Which star gives off more blue light? Explain your reasoning.
18. Which star looks redder? Explain your reasoning.
16. The star with the higher temperature give off more red light.
17. The star with a higher temperature will give off more blue light.
18. The star that looks redder will be the star with the lower temperature, which is Star E.
20. The correct responses are:
Peaks at a longer wavelength: Star CHas a lower surface temperature: Star EHas a greater energy output: Star CHow is a star's brightness explained?The star with a higher temperature will emits more red light. This is because as the temperature of a star increases, the peak wavelength of its emitted radiation shifts towards the blue end of the spectrum, and the relative amount of red light decreases.
The star with the higher temperature emits more blue light. This is because as the temperature of a star increases, the peak wavelength of its emitted radiation shifts towards the blue end of the spectrum, and the relative amount of blue light increases.
The star with the lower temperature, which is Star E, will appear redder. This is because as the temperature of a star decreases, the peak wavelength of its emitted radiation shifts towards the red end of the spectrum.
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what does an animal cell have that a plant cell dosent
Answer:
Animal cells have centrosomes (or a pair of centrioles), and lysosomes, while plant cells don't. Plant cells have a cell wall, chloroplasts, plasmodesmata, and plastids utilized for capacity, and a huge focal vacuole, though creature cells don't.
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A 0.016-kg piece of iron absorbs 1086.75 joules of heat energy, and its
temperature changes from 25°C to 175°C. Calculate the specific heat
capacity of iron. Equation : c = Q/mt
Answer:
c = 115.92 q/g C
Explanation:
0.016 kg = 16 grams
q = Joules
m = mass (g)
t = (final temp. - initial temp)
c = specific heat
c = (1086.75 joules) / (175 C - 25 C) (16 g)
c = 115.92 q/g C
Fill in the magnitude of net force for each case. Including the solution plss
Net forces in all above cases will be
A) F net = 0
B) F net = 1 N
C) F net = 5 N
D) F net = 5N
E) F net = 5 N
F) F net = 5 N
G) F net = 9.9 N
H) F net = 9.9 N
A) net force = upward force - downward force
= 4 - 4 = 0
B) net force = rightward force - leftward force = 4 - 3 = 1 N
C) net force
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = \(\sqrt{25}\) = 5 N
D) F net = \(\sqrt{-4^{2} + (-3)^{2} }\) = 5 N
E) balancing horizontal forces
rightward force - leftward force = 5 - 2 = 3 N
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = 5 N
F) balancing vertical forces
-5 + 2 = -3 N
using Pythagoras theorem
\(\sqrt{(-4)^{2} +(-3) ^{2} }\) = 5 N
G) using Pythagoras theorem
F net = \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
H ) balancing horizontal forces
10 - 3 = 7 N
\(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
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POINTS + BRAINLIEST TO CORRECT ANSWER
In old Polaroid cameras, the image was projected on film that developed inside the camera. The developed image was then ejected from the camera as a printed photograph. The standard film size for one popular camera was 79 mm square. The film was 116 mm behind the lens.
If you wanted a picture of your 1.8-m-tall friend to fill half the frame, how far away from you did she need to stand?
100 points + Brainliest to correct answer
Answer:
5.3 m
Explanation:
Your friend is 1800 mm tall, and you want them to fill half the frame (79 mm / 2 = 39.5 mm).
The film is 116 mm behind the lens. Using similar triangles:
x / 1800 = 116 / 39.5
x = 5286
Rounded to two significant figures, your friend should stand 5.3 meters away.
ASK YOUR TEACHER A 2.0-kg mass swings at the end of a light string with the length of 3.0 m. Its speed at the lowest point on its circular path is 6.0 m/s. What is its kinetic energy at an instant when the string makes an angle of 50 degree with the vertical
Answer:
K_b = 78 J
Explanation:
For this exercise we can use the conservation of energy relations
starting point. Lowest of the trajectory
Em₀ = K = ½ mv²
final point. When it is at tea = 50º
Em_f = K + U
Em_f = ½ m v_b² + m g h
where h is the height from the lowest point
h = L - L cos 50
Em_f = ½ m v_b² + mg L (1 - cos50)
energy be conserve
Em₀ = Em_f
½ mv² = ½ m v_b² + mg L (1 - cos50)
K_b = ½ m v_b² + mg L (1 - cos50)
let's calculate
K_b = ½ 2.0 6.0² + 2.0 9.8 6.0 (1 - cos50)
K_b = 36 +42.0
K_b = 78 J
4. A car travels at a speed of v = 54 km/h. During emergency braking, the wagon decelerates (brakes) with a deceleration (braking) of 3m/s per second. a) Convert the speed into the unit m/ s.b) Calculate how long the braking lasts. c) Sketch the v-t diagram and calculate the braking distance!
The given velocity is 54km/hr, which, when converted to m/s using 1km = 1000m and 1 hour = 3600 seconds, equals 15m/s.
How to calculate distance?Now substitute the initial speed u = 15m/s values.
v = 0m/s as the final velocity
Time is 6 seconds.
In the a= -3 m/ s2 equation,
s= ut + 1/2at2 s= 15 6+ 1/2(-3)(6)2 s= 90-45 s = 45m
As a result, after using the brakes, the car will halt for up to 45 meters.
The inverse of acceleration is deceleration. The deceleration will be calculated by dividing the final velocity minus the initial velocity by the time required for the velocity drop.
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Why is air resistance friction not useful for an airplane?
A. Causes turbulence
B. Speeds it up
C. Slows it down
D. Creates heat
The correct option is C. Air resistance friction is not useful for an airplane because it slows it down.
What is air resistance?Air resistance is the opposition to motion of an object caused by air flow.
High air resistance may cause turbulence during the motion of an air plane. This can lead to engine failure or some mishap during flight.
Air resistance is also a type of friction between air and another material such as airplane.
Effect of air resistance on airplaneFriction between the air and the plane slows the airplane down. This is known as air resistance, or drag.
The faster an object travels through the air, the more it has to fight against drag.
Thus, air resistance friction is not useful for an airplane because it slows it down.
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How much force required to displace a body through 50cm by doing 25J work on it.
Answer:
50 N
Explanation:
W = Fd
F = W/d
first convert cm → m: 50 cm x 1 m/cm = 0.50 m
F = (25 J) / (0.50 m) = 50 N
A bullet traveling at 5.0 x10^2 meters per is brought to rest by an impulse of 50 Newton*seconds. Find the mass of the bullet.
The bullet stops moving on hitting on a surface. Hence, the impulse here is equal to the momentum. Therefore, the mass of the bullet is 0.1 Kg.
What is impulse?Impulse in physics is the change in momentum. It is the product of the force and change in time.
hence, impulse = f. dt
When the bullet is travelling with a velocity of 500 m/s it has a momentum. When it brought to rest, momentum become zero. Thus, the momentum is equal to the impulse here.
Therefore, f.dt = m. v
f.dt = 50 N s
v = 500 m/s
m = 50 N s/500 m/s = 0.1 Kg
Therefore, the mass of the bullet is 0.1 Kg.
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A motorcycle has a constant speed of 29 m/s as it passes over the top of a hill whose radius of curvature is 108 m. The mass of the motorcycle and driver is 350 kg. Find the magnitude of the normal force that acts on the cycle.
The magnitude of normal force (N) on motorcycle is 704.537 N
In this type of scenario, we have been told that the mass, denoted by "m," is 350 kilograms, that the speed of the motorcycle, denoted by "v," is 29 meters per second, and that the radius of curvature, denoted by "R," is 105 meters. We can utilize the second law of motion that Newton proposed to compute the magnitude of the normal force, which is as follows:
\(m . g - N = \frac{mv^{2} }{R}\)
By applying the formula above we have:
\(350 x 9.8 - N= \frac{350x29^{2} }{108}\)
3430 - N = 2725.46296
N = 3430 - 2725.46296
N = 704.537 N
Thus, the magnitude of normal force on motorcycle would be 704.537 N
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1 point
You throw a ball up in the air with a velocity of 30 m/s. How high does it
go?
Answer:
Explanation:
2as=vf^2-Vi^2
vf=30 m/s
vi= 0 m/s
a=g=9.8 m/s^2
s=vf^2-Vi^2/2a
s=(30)²-(0)²/2*9.8
s=900-0/19.6
s=45.9=46 m
A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?
The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and 6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.
4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.For more questions on speed
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Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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A car is moving along a road at 13.0 m/s with an engine that exerts a force of 1,775.0 N on the car to balance the drag and friction so that the car maintains a constant speed. What is the power output of the engine?
Answer:
The power output of the engine can be calculated using the formula:
Power = Force x Velocity
where force is the net force acting on the car, and velocity is the speed of the car. In this case, the net force is equal to the force exerted by the engine, which is 1,775.0 N, since the car is moving at a constant speed and there is no acceleration. The velocity of the car is 13.0 m/s. Thus, the power output of the engine can be calculated as:
Power = 1,775.0 N x 13.0 m/s = 23,075 W
Therefore, the power output of the engine is 23,075 watts.
An object is in circular motion. The radius of its motion is 18.7 m and its velocity is 7 m/s. What is its frequency?
The frequency of the object in circular motion is 0.06 Hz.
What is the frequency of the object in circular motion?The formula to calculate the frequency is derived as follows;
The angular speed, ω is related to the frequency, f, as follows;
ω = 2πf
The linear velocity is related to angular velocity as follows:
v = r ω
ω = v/r
where;
v is the linear speed,
r is the radius, and
ω is the angular speed
Hence,
f = v/2πr
f = 7 / (18.7 * 2π)
Frequency, f = 0.06 Hz
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What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.
Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.
To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.
The energy required to melt 1 kg of ice is 3.33×105 J/kg.
Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.
To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.
Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.
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Two plates labeled A and B are separated and initially neutral. Through some mechanism, 7 μC (microcoulombs) of positive Charge are move from plate A to plate B. Answer below questions about the final electrostatic state of each plate after the transfer. 1) After the transfer is complete, indicate how many excess protons (or singly positive ions) are on Plate B ? 2) After the transfer is complete, what is the sign and number of the uncanceled elemental charges on Plate A. Note: positive values require no sign.
Answer:
1) Approximately \(4\,\,\,10^{13}\) excess protons
2) negative \(4\,\,\,10^{13}\) (\(-4\,\,\,10^{13}\))
Explanation:
1)
Recall that the charge of an electron or proton is approximately: \(1.6\,\,\,10^{-19} \,C\)
Therefore, to find the number of protons transferred in 7 micro-Coulombs of charge, we do:
\(\frac{7\,\,10^{-6}\,}{1.6\,\,10^{-19}} \approx 4\,\,10^{13}\)
Approximately \(4\,\,\,10^{13}\) excess protons
2)
The sign and number of uncanceled elemental charges on plate A is therefore negative \(4\,\,\,10^{13}\) , because the same number of positive charges were removed from it, changing its neutrality