Answers
To solve the problem first, we need the acceleration, in this case, the centripetal acceleration
\(a=\frac{v^2}{R}\)1. v=3m/s , R=0.7m
\(a_c=\frac{3^2}{0.7}=\frac{12.86m}{s^2}\)now the sum of forces, remember the centripetal force always goes to the center. The forces that interact in this point are weight (goes down), centripetal (goes down), and tension which has no defined direction but I'm going to assume it goes up.
\(\begin{gathered} \sum ^{\infty}_{n\mathop=0}Fy=0 \\ 0=T-mg-ma_c \\ T=2\cdot9.81+2\cdot12.86 \\ T=45.34N\text{ going up} \end{gathered}\)2. v=5m/s , R=0.7m
\(a_c=\frac{5^2}{.7}=\frac{35.71m}{s^2}\)now the sum of forces, remember the centripetal force always goes to the center. The forces that interact in this point are weight (goes down), centripetal (goes up), and tension which has no defined direction but I'm going to assume it goes down.
\(\begin{gathered} \sum ^{\infty}_{n\mathop=0}Fy=0 \\ 0=ma_c-mg-T \\ T=2\cdot35.71-2\cdot9.81 \\ T=51.8N\text{ going down} \end{gathered}\)This is for 1.
For 2.
Related Questions
A car, traveling 50ft/s steadily slows to a stop. Determine all unknowns and answer the following question.
Answers
Answer:
100
Explanation:
What is revolution?
A. The motion of an object along a curved path
B. The spinning of an object on its axis
C. The orbit of a satellite around a central body
D. The motion of two objects around each other
Answers
Answer:
A. the motion of an object along a curved path
PHYSICS 1403
Lab Homework - Friction on a Ramp
A laborer wants to move crates containing bottles of olive oil from a truck to the ground by sliding them
along a ramp. The ramp is 6 m long and is at an angle of 25º. There is friction on the ramp for the first
crate. The laborer doesn't know that there is a small leak in one of the bottles. The leak leaves a layer of
oil on the ramp. The oil creates a frictionless surface for the second crate Wayne sends down the ramp. At the bottom of the ramp, the speed of the second crate (without friction) is 2.5 the speed of the first crate (with friction). Find the coefficient of kinetic friction. Hint: this is a multistep problem that is
be solved using only energy equations. Do not use kinematics or you will not receive full
credit, even if your answer is correct. Use conservation of energy and start with the frictionless case.
Answers
Hi there!
Hi there!
We can begin by simplifying the work-energy theorem for Crate 2.
Since there is no friction, there is no energy dissipated. Thus, the initial energy is equal to the final energy.
Initially, we only have gravitational potential energy (U = mgh), and when the box has fully slid down, it only has kinetic energy (KE = 1/2mv²), therefore:
\(E_i = E_f\\\\mgh = \frac{1}{2}mv^2\)
We can cancel out the mass and solve for velocity.
\(gh = \frac{1}{2}v^2\\\\v^2 = 2gh \\\\v = \sqrt{2gh}\)
We must use right triangle trigonometry to solve for the HEIGHT given the ramp's length (hypotenuse).
We can use sine:
\(sin\theta = \frac{\text{h}}{L} \\\\Lsin\theta = h = 6 * sin(25) = 2.5357 m\)
Now, solve for velocity.
\(v = \sqrt{2(9.8)(2.5357)} = 7.05 \frac{m}{s}\)
Since this is 2.5 times the speed of the first crate, we know that the final velocity of crate 1 is:
\(v_1 = \frac{v}{2.5} = 2.82 \frac{m}{s}\)
Crate 1:
In this instance, we have friction. Recall the following.
\(F_f = \mu N\)
On an incline, the normal force is equivalent to the cosine of the force of gravity, so:
\(N = mgcos\theta\)
Now, create an equation for the force due to friction.
\(F_f = \mu mgcos\theta\)
The work done by any force is:
\(W = F \cdot d\\\\W_f = \mu mgdcos\theta\)
In this instance, d = the ramp's length, or 6 m.
Now, we can use the work-energy theorem.
Ei = Ef
However, there is energy dissipated; we can call this Wf (Work due to friction). Therefore:
Ei - Wf = Ef
Now, we can rearrange to solve for Wf:
Ei - Ef = Wf
Like above, there is initially only GPE (U = mgh) and finally only KE (K = 1/2mv²), so:
\(mgh - \frac{1}{2}mv^2 = \mu mgdcos\theta\)
Solve for the coefficient of friction. Begin by canceling out the mass and multiplying all terms by 2:
\(2mgh - mv^2 = 2\mu mgdcos\theta\\\\2gh - v^2 = 2\mu gdcos\theta\\\\\mu = \frac{2gh - v^2}{2gdcos\theta}\\\\\mu = \frac{2(9.8)( 2.5357)- (2.82)^2}{2(9.8)(6)cos(25)}\)
Evaluate:
\(\boxed{\mu = 0.39}\)
You launch a ball at a target with a speed v0 = 10.84 m/s at an angle θ above the horizontal. The target is at a height h = 5.22 m above the level at which you release the ball. You want the ball’s velocity to be horizontal (i.e. vy= 0 m/s) at the instant it reaches the target.
What is the value of the horizontal velocity v0x in m/s?
Enter your value with two (2) decimal places and no units. For example if your answer is 1.276, then enter 1.28.
Answers
Answer:
Explanation:
We can use the kinematic equation for vertical motion to find the value of the initial vertical velocity, v0y:
v0y = v0 * sin(θ)
Next, we can use the equation for vertical motion with constant acceleration (g = 9.8 m/s^2 is the acceleration due to gravity) to find the time it takes for the ball to reach the target:
v0y * t - 0.5 * g * t^2 = h
Solving for t:
t = sqrt(2 * h / g)
Finally, we can use the kinematic equation for horizontal motion (no acceleration in the horizontal direction) to find the horizontal velocity:
v0x = v0 * cos(θ)
So,
v0x = 10.84 * cos(θ) = 10.84 * cos(θ)
v0x = 10.84 * cos(θ) = 10.84 * cos(θ)
We do not have the value of θ, so we cannot determine the exact value of v0x.
what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2
Answers
The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)
Pressure (P) = Density (ρ) × g × Depth (h)
Given: Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Depth (h) = 6 m
Using the given values, one can calculate the pressure:
Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure
= 58800 kg·m⁻¹·s⁻²
Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:
Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)
Pressure = 580.124 atm
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Current Attempt in Progress The atomic radii of a divalent cation and a monovalent anion are 0.52 nm and 0.125 nm, respectively. (a) Calculate the force of attraction between these two ions at their equilibrium interionic separation (i.e., when the ions just touch one another). Enter your answer for part (a) in accordance to the question statement N (b) What is the force of repulsion at this same separation distance
Answers
Answer:
a) F = 1.70 10⁻⁹N, F = 1.47 10⁻⁸ N,
b) * the electronegative repulsion, from the repulsion by quantum effects
Explanation:
a) The atraicione force comes from the electric force given by Coulomb's law,
F = \(k \frac{ q_1 q_2}{r^2}\)
divalent atoms
In this case q = 2q₀ where qo is the charge of the electron -1,6 10⁻¹⁹ C and the separation is given
F = k q² / r²
F = \(2 \ 10^9 \ \frac{2 (1.6 \ 10^{-19} )^2}{ (0.52 10^{-9} )^2 }\)
F = 1.70 10⁻⁹N
monovalent atoms
in this case the load is q = q₀
F = 2 \ 10^9 \ \frac{ (1.6 \ 10^{-19} )^2}{ (0.125 10^{-9} )^2 }
F = 1.47 10⁻⁸ N
b) repulsive forces come from various sources
* the electronegative repulsion of positive nuclei
* the electrostatic repulsion of the electrons when it comes to bringing the electron clouds closer together
* from the repulsion of electron clouds, by quantum effects
7. Imagine you could look at the flashlight from behind your object, looking
from the darkest and lightest parts of the object's shadow. How much of
the light source do you think you could see from each location?
Answers
From the darkest part of the object's shadow, you would be able to see a small amount of the light source. There would be a small amount of light that is visible, but it would be faint. On the other hand, from the lightest part of the shadow, you would be able to see much more of the light source. The light source would be far brighter and more visible, and you would be able to identify the source of the light.
Hope this helps! Have a nice day. :)Light bulbs produce useful energy in the form of light and waste energy in the form of heat. What kind of light bulb would you use
to incubate eggs?
A. low-efficiency light bulbs, because they produce more light
B. low-efficiency light bulbs, because they produce more heat
C. high-efficiency light bulbs, because they produce more heat
D. high-efficiency light bulbs, because they produce more light
Answers
Answer:
C) high efficiency light bulbs, because they produce more heat
Light bulbs produce useful energy in the form of light and waste energy in the form of heat, the kind of light bulb would you use to incubate eggs are low-efficiency light bulbs, because they produce more heat, therefore the correct answer is option B.
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
The type of light bulb you would use to incubate eggs is a low-efficiency light bulb since they produce more heat; consequently, option B is the right response. Light bulbs produce useful energy in the form of light and waste energy in the form of heat.
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How is biochar produced?
Answers
Answer:
Biochar is produced by heating biomass in the total or partial absence of oxygen. Pyrolysis is the most common technology employed to produce biochar, and also occurs in the early stages of the combustion and gasification processes. Besides biochar, bio-oil and gas can be collected from modern pyrolysers.
Two parallel plates 0.800 cm apart are equally and oppositely charged. An electron is released from rest at the surface of the negative plate and simultaneously a proton is released from rest at the surface of the positive plate.
How far from the negative plate is the point at which the electron and proton pass each other?
Express your answer with the appropriate units.
Answers
Answer:
0.79 cm
Explanation:
The computation is shown below:-
Particle acceleration is
\(a = \frac{qE}{m}\)
We will take d which indicates distance as from the negative plate, so the travel by proton is 0.800 cm - d at the same time
\(d = \frac{1}{2} a_et^2\\\\0.800 cm - d = \frac{1}{2} a_pt^2\\\\\frac{d}{0.800 cm - d} = \frac{a_e}{a_p} \\\\\frac{d}{0.800 cm - d} = \frac{m_p}{m_e} \\\\\frac{d}{0.800 cm - d} = \frac{1836m_e}{m_e}\)
After solving the equation we will get 0.79 cm from the negative plate.
Therefore it is 0.79 cm far from the negative pate i.e the point at which the electron and proton pass each other
The point at which the electron and proton pass each other will be 0.79 cm.
What is the charge?When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.
The given data in the problem is;
d' is the distance between the two parallel plates= 0.800 cm
The acceleration is given as;
\(\rm a= \frac{qE}{m} \\\\\)
The distance from Newton's law is found as;
\(d = ut+\frac{1}{2} at^2 \\\\ u=0 \\\\ d= \frac{1}{2} at^2 \\\\ d-d' = \frac{1}{2} a_pt^2 \\\\ 0.800-d= \frac{1}{2} a_pt^2 \\\\\ \frac{d}{0.800-d} =\frac{a}{a_p} \\\\ \frac{d}{0.800-d} =\frac{m_p}{m} \\\\ \frac{d}{0.800-d} =\frac{1836m_e}{m_e} \\\\ d=0.79 \ cm\)
Hence the point at which the electron and proton pass each other will be 0.79 cm.
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Four canisters contain helium gas.
If all the canisters had the same amount of particles, which canister would have the fastest moving particles?
W
X
Y
Z
Answers
D. The canister with the fastest moving particle is Z due to concentration of particle.
Canister with the fastest moving particle
The speed of the particles depend on the mean distance of the particles.
The canister with the largest concentration per particle will contain particles with the greatest speed.
If the particle concentration is increasing from W to Z, then Z will have fastest moving particle.
Thus, the canister with the fastest moving particle is Z due to concentration of particle.
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Answer:
d. Z
Explanation:
If all the canisters had the same amount of particles, which canister would have the fastest moving particles?
Z
A sound wave travels with a velocity of 1.5 m/s and has a frequency of 500 Hz. What is its wavelength?
Answers
Wave velocity (v) is how fast a wave propagates in a given medium. Its unit is meter per second. Check the speed calculator for more information about speed and velocity.
Wavelength (λ) is the distance over which the shape of a wave repeats. It depends on the medium in which a wave travels. It is measured in meters.
Frequency (f) of a wave refers to how many times (per a given time duration) the particles of a medium vibrate when the wave passes through it. The unit of frequency is Hertz or 1/second.
Which best describes friction?
Answers
Answer:
It is the force that opposes motion between two surfaces touching each other. ( OR ) The force between two surfaces that are sliding or trying to slide across each other.
Explanation:
Answer:
a constant force that acts on objects that rub together
Explanation:
a constant force that acts on objects that rub together
prepare a report on why a vehicle needs to be maintained/serviced after a certain period of time. How is servicing different in a petrol/diesel and electric vehicle?
Answers
Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.
Why should cars be maintained and / or serviced ?First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.
The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.
This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.
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What three factors affect the viscosity of magma
Answers
2. The dissolved gases it contains
3. It’s chemical composition
The factors that affect the viscosity of magma include temperature, crystal and rock fragments (composition), and the different dissolved gases.
What is magma?It is a mixture of solid, volatile and liquid materials.
Characteristics of the viscosity of magmaIt is a mixture of chemical components that form high-temperature silicates.It includes substance in solid, liquid and gaseous state due to the temperature of the magma which is above the melting points of certain components.Volcanic eruptions often occur when the vapor pressure of the gases becomes greater than the pressure exerted by the solid rocks that keep the magma confined.Therefore, we can conclude that the fluidity or viscosity of magma depends on its chemical composition and, in particular, the liquids and solids that the magma contains and the various gases dissolved in it.
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A 1000-kg car rolling on a smooth horizontal surface ( no friction) has speed of 20 m/s when it strikes a horizontal spring and is brought to rest in a distance of 2 m What is the spring’s stiffness constant?
Answers
Explanation:
kinetic energy was converted to potential energy in the spring.
the answer is in the above image
The known values are given in the table below them. Find the missing values.
Answers
The value of the missing resistance, R₃ = 10.35 ohms.
The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.
The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.
What is the value of missing component of the circuit?The values of the missing component of the circuit is calculated by applying the following formula.
The total resistance of the circuit;
For R₂, R₃, 1/R = 1/R₂ + 1/R₃
1/R = 1/12 + 1/R₃
1/R = (R₃ + 1)/(12R₃)
R = 12R₃ / (R₃ + 1)
For, R₁, R₂ and R₃, total resistance;
R = 12R₃ / (R₃ + 1) + R₁
R = [12R₃ / (R₃ + 1)] + 2
R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)
R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)
R = (14R₃ + 2 ) / (R₃ + 1)
The total current in circuit is calculated as;
I = V/R
I = 30 / R
I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)
I = (30R₃ + 30) / (14R₃ + 2) ------- (1)
The voltage in parallel circuit is the same
V₂ = V₃ = 24 V
V₃ = IR₃
24 = IR₃
I = 24/R₃ --------- (2)
Solve (1) and (2) together as follows;
24/R₃ = (30R₃ + 30) / (14R₃ + 2)
30R₃² - 306R - 48 = 0
Solve the quadratic equation, using formula method.
R₃ = 10.35 ohms
I₃ = V₃/R₃
I₃ = 24 V / 10.35
I₃ = 2.32 A
If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V
The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A
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a stone on the ground has zero energy why
Answers
Explanation:
it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).
gamma-ray bursts are objects in the universe that emit pulses of gamma rays with high energies. the frequency of the most energetic bursts has been measured at around 3.0 x 1021 hz. what is the wavelength of these gamma rays?
answer options:
1: 1.0 x 10^29 m
2: 1.0 x 10^13 m
3: 1.0 x 10^-13 m
4: 1.0 x 10^-29 m
Answers
Answer:
The answer to your problem is, C. \(1.0 * 10^{3}\)
Explanation:
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometres, and other units since it is a distance measurement.
The relationship between the wave's wavelength, frequency, and speed is given as
Formula ( That I use and you should use ) !
wavelength = speed of light / frequency
\(y = \frac{c}{v}\)
y in this case is the wave length v denotes the wave's speedf is the wave's frequency\(y = \frac{3*10^{3} }{3.0*10^{21} }\)
\(y = 1 * 10^{-13}\)
Thus the answer to your problem is, C. \(1.0 * 10^{3}\)
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4. Which of the following substance will cool off the fastest?
cooper
Iron
Nylon
Aluminum
Answers
Answer:
I'm not sure but I think its aluminum
4. A hot air balloon of mass 250.00 kg at a height of 150.0 m descends slowly into a field. What is the
GPE of the balloon before the descent, in kilojoules?
Answers
The GPE (Gravitational potential energy) of the balloon of mass 250 kg is 367500 J.
What is Gravitational Potential Energy (GPE)?To calculate the GPE of the balloon, we use the formula below.
Formula:
GPE = mgh........... Equation 1Where:
m = Mass of the balloong = acceleration due to gravityh = HeightGPE = Gravitational potential energy.From the question,
Given:
m = 250 kgh = 150 mg = 9.8 m/s²Substitute these values into equation 1
GPE = 250×150×9.8GPE = 367500 JHence, the GPE of the balloon is 367500 J.
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Mark weighs 375 N and is carrying a full-sized cello as he climbs the stairs to a height of 4 m. It takes him 3 seconds to do this.
How does the amount of work he does change if he were to climb the same flight of stairs again in the same amount of time, but this time without the cello?
A) It depends on the weight of the cello.
B) It remains the same.
C) It increases
D) It decreases.
Answers
Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.
The correct answer is option D.
The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :
Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).
When Mark climbs the stairs with the cello, he is doing work against the force of gravity.
The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.
Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.
Therefore, mark's work decreases.
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Write the number below in scientific notation, 35,600 O A. 3.56 x 103 O B. 3.56 x 103 O C. 3.56 x 104 O D. 3.56 x 105
Answers
A spring attached to the ceiling is stretched one foot by a four pound weight. The mass is set in motion by pulling down 2 feet and then released in a medium with a damping force numerically equal to the velocity.
a. Find the Hook's law spring constant k.
b. Find its natural frequency ω.
c. Form a differential equation for the position x(t) of the mass.
d. Determine the solution for the position (in alternate form).
e. Find the times at which the mass passes the equilibrium second time heading up.
Answers
Given that,
Weight = 4 pound
\(W=4\ lb\)
Stretch = 2 feet
Let the force be F.
The elongation of the spring after the mass attached is
\(x=2-1=1\ feet\)
(a). We need to calculate the value of spring constant
Using Hooke's law
\(F=kx\)
\(k=\dfrac{F}{x}\)
Where, F = force
k = spring constant
x = elongation
Put the value into the formula
\(k=\dfrac{4}{1}\)
\(k=4\)
(b). We need to calculate the mass
Using the formula
\(F=mg\)
\(m=\dfrac{F}{g}\)
Where, F = force
g = acceleration due to gravity
Put the value into the formula
\(m=\dfrac{4}{32}\)
\(m=\dfrac{1}{8}\ lb\)
We need to calculate the natural frequency
Using formula of natural frequency
\(\omega=\sqrt{\dfrac{k}{m}}\)
Where, k = spring constant
m = mass
Put the value into the formula
\(\omega=\sqrt{\dfrac{4}{\dfrac{1}{8}}}\)
\(\omega=\sqrt{32}\)
\(\omega=4\sqrt{2}\)
(c). We need to write the differential equation
Using differential equation
\(m\dfrac{d^2x}{dt^2}+kx=0\)
Put the value in the equation
\(\dfrac{1}{8}\dfrac{d^2x}{dt^2}+4x=0\)
\(\dfrac{d^2x}{dt^2}+32x=0\)
(d). We need to find the solution for the position
Using auxiliary equation
\(m^2+32=0\)
\(m=\pm i\sqrt{32}\)
We know that,
The general equation is
\(x(t)=A\cos(\sqrt{32t})+B\sin(\sqrt{32t})\)
Using initial conditions
(I). \(x(0)=2\)
Then, \(x(0)=A\cos(\sqrt{32\times0})+B\sin(\sqrt{32\times0})\)
Put the value in equation
\(2=A+0\)
\(A=2\).....(I)
Now, on differentiating of general equation
\(x'(t)=-\sqrt{32}A\sin(\sqrt{32t})+\sqrt{32}B\cos(\sqrt{32t})\)
Using condition
(II). \(x'(0)=0\)
Then, \(x'(0)=-\sqrt{32}A\sin(\sqrt{32\times0})+\sqrt{32}B\cos(\sqrt{32\times0})\)
Put the value in the equation
\(0=0+\sqrt{32}B\)
So, B = 0
Now, put the value in general equation from equation (I) and (II)
So, The general solution is
\( x(t)=2\cos\sqrt{32t}\)
(e). We need to calculate the time
Using formula of time
\(T=\dfrac{2\pi}{\omega}\)
Put the value into the formula
\(T=\dfrac{2\pi}{4\sqrt{2}}\)
\(T=1.11\ sec\)
Hence, (a). The value of spring constant is 4.
(b). The natural frequency is 4√2.
(c). The differential equation is \(\dfrac{d^2x}{dt^2}+32x=0\)
(d). The solution for the position is \( x(t)=2\cos\sqrt{32t}\)
(e). The time period is 1.11 sec.
A rectangular block of wood has dimensions 240mm×20.5cm×0.040m. calculate its volume in cm³.
Answers
Answer: 1968 cm3
Explanation: You first need to convert all of your dimensions to the same units.
240 mm = 24 cm
20.5 cm = 20.5 cm
0.04 m = 4 cm
Then volume is Length x width x height = 24 cm x 20.5 cm x 4 cm =
Jaleh takes path 1 from point A to point B. She then runs from point B back to point A, following path 3. It takes her 500 seconds to make the round trip.
What is Jaleh's velocity for the entire trip?
Answers
Answer:
C
Explanation:
how to prepare for neet
Answers
Be Familiar With The Syllabus.
High-Quality Study Material.
Create a Realistic Timetable.
Prepare Notes While Learning.
Revise Regularly.
Maintain a Healthy Diet.
Regular Study Breaks are a Must.
Do Proper Exercise.
At t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT . At the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
1.) At what time does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
t=
2.) At what coordinate does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
x =
Answers
1. The truck overtakes the car at time t = 2vC/(aT - aC)
2. The coordinate where the truck passes the car is x = 2aT[vC/(aT - aC)]²
The question has to do with equation of motion
What are the equations of motion?The equations of motion are equations that are used to describe the motion of an object under constant acceleration.
1.) At what time does the truck pass the car?
Since at t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT.
We find the distance moved by the truck using the equation of motion d = ut + 1/2at² where
u = initial speed of truck = 0 m/s(since it starts at rest) a = acceleration of truck = aTSo, d = ut + 1/2at²
d = 0 × t + 1/2aTt²
d = 1/2aTt²
Also, at the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
We find the distance moved by the car using the equation of motion D = ut + 1/2at² where
u = initial speed of car = vC a = acceleration of car = -aCSo, D = ut + 1/2at²
D = vCt + 1/2(-aC)t²
D = vCt - 1/2aCt²
The truck over takes the car when d = D
So, 1/2aTt² = vCt - 1/2aCt²
1/2aTt² - 1/2aCt² - vCt = 0
[(aT - aC)t/2 - vC)]t = 0
⇒ t = 0 or (aT - aC)t/2 - vC = 0
⇒ t = 0 or (aT - aC)t/2 = vC
⇒ t = 0 or t = 2vC/(aT - aC)
So, the truck overtakes the car at time t = 2vC/(aT - aC)
2.) At what coordinate does the truck pass the car?Since the distance moved by the truck is d = x - 0
= 1/2aTt², where x = coordinate where truck passes car.
To find the coordinate where the truck passes the car, we susbstitute the time where the truck passes the car into d. So, t = 2vC/(aT - aC)
So, x - 0 = 1/2aTt²
x = 1/2aT[2vC/(aT - aC)]²
x = 2aT[vC/(aT - aC)]²
So, the coordinate where the truck passes the car is x = 2aT[vC/(aT - aC)]²
Learn more about equations of motion here:
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Jacob Grena raises a spoon 0.210 m above a table . If the spoon and its contents have a mass of 30.0 g, what is the gravitational potential energy associated with the spoon at that height relative to the table's surface?
Answers
Explanation:
The spoon is raised so it gains Gravitational potential energy. Formula to find Gravitational potential energy;
Gravitational potential energy = mass × Gravitational field strength × height of the body from the surface (table in this scenario)
In symbols; E = m×g×h
Substitute values:
m = 30g = 0.03kg (don't forget to convert grams to kg)
g = 10N/kg
h = 0.210 m
So it's;
0.03kg × 10N/kg × 0.210m = 0.063 Joules
SI Unit of energy is joules
in the process of identifying the alcohol contained in the wine, why does color changed into light blue from brown, to dark green, to light green and finally to light blue?
Answers
Answer:
The color of the Anthocyanins changes depending on the PH of what they come into contact with, because wine already has acid in its Anthocyanins are red. But as soon as you expose those Anthocyanins to more alkaline factors, it will start to turn blue.