Question number 3 is the one I need help on

Question Number 3 Is The One I Need Help On

Answers

Answer 1

Given,

Distance Sandy covered while walking east, s₁=10 blocks.

Distance Sandy covered while walking west, s₂=5 blocks.

The total distance covered is the sum of the two distances given in the question.

That is,

\(\begin{gathered} \text{distance}=s_1+s_2 \\ =10+5 \\ 15\text{ blocks} \end{gathered}\)

The displacement is the shortest distance between the starting and ending point of a path.

Let us assume that the eastward direction is positive and the westward direction is negative.

Thus the total displacement of Sandy is given by,

\(\text{displacement}=s_1-s_2\)

On substituting the known values,

\(\text{displacement}=10\text{-5=5 blocks.}\)

Therefore total distance covered by Sandy = 15 blocks.

And the total displacement of the Sandy = 5 blocks


Related Questions

what is - zqxs toivde :: apple flavoured and 8 are blackberry flavoured. She chooses a sweet at random and eats it. Then she chooses another sweet at random. Calculate the probability​

Answers

The probabilities regarding the sweets are given as follows:

a) both sweets were apple flavour: 5/17.

b) both sweets were blackberry flavored: 28/153.

c) the first was apple and the second was blackberry: 40/153.

How to calculate the probabilities?

A probability is calculated as the division of the number of desired outcomes by the number of total outcomes.

The sweets are chosen without replacement, hence the probability that both sweets were of apple flavor is calculated as follows:

p = 10/18 x 9/17 = 5/17.

The probability that both were blackberry flavored is calculated as follows:

p = 8/18 x 7/17 = 28/153.

The probability that the first was apple and the second was blackberry is of:

p = 10/18 x 8/17 = 40/153.

Missing Information

The complete problem is given as follows:

Maria has a bag containing 18 fruit drop sweets. 10 are apple flavoured and 8 are blackberry flavoured. She chooses a sweet at random and eats it. Then she chooses another sweet at random. Calculate the probability that:

a) both sweets were apple flavour

b) both sweets were blackberry flavored

c) the first was apple and the second was blackberry

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As a boss, knowing your employees’ personality types can help you

Answers

Answer:

identify who they are as a person

Explanation:

Help asap!!!


Due right now!! fast!!!


Help asap!!!Due right now!! fast!!!

Answers

Answer:

Not sure but I think its (A)

Explanation:

I think its (A)

Answer:

C

Explanation:

They divided some numbers and got 5

It said something about it accelerates at 10 seconds so all I did was multiply by 2 and I got C

A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?

Answers

The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Electrostatic attraction

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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An object is acted upon by two and only two forces that are equal magnitude and oppositely directed. Is the objected necessarily in static equilibrium? Explain. You can draw a picture if that helps explain.

Answers

Answer:

the body is subjected to a continuous rotation and the body is not in rotational equilibrium

Explanation:

For an object to have a static equilibrium, it must meet two relationships

             ∑ F = 0

             ∑ τ =0              

force acting on a body fulfills the relation of

         sum F = F - F = 0

when two forces do not move from position.

To find the torque we assume that the counterclockwise rotations are positive

        Σ τ = - F r - F r

        Στ = -2 Fr <> 0

consequently the body is subjected to a continuous rotation and the body is not in rotational equilibrium

A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?

Answers

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.

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Where are metals generally found on the periodic table ?

Answers

Answer:

on the left of the periodic table

Answer:

in the middle towards the left

Explanation:

just finished the quiz

Which term is most applicable to a discussion of angular momentum in the context of black holes?
A. photon
B. curvature
C. spin
D. time

Answers

Answer:

Curvature

Explanation:

A 3.00kg mass is attached to an ideal spring with k=200N\m if the velocity of body at 0.25m Is 2.3m\s find the amplitude and maximum velocity

Answers

To solve this we must be knowing each and every concept related to velocity. Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

What is velocity?

V is the velocity measurement of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.

For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below.

v = √(k / m) ×A

v = velocity of the mass

k= spring constant

m =mass of the object

A= amplitude of the oscillation.

substituting all the given values in the above equation, we get

2.3 m/s = √(200 N/m / 3.00 kg)×A

A = 2.3 m/s / √(200 N/m / 3.00 kg)

    = 0.23 m

v =√(200 N/m / 3.00 kg) ×0.23 m

 = 2.75 m/s

Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

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In a reading assignment, the main headings and key concepts are useful for which of
the following?
0000
defining vocabulary words
finding the general location of information in reading assignments
giving exact answers to exam questions
none of the above

Answers

The main headings and key concepts are useful for finding the general location of information in reading assignments. They provide a quick overview of the content and organization of the text, which can help readers to locate specific information more easily. However, they may not always be sufficient for defining vocabulary words or giving exact answers to exam questions, as these tasks often require more detailed and specific information from the text.

EARTH AND SPACE SCIENCE!
All of the following are Kepler's laws of planetary motion EXCEPT?

a.) Planets follow elliptical orbits with the sun at one of its foci
b.) The period of a planet (time it takes to go around the sun) is related to its distance from its Sun
c.) The period of a planet(time it takes to go around the sun) is related to the planet's mass

Answers

C. The period of a planet (time it takes to go around the sun) is not related to its mass.

The first law states that the planets follow elliptical orbits with the sun at one of its foci, the second law states that an imaginary line drawn from the sun to a planet sweeps out equal areas in equal times, and the third law states that the square of the period of a planet is directly proportional to the cube of its average distance from the sun. Since the period of a planet is not related to its mass, answer C is not one of Kepler's laws of planetary motion.

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A seesaw made of a plank of mass 10.0 kg and length 3.00 m is balanced on a fulcrum 1.00 m from one end of the plank. A 20.0-kg mass rests on the end of the plank nearest the fulcrum. What mass must be on the other end if the plank remains balanced?

Answers

Answer:

7.5 kg

Explanation:

We are given that

\(m_1=10 kg\)

Length of plank, l=3 m

Distance of fulcrum from one end of the plank=1 m

\(m_2=20 kg\)

We have to find the mass must be on the other end if the plank remains balanced.

Let m be the mass must be on the other end if the plank remains balanced.

In balance condition

\(20\times 1=10\times (1.5-1)+m\times (1.5+0.5)\)

\(20=10(0.5)+2m\)

\(20=5+2m\)

\(2m=20-5=15\)

\(\implies m=\frac{15}{2}\)

\(m=7.5 kg\)

Hence, mass 7.5 kg   must be on the other end if the plank remains balanced.

Answer:

The mass at the other end is 7.5 kg.

Explanation:

Let the mass is m.

Take the moments about the fulcrum.

20 x 1 = 10 x 0.5 + m x 2

20 = 5 + 2 m

2 m = 15

m = 7.5 kg

A seesaw made of a plank of mass 10.0 kg and length 3.00 m is balanced on a fulcrum 1.00 m from one end

Roots spreading far and wide

Answers

Answer:

₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₣5₣ đ₮ɽ ₮₣ ₮ɽ

Part C Now, grab Tracker’s protractor tool (the green angle in the video frame) and measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below. Hints: To advance the video a frame at a time, use the step buttons on the right. Position the vertex of the protractor exactly at the origin of the coordinate axis. Move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.

Answers

In order to measure the angle of incidence and the angle of refraction using Tracker's protractor tool (the green angle in the video frame), the following steps should be followed:

Step 1: Open the video in Tracker software.

Step 2: Click on the "Measure" button on the toolbar at the top of the software.

Step 3: From the dropdown menu, select "Angle".

Step 4: Click on the "protractor tool" icon (the green angle in the video frame).

Step 5: Position the vertex of the protractor exactly at the origin of the coordinate axis and move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.

Step 6: Measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below by using the step buttons on the right to advance the video a frame at a time.

Step 7: Record the measured angles in the table below. Note that the angle of incidence should be measured on the incident ray (the ray that is coming from the left), and the angle of refraction should be measured on the refracted ray (the ray that is coming from the right).In conclusion, by following these steps, one can measure the angle of incidence and the angle of refraction using Tracker's protractor tool.

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The observation of a rainbow, shown here, often occurs on a rainy day during or immediately after an afternoon shower. The observer notices that this occurrence often happens on a late sunny afternoon after a rain shower. What explanation fits with the phenomenon seen here? Select ALL that apply.

Answers

Answer:

A) Light refracts through different media, causing rainbows.

B) Light from the sun is moving through air and moisture at the same time.

E) Light moving through water moves at different speeds, causing different wavelengths to appear at separate locations.

Explanation:

The answers are A, B, and E because I got them on USATestprep

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the instantaneous velocity of the particle when t=1.0 s?

Answers

Answer:

pls first attach the fig.

The graph in the figure shows the position of a particle as it travels along the x-axis. The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s. Therefore, option B is correct.

What do you mean by average speed ?

The term average speed is defined as the total distance traveled by the object in a particular time interval.

In the kinematics studies the movement of bodies, give the relationships between position, velocity and acceleration. In the special case that the acceleration is zero the motion is known as uniform motion.

       v = Δ x / Δt

Where v is the velocity, Δx is the position variation and Δt is the time variation in the analyzed interval.

Therefore,

v =  2.0 - ( - 2.0 ) / 4.0 - 1.0

v = 1.33 m / s          

Thus, The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s, option B is correct.

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Your question is incomplete, most probably your question was

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s?

Please help!! The graph in the figure shows the position - 1, Graph is attache below in image.

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the

An object, accelerating from rest at a constant rate, travels over 28 m in 11 s. What is its final velocity?

1.81 m/s

3.20 m/s

5.09 m/s

0.00 m/s

none of the above

Answers

Answer:

answer is 3

Explanation:

by using s= [(v+ u)/2] x t

28= (v+ 0)/2 x 11

v= 5.09 ms^-1

help me becase im stuck and dont know what to do

help me becase im stuck and dont know what to do

Answers

Transverse wave is the correct answer as it has crests and troughs.

If the internal energy of a system is decreased, which of the following is impossible?
a
Work done by the system is larger than heat
released.
b
Work done on the system is smaller than
heat released.
C
Work done by the system is larger than heat
absorbed.
d
Work done on the system is smaller than
heat absorbed.

Answers

Work done on the system is smaller than heat absorbed.

What happens when internal energy decreases?A cell's internal energy drops when it does work or expels heat. There won't be a net change in internal energy if the work performed by a cell matches the energy transferred in by heat or if the work performed on a cell matches the energy transported out by the heat.The energy within remains constant. The ideal gas law states that the temperature decreases according to the volume when a gas is compressed while maintaining a constant pressure. In this instance, more energy is lost as heat from the system is gained through work. Internal energy levels drop.Ideal gases' internal energy and enthalpy depend solely on temperature; neither volume nor pressure play a role. Using property relations, we may demonstrate these characteristics of ideal gases.

If the internal energy of a system is decreased, which of the following is impossible:

C) Work done on the system is smaller than heat absorbed.

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Find the angles of the first three principal maxima above the central fringe when this grating is illuminated with 672 nm light.

Answers

Complete Question

A grating has 767 lines per centimetre.Find the angles of the first three principal maxima above the central fringe when this grating is illuminated with 672 nm light.

Answer:

The  first is  

      \(\theta_1 = 2.92^o\)

 The second is  

       \(\theta _2 = 5.93^o\)

 The third is  

        \(\theta _3 = 8.92^o\)

Explanation:

From the question we are told that

        The  number of lines per cm is  \(I = 767 \ lines/cm = 76700 \ lines / m\)

        The  wavelength is  \(\lambda = 672nm = 672 *10^{-9} \ m\)

       

Generally the condition for constructive  interference is  

            \(dsin (\theta ) = n\lambda\)    

Here d is the distance of separation of the slit which is mathematically represented as

             \(d = \frac{1}{l}\)

             \(d = \frac{1}{76700}\)

             \(d = 1.30*10^{-5} \ m\)

So          

           \(\theta_1 = sin^{-1} [\frac{ n \lambda }{ d} ]\)

For the  first angle  n =  1  

  So  

        \(\theta_1 = sin^{-1} [\frac{ 1 * 672 *10^{-9} }{ 1.30 *10^{-5}} ]\)

          \(\theta_1 = 2.92^o\)

For  the second angle  n  =  2

      So  

            \(\theta_2 = sin^{-1} [\frac{ 2 * 672 *10^{-9} }{ 1.30 *10^{-5}} ]\)

            \(\theta _2 = 5.93^o\)

For  the second angle  n  =  3

      So  

           \(\theta_3 = sin^{-1} [\frac{ 3 * 672 *10^{-9} }{ 1.30 *10^{-5}} ]\)

          \(\theta _3 = 8.92^o\)

         

help on this asap please

help on this asap please

Answers

Answer:

I think A is correct.

Explanation:

If it's not I'm sorry probably my fault but I hope this helps:)

You have learned how to create an effective study space in this learning path.

What has been the biggest change you have made in your study space?
Give at least one specific example.
How has the information you have learned (and the possible changes you have made) already been a benefit to you?
Your answer should be at least two complete sentences.

Answers

Answer:

Getting comfy but not too comfy

Explaination :  Some people work the majority of their lives in sweat pants and a grungy t-shirt; others dress in full business attire before sitting down at the desk in their study. Because I want to enjoy the place where I study, I say be comfortable—but not too comfortable.  I change out of my pajamas before I crack open my books to give my mind another signal that this isn’t lounge time, but study time.

Hazel recently read an article that claimed that radio waves can cause electron displacement. Based on
the passage, is the article's claim true?
No, because radio waves
have energies that are too
low to fall in the ionizing
range
Yes, because radio waves
have energies that are
high enough to fall in the
ionizing range
Yes, because radio waves
have wavelengths that
are short enough to fall in
the ionizing range

Answers

Answer:

Based on  the passage, the article's claim is not true.  Therefore, the answer is:

No, because radio waves  have energies that are too  low to fall in the ionizing  range.

Explanation:

Radio waves are generally known as forms of non-ionizing radiation.  This means that they do not have enough energy, unlike microwaves, to separate electrons from atoms or molecules, thereby ionizing them.  They cannot cause electron displacement, as claimed in the article.  Therefore, they cannot break chemical bonds, which can cause chemical reactions or DNA damage. As non-ionizing radiation, radio waves occur at lower frequencies in the electromagnetic spectrum.

For a certain transverse standing wave on a long string, an antinode is at x = 0 and an adjacent node is at x = 0.20 m. The displacement y(t) of the string particle at x = 0 is shown in the figure, where the scale of the y axis is set by ys = 4.3 cm. When t = 0.90 s, what is the displacement of the string particle at (a) x = 0.30 m and (b) x = 0.40 m ? What is the transverse velocity of the string particle at x = 0.30 m at (c) t = 0.90 s and (d) t = 1.3 s?

For a certain transverse standing wave on a long string, an antinode is at x = 0 and an adjacent node

Answers

The expressions for the traveling and standing wave to find the results for the questions about the displacement and speed of the particle are:

       a) For time zero, the displacement at position x = 0.30 m is y = 3.04 cm

     b) For time zero, the displacement at position x = 0.40 m is: y = 0

      c) For the point x = 0.30 and time t = 0.9s, the velocity of the particle is:

          v = 9.11 cm / s

      d) For the point x = 0.30 and time t = 1.3s, the velocity of the particle is:

          v = 9.65 cm / s

The traveling wave is a disturbance in the medium that moves at constant speed, in the case of a transverse wave the expression for the perpendicular oscillation is:

         y = A sin (kx - wt)

Where y is the oscillation perpendicular to the direction of the displacement, A the amplitude, k in wave number and w the angular velocity.

Standing waves are formed when a traveling wave collides with an obstacle and is reflected, in this case the sum of the two waves gives a wave that does not shift in time and fulfills the relationship

           \(\frac{\lambda}{2} = \frac{L}{n}\)  

Where λ is the wavelength, L the distance between the reflection points and n the number of nodes.

Indicates that for the standing wave the distance between an antinode and the node is x = 0.20 m, therefore

               \(\frac{\lambda}{4} = \frac{L}{1}\)  

              λ = 4L

              λ = 4 0.20

              λ = 0.80 m

The wave number.

              k = \(\frac{2\pi }{\lambda }\)  

              k = \(\frac{2 \pi }{0.80 }\)  

              k = 2.5π i m⁻¹

In the associated traveling wave, from the graph we can see that the period of the wave is:

             T = 2.8 s

the angular velocity is related to the period.

             \(w=\frac{2\pi}{T} \\w = \frac{2\pi }{2.8}\)  

             w = 0.714π  rad/s

indicate the maximum displacement that is the amplitude of the wave.

              A = \(y_s\)  

             A = 4.3 cm

Let's write the equation of the traveling wave.

              y = 4.3 sin [π (2.5 x - 0.714 t)]

with this expression we can answer the questions.

a) the displacement of the particle for x = 0.30 m

            y = 4.3 sin (π (2.5 0.30 - 0.714 t))

            y = 4.3 sin π( 0.75 - 0.714 t(

Remember that the angles must be in radians.  For time t = 0 the displacement is

              y = 4.3  0.707

              y = 3.04 cm

 

b) The displacement for x = 0.4m

              y = 4.3 sin (π 2.5 0.4)

              y = 0 cm

c) the transverse velocity of the wave at x = 0.30 m for the time of t = 0.90s

the speed of the wave is

              \(v= \frac{dy}{dt} \\v= A w cos ( kx - wt)\)  

              v = 4.3 0.714π cos π(2.5 0.3 - 0.714 t)

              v = 9.65 cos π(0.75 - 0.714 t)

For time t = 0.90 s the velocity is:

            v = 9.65 cos π(0.75 - 0.714 0.9)

            v = 9.65 0.9436

            v = 9.11 cm / s

d) The velocity for time t = 1.3 s

           v = 9.65 cos π(0.75 - 0.714 1.3)

           v = 9.65 0.9999

           v = 9.65 cm / s

In conclusion, using the expressions for the traveling and standing wave, we can find the results for the questions about the displacement and speed of the particle are:

      a) For time zero, the displacement at position x = 0.30 m is y = 3.04 cm

     b) For time zero, the displacement at position x = 0.40 m is: y = 0

      c) For the point x = 0.30 and time t = 0.9s, the velocity of the particle is:

          v = 9.11 cm / s

      d) For the point x = 0.30 and time t = 1.3s, the velocity of the particle is:

          v = 9.65 cm / s

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10. In a laboratory experiment, students recorded the
following length data: 12.2 cm, 12.1 cm, 12 cm,
11.9 cm, and 12.20 cm. (a) Determine the average
length and express the answer using the correct
number of significant figures. (b) Based on your
average length calculation in part (a), discuss the
importance of recording measurements to the
appropriate number of significant figures.

Answers

a) 12.1 Average.

B) It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.

What does the average?A data set's mean (average) is calculated by summing all of the numbers in the set, then dividing by the total number of values in the set. When a data collection is ranked from least to greatest, the median is the midpoint.The mean, median, and mode are the three primary varieties of average. Each of these methods operates slightly differently and frequently yields values typically a little off. The average that is most frequently used is the mean. You add all the values and divide this sum by the total number of values to obtain the mean value.Averages are mostly used to track changes over time within a sample group or cohort.Since averages can be used to compare different quantities of the same category, we employ them. The calculation of averages has limits since it cannot reveal how something is distributed among individuals. For instance, the distribution of income is not shown by per capita income.

A) Determine the average length and express the answer using the correct number of significant figures:

12.2+12.1+12=36.3/3 = 12.1 Average.

B)  Based on your average length calculation in part a, discuss the importance of recording measurements to the appropriate number of significant figures:

It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.

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What is it called when scientists in the same or similar field of study judge the quality of a fellow scientist’s scientific claim?

academic claim
academic review
peer claim
peer review

Answers

Answer:

When scientists in the same or similar field of study judges the quality of a fellow scientist’s scientific claim, it is known as peer review.

When scientists in the same or similar field of study judge the quality of a fellow scientist’s scientific claim it is called Peer review.

what is the scientific claim?

Scientific claims are statements made in science based on an experiment.

These Scientific claims are backed by the experimental data and their true results obtained from scientific investigation and experimentation.

Peer review is done when scientists in the same or similar field of study judge the quality of a fellow scientist’s scientific claims.

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A loop of wire with radius r= 0.055m is placed in a region of uniform magnetic field with magnitude B. As shown in the figure, the field direction is perpendicular to the plane of the loop. The magnitude of the magnetic field changes at a constant rate from B1=0.65T to B2=4.5T in time Δt=3.5s. The resistance of the wire is R=12Ω. Calculate, in Tesla squared meters, the magnitude of the change in the magnetic flux.

(ΔΦ= _____T⋅m2)

Answers

In Tesla squared meters, the magnitude of the change in the magnetic flux. (ΔΦ= 2.3468T⋅m²).

The magnetic flux through the loop is given by;

Φ = B A cosθ

where B is magnetic field strength, A is area of the loop, and θ is angle between the normal to the loop and the direction of the magnetic field. Since the magnetic field is perpendicular to the plane of the loop, θ = 0 and cosθ = 1.

The magnitude of the change in the magnetic flux is given by;

ΔΦ = Φ₂ - Φ₁

where Φ₁ is the initial magnetic flux through the loop when the magnetic field strength is B₁ = 0.65 T, and Φ₂ is the final magnetic flux through the loop when the magnetic field strength is B₂ = 4.5 T.

The initial magnetic flux through the loop is;

Φ₁ = B₁ A cosθ = 0.65 × πr² × 1 = 0.1126 T⋅m²

The final magnetic flux through the loop is;

Φ₂ = B₂ A cosθ = 4.5 × πr² × 1 = 2.4594 T⋅m²

Therefore, the magnitude of the change in the magnetic flux is;

ΔΦ = Φ₂ - Φ₁ = 2.4594 - 0.1126 = 2.3468 T⋅m²

Therefore, ΔΦ = 2.3468 T⋅m².

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A cart of mass M is on a level, horizontal track. The cart is attached to one end of an ideal spring, and the other end of the spring is attached to a vertical support. The spring has a spring constant k. The cart is pulled to the right, stretching the spring a distance d, as shown above, and released from rest at time t = 0. The cart-spring system begins to oscillate, and the position x of the cart as a function of time t is given by the equation x(t) = d cos(ωt) , where x is in meters, ω is in rad/s , and t is in seconds. Assume the mass of the cart’s wheels to be negligible.

(a) Derive an equation for the velocity of the cart v as a function of time t .

(b) On the axes below, sketch a graph of the velocity v of the cart as a function of time t for two complete oscillations. On the graph, T represents the time for one complete oscillation. Explicitly label asymptotes, maxima, or minima with algebraic expressions, as appropriate.
(c) Express all answers in part (c) in terms of ω, t, M, d, k, and physical constants, as appropriate.

i. Determine an expression for the kinetic energy K of the system as a function of time t.

ii. Determine an expression for the potential energy U of the system as a function of time t.

iii. Using the equations from parts (c)i and (c)ii, show that the rate of change of the total energy of the system dE/dt is zero.
Two springs identical to the spring above are attached to each side of the cart of unknown mass M, as shown in Figure 1 above. The cart is on a level, horizontal track of negligible friction. A piece of clay is added to the top of the cart so that it will stick to the cart. The cart is displaced to the left a distance d and released from rest, as shown in Figure 2 above. The period of oscillation is recorded. This procedure is repeated for several different pieces of clay of different masses. In each trial, the cart is displaced the same distance d. The data are shown below on the linear graph of T2 as a function of mC , where T is the period of oscillation and mC represents the mass of the clay.
(d) From the graph, determine the following.

k, the spring constant of each spring

M, the mass of the cart

(e) The experiment is repeated, but in a second set of trials, the cart is pulled back a distance D, where D > d . Describe any changes that will occur for the straight line on the graph in part (d).

Justify your answer.

Answers

An equation for the velocity of the cart v as a function of time t is v(t) = -dw sinwt

What is velocity?

Velocity, a physical entity quantifying the rate at which an object alters it's location over a precise duration, stands as a vector quantity with both magnitude and direction.

Conventionally expressed in meters per second (m/s) or equivalent units of stretch distance versus duration, average velocity is worked out by partitioning an object's displacement over the time taken to complete said displacement. The formula for the same is quite simple:

Average Velocity = Displacement / Duration

Wherein, Displacement reflects the alteration in position of an object, and span denotes the interval consumed during that change.

Check the attachment.

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A cart of mass M is on a level, horizontal track. The cart is attached to one end of an ideal spring,
A cart of mass M is on a level, horizontal track. The cart is attached to one end of an ideal spring,
A cart of mass M is on a level, horizontal track. The cart is attached to one end of an ideal spring,

Maslow's hierarchy of needs assumes

Answers

Answer:

That people are motivated by a series of five universal needs.

Explanation:

Why must humans limit their exposure to X-rays and gamma rays?
A. The rays can change molecules and atoms in the body into ions.
B. Exposure can cause the human body to give off heat.
O C. Even a small amount of radiation can burn the skin.
D. These rays act similarly to microwaves on the human body.

Answers

Answer:

A. The rays can change molecules and atoms in the body into ions.

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