solving ground speed trig problems law of sines law of cosines

Answers

Answer 1

Solving ground speed trig problems using the law of sines and law of cosines involves applying these trigonometric principles to find the unknown angles or sides in a given triangle.



The law of sines states that the ratio of a side of a triangle to the sine of its opposite angle is the same for all three sides.

It is represented as (a/sin(A)) = (b/sin(B)) = (c/sin(C)). The law of cosines states that for any triangle with sides a, b, and c, and angles A, B, and C, the equation a^2 = b^2 + c^2 - 2bc*cos(A) holds true.

Both of these laws are commonly used to solve ground speed problems in aviation and other fields.



Summary: To solve ground speed trig problems, you can use the law of sines and law of cosines to find unknown angles or sides in a triangle, which can help you determine ground speed, wind speed, and other relevant information.

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Related Questions

A ball is left in the bed of a truck will do what when a truck takes off in motion. What happens when the truck stops and why?​

Answers

The call has inertia which means it will try to stay where it was when the truck started moving. This will make it look as if it is going towards the back of the truck.
When the truck stops the ball will try to keep moving and end up moving towards the front of the truck.

which scan examines the current security, in a passive method?

Answers

The scan that examines the current security in a passive method is called a Vulnerability Assessment (VA) scan.

A Vulnerability Assessment scan is a process of identifying and assessing vulnerabilities within a system, network, or application. It is typically performed using automated tools that scan the target environment for known vulnerabilities, configuration weaknesses, and security holes. Unlike active scanning techniques that actively probe the system and may generate network traffic, a VA scan operates in a passive manner, observing the system without actively interacting with it.

During a Vulnerability Assessment scan, the automated tool examines the target environment by analyzing network traffic, configurations, system logs, and other sources of information to identify potential vulnerabilities. It compares the collected data against a database of known vulnerabilities and security weaknesses to determine if any matches exist.

The passive nature of a VA scan makes it non-intrusive, as it does not generate additional traffic or perform active actions that could potentially impact the system's performance or stability. It allows organizations to assess their current security posture, identify vulnerabilities, and prioritize remediation efforts without disrupting the normal operation of the environment.

The results of a Vulnerability Assessment scan provide insights into the security weaknesses present in the system, enabling organizations to take appropriate measures to address and mitigate those vulnerabilities. This may include applying security patches, reconfiguring systems, updating software versions, or implementing additional security controls to protect against potential threats.

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John has a utility function of the following: UL, C) = L ^BC ^(1-ẞ), where L is leisure and C is consumption. If he works, he receives a real wage w. Outside of the labor market, he has nonlabor market income V. And his endowment of time T is normalized to 1. And the price of goods p is also normalized to 1.
(a) Please write down his budget constraint.
(b) Assuming ẞ = 1/2, V = 100, w = 200, what is his optimal supply of labor?
(c) How much total income does he have?
(d) How much consumption will he make?
(e) Now, consider the case where John is subject to a 10% income tax on labor income only. What is his new optimal supply of labor?

Answers

(a) The budget constraint can be written as: C = wL + V, where C is consumption, w is the real wage, L is leisure, and V is non-labor market income.

(b) With ẞ = 1/2, V = 100, and w = 200, John's optimal supply of labor cannot be determined without information about his preferences for leisure and consumption. The utility function only represents his preferences, but we need additional information to determine the specific amount of labor he would choose to supply.

(c) John's total income is the sum of his labor income and non-labor market income: Total income = Labor income + Non-labor income = wL + V. Without knowing the specific value of L, we cannot calculate the total income.

(d) Similarly, without knowing John's preferences for leisure and consumption, we cannot determine the specific level of consumption he would choose.

(e) In the case where John is subject to a 10% income tax on labor income only, his new optimal supply of labor would depend on the tax rate's impact on his preferences and the trade-off between leisure and consumption. Without further information on his preferences and the specific tax structure, we cannot determine the new optimal supply of labor.

Additional information about John's preferences for leisure and consumption, as well as the specific tax structure, is necessary to calculate his optimal labor supply, total income, consumption, and the impact of the income tax on his labor supply.

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A Balloon is filled with water inside, when it is hanged over a burning fire the balloon filled with water doesn't brust why??​

Answers

Answer:

The water filled balloon does not burst because the rubber obviously does not reach a temperature sufficient for it to melt or burn. The rubber is stretched thin so that heat is quickly transferred into the balloon. With air inside the balloon, this heat is not readily dissipated away from the spot touching the flame.

does the centripetal force acting on an object do work on the object?

Answers

No, centripetal force acting on an object does not do work on the object.

Centripetal force is not a fundamental force; rather, it is the name given to any force that causes a body to travel in a circle or curved path. It works at right angles to the direction of motion and points toward the center of the curve. For example, the force of gravity that pulls the moon towards the Earth is a centripetal force that keeps it in orbit. Centripetal force does not do any work because the force and displacement vectors are perpendicular. As a result, the dot product is zero, indicating that no work is being done. When a body travels in a circle, the speed and direction of the body are constantly changing, but the total work done on the body is zero. The work done by the force of gravity and the normal force in a circular path is equal to zero.

Centripetal force does not do any work because the force and displacement vectors are perpendicular. When a body travels in a circle, the speed and direction of the body are constantly changing, but the total work done on the body is zero.

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A car travels East at a distance of 540 km in 6.1 hours. What is the cars velocity?

Answers

Answer: 55.0066 miles per hour

Explanation: i hope this helped, and pls mark me as brainliest

Which of the following is the clearest example of a neuronal membrane’s selective permeability?
a. The Na+-K+ pump only transports Na+ and K+ ions.
b. K+ ions can diffuse across the membrane more easily than Na+ ions.
c. Diffusion of K+ ions out of the neuron causes the membrane potential to become more negative.
d. The concentration gradient for Na+ ions is inward, but the concentration gradient for K+ ions is outward.

Answers

The clearest example of a neuronal membrane's selective permeability is an option (b) - K+ ions can diffuse across the membrane more easily than Na+ ions. This is because the membrane is more permeable to K+ ions than to Na+ ions.

This is due to the presence of potassium ion channels, which allow K+ ions to easily cross the membrane. On the other hand, the presence of sodium ion channels is limited, which makes it more difficult for Na+ ions to cross the membrane.

The selective permeability of the neuronal membrane is crucial for maintaining the proper functioning of the nervous system. It allows for the regulation of ion concentrations inside and outside the cell, which is essential for generating and transmitting electrical signals. This selective permeability is achieved through the presence of ion channels and transporters that selectively allow certain ions to pass through the membrane.

In summary, the clearest example of a neuronal membrane's selective permeability is the fact that K+ ions can diffuse across the membrane more easily than Na+ ions, due to the presence of potassium ion channels and the limited presence of sodium ion channels. Hence, b is the correct option.

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Wave A carries more energy than wave B. Wave B must have a smaller than wave A. A. frequency B. amplitude C. wavelength D. speed​

Answers

Answer:

Amplitude

Explanation:

The amount of energy a wave carries is determined by the amplitude. The larger the amplitude, the more energy the wave has, and the smaller the amplitude, the less energy the wave has.

In this case, since wave A has more energy than wave B, wave B must have a smaller amplitude than wave A.

Let me know if this helps!

a cherry pie in a 8.50 in diameter plate is placed upon a rotating tray. then, the tray is rotated such that the rim of the pie plate moves through a distance of 308 in. express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.

Answers

The angular distance should be

In revolution, θ = 11.53 revolution.

In radian = θ = 72.40 rad.

In degree θ = 4150.8°.

Calculation of the angular distance:

Since

Pie diameter = 8.50 in

So,  the circumference of the pie should be

P = πd = 8.50π in

And, rim of the pie rotates 308 in,

So,

1 Revolution of the pie is 8.50π in,

So, for 308 it should be

= 308 in / 8.50π in revolution

=11.53 revolution

Now in the case when when we have to find distance in radians:

1 revolution is 2πrad

So,

11.53 revolution = 11.53 × 2π = 72.40 rad.

And also, 1 revolution is 360°

So,

11.53 revolution = 11.53 × 360 = 4150.8°

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Dropping a rock from 4 feet in the air is an example of what type of energy?

Answers

Answer:

The type of energy is potential energy

It is called mechanical energy but to be more specific potential energy

the vertical distance between atc and avc reflects:

Answers

c) average fixed cost.This implies that in the case of ATC and AVC first both the cost decreases reaches the lowest point and then increases. AFC (average fixed cost) curve is always decreasing, because the average cost remains constant.

Why does the vertical gap shrink as output rises between ATC and AVC?

As output rises, the separation between the AC and AVC curves tends to decrease. This is due to the fact that as output rises, the AC's AVC component tends to grow while its AFC component tends to shrink.

What does the vertical distance between ATC and AVC curve represent?

AFC = ATC - AVC where AFC = Average fixed cost, ATC = Average total cost and AVC = Average variable cost. Therefore, the vertical distance between ATC and AVC is the AFC.

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Given that the mass of the earth is 5.97 X 10 24 kg and its radius length is 6.34 X 10'
6 m Then find the tension of gravitational field of earth to a body of mass 1000 kg putting on the ground surface

Answers

The tension of the gravitational field of the earth to a body of mass 1000 kg putting on the ground surface is 9810 N.

The tension of the gravitational field of the earth to a body of mass 1000 kg putting on the ground surface is given by the formula:

Weight (W) = mg

where g is the acceleration due to gravity at the surface of the earth and m is the mass of the body.

We can find g using the formula:

Tension of gravitational field of earth (g) = GM/r²

where G is the gravitational constant (6.67 x 10⁻¹¹ Nm²/kg²), M is the mass of the earth (5.97 x 10²⁴ kg), and r is the radius length of the earth (6.34 x 10⁶ m).

So, substituting the given values, we have:

g = (6.67 x 10⁻¹¹Nm²/kg² × 5.97 x 10²⁴ kg)/(6.34 x 10⁶ m)²g = 9.81 m/s² (approximately)

Therefore, the weight of the body of mass 1000 kg putting on the ground surface would be:

W = mg

W = 1000 kg × 9.81 m/s²

W = 9810 N

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Please help anyone ASAP You can listen to your friend round a corner, but you cannot watch him/her .Why? Related to sound

Answers

Answer:

The sound waves have larger wavelength than light waves. These are diffracted by the corner of wall and light waves cannot do so, due to their very small wavelength (as compared with size of wall corner). So, without seeing the friends his/her voice can be heard.

The sound wave has a longer wavelength as compared to light waves and due to diffraction the sound wave reaches your friend around a corner, but the light wave can't.

What is sound?

Sound is a mechanical disturbance that travels through an elastic medium and disrupts an equilibrium condition. It is also feasible to define sound solely subjectively, as that which is perceived by the ear.

Although this definition lacks clarity and is overly pedantic because it is necessary to discuss noises that cannot be heard by the human ear, such as those made by dog whistles or sonar devices.

Compared to light waves, sound waves have a longer wavelength. Since light waves have a very short wavelength, they cannot be diffracted by a corner of a wall (as compared with the size of wall corner). He or she can therefore be heard even when the friends are not seen.

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What is transparency in Scrum environment?

Answers

The transparency in scrum environment is the emergent process and work must be visible to those performing the work as well as those receiving the work.

The definition of transparency.

When a team uses this phrase, it means that every step of the process is visible to everyone. Due to its role in ensuring that everyone is kept on track, transparency is crucial in the workplace.

Transparency is operating in a way that makes it simple for others to see what is done, and it is a core value that cuts across science, engineering, business, and the humanities. Openness, dialogue, and accountability are all implied by transparency.

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Can someone please help me with this?? It's due in an hour and I've been stuck on it!
I've gotten the first three of all of them done, but I am stuck on the last two. You can probably look them up.

[Part One]

Mercury:
1. What shape is the orbit of Mercury?
2. Why do you think the Sun is not at the center of Mercury’s orbit?
3. What did you notice about the motion of Mercury in its orbit?
Click on each highlighted section and record the area. What do you notice about each area?
4. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).

Earth:
1. What is the orbit of the Earth?
2. Is the Sun at the center of the Earth’s orbit?
3. Describe the motion of the Earth throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).

Mars:
1. What is the orbit of the Mars?
2. Is the Sun at the center of the Mars’s orbit?
3. Describe the motion of Mars throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).

[Part Two]

Saturn:
1. What is the orbit of the Saturn?
2. Is the Sun at the center of the Saturn’s orbit?
3. Describe the motion of Saturn throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).

Neptune
1. What is the orbit of the Neptune?
2. Is the Sun at the center of the Nepturn’s orbit?
3. Describe the motion of Neptune throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).

Comet
1. What is the orbit of the comet?
2. Is the Sun at the center of the comet’s orbit?
3. Describe the motion of the comet throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).

Answers

Answer:

Earth:

1. What is the orbit of the Earth?

365 days

2. Is the Sun at the center of the Earth’s orbit?

Yes

3. Describe the motion of the Earth throughout its orbit? Does it move at constant speed?

Yes, the Earth moves pretty quickly and orbits around the Sun at a rate of approximately 67,000 miles per hour.

Mars:

1. What is the orbit of Mars?

The shape is circular, 687 days

2. Is the Sun at the center of Mars’s orbit?

Yes

3. Describe the motion of Mars throughout its orbit? Does it move at constant speed?

Travels at a regular steady speed, yes moves at a constant speed

Saturn:

1. What is the orbit of Saturn?

Circular, 29 years

2. Is the Sun at the center of Saturn’s orbit?

Yes

3. Describe the motion of Saturn throughout its orbit? Does it move at constant speed?

Just like Mars, it moves faster when it is closer to the sun, so yes.

Neptune:

1. What is the orbit of Neptune?

Circular, 165 years

2. Is the Sun at the center of Nepturn’s orbit?

Yes

3. Describe the motion of Neptune throughout its orbit? Does it move at constant speed?

A steady consistent speed and yes it moves at a constant speed.

Comet:

1. What is the orbit of the comet?

An oval, 200 years

2. Is the Sun at the center of the comet’s orbit?

No

3. Describe the motion of the comet throughout its orbit? Does it move at constant speed?

A comet starts off slow then picks up speed and no it does not move at a constant speed.

Explanation:

I hope this helps, You're welcome.

An atom has 15 neutrons, 19 electrons, and 20 protons. What is the charge of this atom?

Answers

Because the number of electrons and protons in a neutral atom is the same, this atom's charge is zero.

The number of electrons in a neutral atom is the same as the number of protons. In the case of this atom, there are 19 electrons and 20 protons, resulting in a charge of +1. This atom is a cation since it has more protons than electrons.The atomic number of an element is determined by the number of protons in its nucleus, and it is represented by the symbol Z. The total number of protons and neutrons in an atom's nucleus is called its mass number, and it is represented by the symbol A. The number of neutrons in an atom can be determined by subtracting the atomic number (Z) from the mass number (A).In this particular atom, there are 20 protons and 15 neutrons. The mass number is 20 + 15 = 35. The atomic number, on the other hand, is 20. As a result, this element is a neutral atom with 20 electrons.

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when drawing a scatter diagram, along which axis is the explanatory variable placed? along which axis is the response variable placed?

Answers

The explanatory variable is placed on the x-axis and the response variable is placed on the y-axis.

A scientist is designing a device that will mimic Earth's atmosphere by
blocking high-energy waves from the Sun. Pick three high-energy waves
that the device should be able to block?

Answers

Answer:

1. Ultraviolet light (UV)

2. X-rays

3. Gamma-rays

Explanation:

Though there are different types of energy or electromagnetic waves with varying wavelengths, including the likes of Gamma X-rays, ultraviolet light, visible light, infrared radiation, and microwave radiation.

What is more certain is that the atmosphere blocked the high-energy waves from getting to the earth surface or biosphere such as Ultraviolet light (UV), X-rays and Gamma-rays

The amount of voltage induced into a conductor moving in a magnetic field depends on the ______.

Answers

A measure of how quickly a conductor moves across a field. The voltage induced increased as the conductor moved through the field more quickly. The induced voltage and speed are directly inversely proportional.

When a conductor is moved in a magnetic field, a voltage will be induced on the conductor.?

Current can only flow when a circuit is closed or complete, hence, unless the circuit is completed current will not flow

What is Electro-Magnetic Induction?

This a phenomenon whereby a wound wire or a soft core of conductor made to cut across magnetic line of force and an E.M.F is generated, this E.M.F forces current to flow if the circuit is completed.

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What force acts on all objects, all the time on Earth?
State this force, and write the notation used for this force.
What force does a surface exert on an object perpendicularly?
State this force, and write the notation used for this force.

Answers

The force that acts on all objects, all the time on Earth is gravitational force.

The force that surface exert on an object perpendicularly is normal reaction.

What force acts on all objects, all the time on Earth?Force due to gravity is gravitational pull on objects due to its position on earth's surface.

The force due to gravity on object's is calculated by applying Newton's second law of motion as follows;

F = mg

where;

m is the mass of the objectg is acceleration due to gravity

The force that surface exert on an object perpendicularly is normal reaction.

Thus, the force that acts on all objects, all the time on Earth is gravitational force.

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A book is thrown upward from height 10.m and lands with a velocity of -17.50m/s. What was its initial velocity

Answers

Answer:

Below

Explanation:

Find the velocity if it was just DROPPED from 10m

d = 1/2 at^2

10 = 1/2 * 9.81 * t^2   shows t = 1.42784 s    to hit ground from 10 m

    velocity if just dropped   v = at = 9.81 * 1.4278414 m/s  

when the book is tossed up...and it returns to the launch point it will have the same magnitude of velocity

  so it was launched up at the difference between what it was if just dropped and the final v of 17.5

  17.5 - 14 = 3.5 m/s  initial v

d) A 2-kg book is held 1 m above the floor is for 10s. The work done on the book is zero and its potential energy is 20 J. Is it true or false?​

Answers

Ep=mgh
Ep=2x9.8x1 = 19.6J

the two nearest harmonics of a tube closed at one end and opened at the other end are 240Hz and 280Hz.What is the fundamental frequency of the system​

Answers

f(1) = v/2L, so fundamental frequency of the system = 343 m/s/2(7/3)L = 343 m/s*(7/6)L.

The fundamental frequency can be computed as 204.25 Hz.

343 m/s is the speed of sound BTW.

how does cells and tissues work together with the brain to do its job

Answers

Cells are grouped together to carry out specific functions. A group of cells that work together form a tissue. Your body has four main types of tissues, as do the bodies of other animals. These tissues make up all structures and contents of your body.

The Hubble Space Telescope (HST) orbits Earth at an altitude of 613 km. It has an objective mirror that is 2.40 m in diameter. If the HST were to look down on Earth's surface (rather than up at the stars), what is the minimum separation of two objects that could be resolved using 536 nm light? [: The HST is used only for astronomical work, but a (classified) number of similar telescopes are in orbit for spy purposes

Answers

the minimum separation of two objects that the HST could resolve when looking down at Earth's surface using 536 nm light would be approximately 167 mm.

To calculate the minimum separation of two objects that the Hubble Space Telescope (HST) can resolve when looking down at Earth's surface, we can use the formula for angular resolution:
θ = 1.22 * (λ/D)
Where:
- θ is the angular resolution in radians
- λ is the wavelength of light used, in this case, 536 nm (5.36 x 10^-7 m)
- D is the diameter of the objective mirror, which is 2.40 m for the HST
Step 1: Calculate the angular resolution:
θ = 1.22 * (5.36 x 10^-7 m / 2.40 m) ≈ 2.73 x 10^-7 radians
Step 2: Convert angular resolution to the linear resolution at the HST's altitude:
The minimum separation (s) can be calculated using the formula:
s = θ * h
Where:
- h is the altitude of the HST, which is 613,000 m
s = 2.73 x 10^-7 radians * 613,000 m ≈ 0.167 m or 167 mm
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PLEASE HELP!!! a skateboard rolls down a ramp, starting from rest. after 3seconds, the skateboard’s velocity is 15m/s. what is the acceleration of the skateboarder?

Answers

V = Vi + at
15 = 0 + a (3)
15/3 = a
acceleration = 5 m/s^2

An ocean wave has a frequency of 3 waves per second, and the waves are
5 meters apart. What is the speed of the wave?

Answers

Answer:

v = λf = (4 m)(3 Hz) = 12 m/s

Explanation:

An airport screens bags for forbidden items, and an alarm is supposed to be triggered when a forbidden item is detected. Suppose 5% of bags contain forbidden items. If a bag contains a forbidden item, there is a 98% chance that it triggers the alarm. If it doesn't contain a forbidden item, there is an 8 % chance that it triggers the alarm. Given a randomly chosen bag triggers the alarm, what is the probability that it contains a forbidden item

Answers

A randomly chosen bag triggers the alarm, the probability that it contains a forbidden item can be calculated using Bayes' theorem. The probability is approximately 80.56%.

What is the probability that a bag contains a forbidden item if it triggers the alarm?

To determine the probability that a bag contains a forbidden item given that it triggers the alarm, we can use Bayes' theorem. Let's denote event A as "bag contains a forbidden item" and event B as "bag triggers the alarm." We are given that the probability of event A is 5% (0.05) and the probability of event B given A is 98% (0.98). Additionally, the probability of event B given not A (i.e., the alarm being triggered by a bag without a forbidden item) is 8% (0.08). Using these probabilities, we can apply Bayes' theorem:

\(P(A|B) = (P(B|A) * P(A)) / (P(B|A) * P(A) + P(B|not A) * P(not A))\)

Substituting the given values, we get:

\(P(A|B) = (0.98 * 0.05) / (0.98 * 0.05 + 0.08 * 0.95) = 0.8056\)

Therefore, the probability that a bag contains a forbidden item, given that it triggers the alarm, is approximately 80.56%.

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Una pelota de golf se suelta desde el reposo del techo de un edificio muy alto. Despreciando la resistencia del aire, calcule (a) la posicion y (b) la velocidad de la pelota despues de 1s, 2s y 3s.

Answers

Answer:

a)   y = y₀ - 4.9, v = -9.8 m / s, b)  y =y₀ - 19.6,  v = - 19 m / s

c)  y =y₀ - 44.1, v = - 29.4 m / s

Explanation:

To solve this exercise let us use the kinematic relations

          y =y₀ + v₀ t - ½ g t²

          v = v₀ - g t

They indicate that the body is released therefore the initial velocity is zero v₀ = 0

          y = y₀ - ½ g t²

          v = - gt

a) the position and velocity for t = 1s

         y = y₀ - ½ 9.8 12

         y = y₀ - 4.9

         v = - 9.8 1

         v = -9.8 m / s

the negative sign indicates that the velocity is directed downwards

b) t = 2 s

         y =y₀ - ½ 9.8 2 2

         y =y₀ - 19.6

         v = - 9.8 2

         v = - 19 m / s

c) t = 3 s

        y = y₀ - ½ 9.8 3 2

        y =y₀ - 44.1

        v = - 9.8 3

        v = - 29.4 m / s

Para el siguiente conjunto de medidas, calcule EL ERROR RELATIVO PORCENTUAL: 1.34 m, 1.35 m, 1.37 m y 1.36 m

Answers

Answer:

Ver explicacion abajo

Explanation:

En este caso para poder calcular el error relativo porcentual, es necesario calcular primero el error absoluto, que se calcula de la siguiente forma:

Error absoluto = Resultado exacto - aproximación

Sin embargo, no tenemos el resultado exacto de las medidas, pero podriamos conocerlo tomando el promedio de estas medidas y este es el que tomaremos como el verdadero resultado de las medidas:

Promedio de medidas = 1.34 + 1.35 + 1.37 + 1.36 / 4

Promedio de medidas = 1.355 m

Ya que tenemos el promedio, podemos calcular el error absoluto de cada medida y luego el error relativo porcentual:

Ea1 = 1.355 - 1.34 = 0.015

Ea2 = 1.355 - 1.35 = 0.005

Ea3 = 1.37 - 1.355 = 0.015

Ea4 = 1.36 - 1.355 = 0.005

Ya que tenemos los 4 errores absolutos, es posible calcular el porcentual:

%error relativo = (Error absoluto / resultado exacto) * 100

Aplicando la expresión con cada uno de los valores tenemos:

%Er1 = (0.015/1.34) * 100 = 1.12%

%Er2 = (0.005/1.35) * 100 = 0.37%

%Er3 = (0.015/1.37) * 100 = 1.09%

%Er4 = (0.005/1.36) * 100 = 0.37%

Espero que te sirva.

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