The ratio of the final kinetic energy to the initial kinetic energy of an object is one half. If the initial velocity of the object is 10m/s, what is the final velocity?Select one:О A. 2.7 m/sO B 1.5 m/sO C. 7.1 m/sO D. 10 m/sO E. 20 m/s

Answer:

Static equilibrium.

Explanation:

Before the ball hits the ground, it is 2.8 seconds in the air. The result is obtained by using the equations in uniformly accelerated straight motion.

The equations apply in uniformly accelerated straight motion in vertical dimension are

v₁ = v₀ + gt

v₁² = v₀² + 2gh

h = v₀t + ½ gt²

Where

A student standing on the ground throws a ball straight up with

Find the time it takes for the ball to reach the ground!

We use g = 9.8 m/s². See the illustration picture in the attachment!

The ball will go upward and stop at a certain height with v₁ = 0. The time needed is

v₁ = v₀ - gt₁

0 = 13.0 - 9.8t

13.0 = 9.8t

t₁ = 13.0/9.8

t₁ = 1.3 s

The height above the hand when the ball stops is

v₁² = v₀² - 2gh₂

0 = 13.0² - 2(9.8)h₂

13.0² = 2(9.8)h₂

169 = 19.6h₂

h₂ = 8,62 m

The ball stops at a height of

h₃ = h₁ + h₂

h₃ = 2.50 + 8.62

h₃ = 11.12 m

The ball goes downward and reach the ground. Initial velocity in this condition is v₁ = 0. The time needed is

h₃ = v₁t + ½ gt₂²

11.12 = 0 + ½ (9.8)t₂²

11.12 = 4.9t²

t₂² = 2.27

t₂ ≈ 1.5 s

The time that the ball in the air is

t = t₁ + t₂

t = 1.3 + 1.5

t = 2.8 s

Hence, the ball is in the air for 2.8 seconds.

Your question is incomplete, but most probably your full question was

A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground. How long is the ball in the air before it hits the ground? (The student moves her hand out of the way).

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Answer:

The moon does not have an atmosphere because it does not have enough gravity to hold onto the gases that make up an atmosphere. The moon also does not have plate tectonic activity because it does not have enough internal heat to drive the movement of the plates.

Explanation:

Answer:

B. 2.3 x 10⁶

Explanation:

To calculate scientific notation for the number 2,300,000, we have to follow this notation

Step 1 :

To find a we have to write the non-zero digits placing a decimal after the first non-zero digit.

Step 2 :

Now, to find b count how many numbers of digits are there to the right of the decimal.

Hence, there are 6 digits to the right of the decimal.

Step 3 :

Since, we had found the value of a and b, we can now reconstruct the number into scientific notation.

a = 2.3

b = 6

Therefore, option b is correct.

Answer:

1.37 ×10^-3 T

Explanation:

From;

B= μnI

μ = 4π x 10-7 N/A2

n= number of turns /length of wire = 1700/0.75 = 2266.67

I= 0.48 A

Hence;

B= 4π x 10^-7 × 2266.67 ×0.48

B= 1.37 ×10^-3 T

Answer:

correct

Explanation:

all the answer are good cuc

The final velocity of a truck is 74.0 ft/s, if it accelerates at a range of 3.00 ft/\(s^2\) from an initial velocity of 5.00 ft/s, then it will take the truck 23.67 seconds to attain its final velocity of 74.0 ft/s.

v = u + at

Here, v =the final velocity, u =the initial velocity, a =the acceleration, and t =the time taken.

Substituting the given values, one can get,

74.0 ft/s = 5.00 ft/s + 3.00 ft/\(s^2\) × t

Solving for t, one gets,

t = (74.0 ft/s - 5.00 ft/s) / (3.00 ft/\(s^2\)) = 23.67 s (that is  23.67 seconds is needed to attain final velocity of 74.0 ft/s)

Hence, a truck needs 23.67 seconds time to attain its final velocity of 74.0 ft/s and this is the final velocity.

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If two wires, A and B, and a variable resistor, R, are connected in series to a battery, and resistance of R is increase, hence the total current through the battery will increase and the current through the entire circuit will decrease (option E)

The relationship between the voltage applied and the quantity of current flowing through something is known as the electrical resistance. In other words, we can argue that an electrical circuit's ability to resist the flow of current through it is one of its characteristics. The relationship between voltage, current, and resistance is given by Ohm's law. i.e.

V = IR

Where

V = the voltage.

I = the current.

R = the resistance (Omega / Ω)

Because the network's equivalent resistance has decreased, the current flowing through the battery will increase (current = voltage/resistance).

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The statement "In the presence of no other outside forces, an object placed under motion will continue to move forever in that same direction" is TRUE

According to Newton's first law which states that an object will continue to move in a straight line unless if the body is acted upon by a force.

Based on the law, we can see that the body will keep moving in the same direction unless if acted upon by an external force.

This means that if an object is placed under motion, it will continue to move forever in that same direction unless it is acted upon by a force. The statement is therefore TRUE

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Answer:

The answer is true.

Explanation:

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

1. The kinetic energy would be the same for the both balls.

2) As the ball gains potential energy, its speed will decrease.

Kinetic energy is the energy possessed by an object due to its motion. The amount of kinetic energy an object has is dependent on its mass and velocity. An object with a greater mass and a higher velocity will have a higher kinetic energy than an object with a smaller mass and lower velocity.

The increase in the potential energy as the ball reaches the maximum height would imply that the ball would become stationary for some time and the speed will decrease.

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Answer: Limestone Caves

Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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Answer:

a

 \(Q_e  =  -4.39 *10^{11}  \  C \)

b

\(Q_p  =  + 2.395*10^{-8} \  C \)

Explanation:

Generally the number of electron in the given mass is  mathematically evaluated as

        \(N_e =  \frac{2.5}{m_e }\)

Here  m_e is the mass of electron with value \(m_e =  9.11 * 10^{-31} \  kg\)

    =>  \(N_e =  \frac{2.5}{ 9.11 * 10^{-31} }\)

       =>  \(N_e =2.74 *10^{30} \  electrons \)

The total electric charge is mathematically represented as

       \(Q_e  =  N_e  *  e\)

Here e is the charge on a single electron with value  \(e  =  1.60 *10^{-19}  \  C\)

 So

          \(Q_e  =  -2.74 *10^{30}   *  1.60 *10^{-19} \)

          \(Q_e  =  -4.39 *10^{11}  \  C \)

The  negative sign is because we are considering electron

Generally the number of  protons in the given mass is  mathematically evaluated as

    \(N_p =  \frac{2.5}{m_p }\)

Here  m_p is the mass of electron with value \(m_e =  1.67 * 10^{-27} \  kg\)

    =>  \(N_p =  \frac{2.5}{ 1.67 * 10^{-27} }\)

       =>  \(N_p =1.497 *10^{27} \  protons \)

The total electric charge is mathematically represented as

       \(Q_p  = + N_p  *  e\)

Here p is the charge on a single proton with value  \(p  =  1.60 *10^{-19}  \  C\)

 So

          \(Q_p  =  +1.497 *10^{27}   *  1.60 *10^{-19} \)

          \(Q_p  =  + 2.395*10^{-8} \  C \)

1. b. electrical potential energy.

2. a. True. For electric potential energy, a reference position must be defined.

3. a. -4 J. The potential energy between two charges is given by the equation U = k(q1q2)/r, where k is the electrostatic constant, q1 and q2 are the charges, and r is the separation between them. Since the potential energy is given as 2 J initially, and q2 is replaced by q3 (which is negative and twice the magnitude of q2), the potential energy becomes -4 J.

4. c. decreases. The potential energy between two charges decreases as they are moved closer together.

5. b. -3.24 J. The electric potential energy between two point charges is given by the equation U = k(q1q2)/r, where k is the electrostatic constant, q1 and q2 are the charges, and r is the separation between them. Substituting the values into the equation, we get U = (9x10^(-6) C)(-4x10^(-6) C)/(0.1 m) = -3.24 J.

6. a. B or D. Electric potential energy can never be negative if the charges repel each other.

7. c. measures energy per unit charge.

8. 12 J. The potential energy is given by the equation U = qV, where U is the potential energy, q is the charge, and V is the potential. Substituting the values into the equation, we get U = (6 C)(2 V) = 12 J.

9. b. 10 V. The electric potential is given by the equation V = U/q, where V is the potential, U is the potential energy, and q is the charge. Substituting the values into the equation, we get V = 50 J/5 C = 10 V.

10. c. 14 V. The electric potential is inversely proportional to the distance from a point charge. When the distance is doubled, the potential is halved. Therefore, the electric potential at the new position of q2 is 28 V/2 = 14 V.

11. c. increases. The potential at the position of q2 due to q1 increases when a negative test charge is substituted with twice the magnitude of the positive test charge.

12. By convention, the direction of a current is taken to be the direction of motion of negative charges. In reality, it is actually electrons that move in wires.

13. c. 0.25 A. The current is defined as the rate of flow of charge. Given that 15 C flows through the wire each minute, the current is 15 C/60 s = 0.25 A.

14. b. 1.2x10^6 C. The charge flowing through the wire is given by the equation Q = It, where Q is the charge, I is the current, and t is the time. Substituting the values into the equation, we get Q = (3x10^(-3) A)(1 hour)(3600 s/hour) = 1.2x10^6 C.

15. d. current. An ampere is a unit of electric current.

16. electrons. As current flows through a wire, it is actually electrons that move. The flow of electrons constitutes the electric current.

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Answer: These apparent star tracks are in fact not due to the stars moving, but to the rotational motion of the Earth. As the Earth rotates with an axis that is pointed in the direction of the North Star, stars appear to move from east to west in the sky.

Explanation: why do the star constellations seem to move across the sky

Answer:

because the world moves around and around rotating in a circle and circling around the sun so as we move the stars stay the same but to our view it looks like their moving but in reality we are.

Explanation:

Answer:

what's the question ,so I can answer it right ?

A is the answer  because it is the answer

Answer:

Alfred Wegener

Explanation:

Answer:  A. He developed the world's first star catalogue.

Explanation: Gan De's contribution to astronomy was the development of the world's first star catalogue , along with his colleague Shi Shen. He also made observations of the planets, particularly Jupiter, and may have been the first to describe one of Jupiter's moons. Unfortunately, all of Gan De's writings have been lost, but fragments of his works' titles and quoted fragments are known from later texts.

Answer:

Velocity and Time

Explanation:

I googled it-

The kinematic relationships we can find the position, acceleration and launch angle of the body on the planet Exidor.

a) the position are

      time (s)  x (m)   y(m)

        0            0          0

        2.0         3.6        1.2

        3.0         5.4        0.9

b) The aceleration is  g = 0.6 m / s²

c) The launch angle      θ = 33.7º

given parameters

to find

    a) position

    b) acceleration

    c) launch angle

Projectile launch is an application of kinematics to the movement of the body in two dimensions where there is no acceleration on the x axis and the y axis has the planet's gravity acceleration

b) To calculate the acceleration of the plant acting on the y-axis, we use that the vertical velocity of the body at the highest point is zero.

         v_y = v_{oy} - g t

where v and v({oy}  are the velocities of the body, g the acceleration of the planet's gravity and t the time

          0 = v_{oy} - gt

           g = v_{oy} / t

from the graph we observe that the highest point occurs for t = 2.0 s

           g = 1.2 / 2.0

           g = 0.6 m / s²

a) The position is requested for several times

X axis

in this axis there is no acceleration so we can use the uniform motion relationships

          vₓ = x / t

          x = vₓ t

where x is the position, vx is the velocity and t is the time

we calculate for the time

t = 0.0 s

          x₀ = 0

t = 2.0 s

          x₂ = 1.8 2

          x₂ = 3.6 m

t = 3.0 s

          x₃ = 1.8 3

          x₃ = 5.4 m

Y axis

In this axis there is the acceleration of the planet, let us use for the position the relation

          y = v_{oy} t - ½ g t²

t = 0.0 s

          y₀ = 0

          y₀ = 0 m

t = 2.0 s

         y₂ = 1.2 2 - ½ 0.6 2²

         y₂ = 1.2 m

t = 3.0 s

        y₃ = 1.2  3 - ½  0.6  3²

        y₃ = 0.9 m

c) the launch angle use the trigonometry relation

        tan θ = \(\frac{v_y}{v_x}\)

        θ = tan⁻¹ \(\frac{v_y}{v_x}\)

        θ = tan⁻¹ \(\frac{1.2}{1.8}\)

        θ = 33.7º

measured counterclockwise from the positive side of the x-axis

With the kinematic relationships we can find the position, acceleration and launch angle of the body on the planet Exidor.

a) the position are

      time (s)  x (m)   y(m)

        0            0          0

        2.0         3.6        1.2

        3.0         5.4        0.9

b) The aceleration is  g = 0.6 m / s²

c) The launch angle      θ = 33.7ºto)

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Answer:

60 ohms

Explanation:

To find the equivalent resistance of two resistors R₁ and R₂ in parallel, we can use the formula:

1/Req = 1/R₁ + 1/R₂

where Req is the equivalent resistance.

Substituting the values given, we get:

1/Req = 1/30 + 1/20

Simplifying, we get:

1/Req = 1/60

Multiplying both sides by Req, we get:

Req = 60 ohms

Therefore, the equivalent resistance of the two resistors R₁ and R₂ in parallel is 60 ohms.

Answer:

the answer is the first letter in the alphabet

Explanation:

To find the net work done on the particle to cause it to move to the right at 38 m/s, we need to use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:

Net work = ΔK = 1/2 * m * (vf^2 - vi^2)

where m is the mass of the particle, vi is its initial velocity (to the left), and vf is its final velocity (to the right).

Substituting the given values, we get:

Net work = 1/2 * 0.059 kg * (38 m/s)^2 - 1/2 * 0.059 kg * (27 m/s)^2

Net work = 46.4657 J - 22.6545 J

Net work = 23.8112 J

Therefore, the net work done on the particle to cause it to move to the right at 38 m/s is 23.8112 Joules.

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 95 × 25

We have the final answer as

Hope this helps you

Answer:

Fuel cells (Chemical energy → Electrical energy) Battery (electricity) (Chemical energy → Electrical energy) Fire (Chemical energy → Heat and Light)

Explanation:

Answer:

the ball lose kentic energy and gains potential energy rolling upward

Answer:

c

Explanation:

when a ball is rolling down it loses potential and gains kinetic, but in this case since the ball is going upwards it is losing kinetic energy and gaining potentail like a roller coaser

An example of convection currents is the movement of air in a room when a heater is turned on. When the heater warms the air in the room, the warm air becomes less dense and rises, creating a convection current. As the warm air rises, cooler air from other parts of the room moves in to replace it, creating a continuous circulation of air. This process is known as natural convection.

Convection currents occur when there is a transfer of heat through the movement of a fluid, either liquid or gas. Here is a step-by-step explanation of convection currents:

Heating: In the example of a room with a heater, the heating element of the heater warms the air in the vicinity.

Expansion: As the air near the heater gets heated, it expands and becomes less dense. This decrease in density makes the warm air rise.

Rising: The warm air rises upward due to its buoyancy. This upward movement creates an area of low pressure near the heater.

Replacement: As the warm air rises, cooler air from other parts of the room moves in to fill the space left by the rising warm air. This cooler air is denser and moves downward.

Circulation: The cycle continues as the warm air rises, cools down, and then descends to be heated again by the heater. This creates a continuous circulation of air, forming convection currents.

Other examples of convection currents include the movement of boiling water in a pot, the circulation of air in the atmosphere resulting in wind patterns, and the movement of magma in the Earth's mantle leading to plate tectonics. Convection currents play a significant role in distributing heat energy and maintaining fluid movements in various natural and artificial systems.

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