The solution is -1/2.

Which division equation also has the given solution?

Answer:

2×2×2×7

Step-by-step explanation:

if you multply 2×2 it is 4×2=8×7=56

backward is easy 7×2= 14×2= 28×2=56

2 × 2 × 2 × 7 is the prime factorization of the number 56.

Given that,
To determine the number whose prime factorization is given as 2 x 2 x 2 x 7.

Factors can be defined by splitting the value into multipliable values.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Prime factorization of the number are a multiplicable number that consists of the prime numbers only,
According to the question,
2 x 2 x 2 x 7  = 56

Thus,  2 × 2 × 2 × 7 is the prime factorization of the number 56.

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Answer:

21

Step-by-step explanation:

Answer:

Y(0,13)

X(13,0)

Answer:

The median is 1.84 and the difference between the first and third quartile is 0.34

Step-by-step explanation:

When you write them out 1.84 is the median (middle number). To find the difference I just subtracted the third quartile (2.09) by the first quartile (1.75)

========================================================

Explanation:

Original data set = {1.96, 2.09, 1.79, 1.61, 1.75, 2.11, 1.84}

Sorted data set = {1.61, 1.75, 1.79, 1.84, 1.96, 2.09, 2.11}

Notice that 1.84 is in the middle of the sorted set. Three values are smaller than it, and three values are larger than it.

Therefore, 1.84 is the median.

The values {1.61, 1.75, 1.79} are smaller than the median. We'll call this set L for lower set.

The values {1.96, 2.09, 2.11} are larger than the median. We'll call this set U for upper set.

From set L = {1.61, 1.75, 1.79}, the median here is 1.75. This is the value of the first quartile Q1

The value of Q3 is 2.09 as it is in the direct middle of set U = {1.96, 2.09, 2.11}

The interquartile range (IQR) is the difference of Q3 and Q1

IQR = Q3 - Q1

IQR = 2.09 - 1.75

IQR = 0.34

The circled portion in the confidence interval formula p ± z represents the Margin of Error, which plays a crucial role in interpreting the range of plausible values for the population parameter.

In the confidence interval formula p ± z, the circled portion represents the Margin of Error.

The Margin of Error is a critical component of a confidence interval and quantifies the level of uncertainty in the estimate.

It indicates the range within which the true population parameter is likely to fall based on the sample data.

The Margin of Error is calculated by multiplying the critical value (z) by the standard deviation of the sampling distribution.

The critical value is determined based on the desired level of confidence, often denoted as (1 - α), where α is the significance level or the probability of making a Type I error.

The Margin of Error accounts for the variability in the sample and provides a measure of the precision of the estimate.

It reflects the trade-off between the desired level of confidence and the width of the interval.

A larger Margin of Error indicates a wider confidence interval, implying less precision and more uncertainty in the estimate.

Conversely, a smaller Margin of Error leads to a narrower confidence interval, indicating higher precision and greater certainty in the estimate.

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so the idea being, we have a system of equations of two variables and 4 equations, each one rendering a line, for this case these aren't equations per se, they're INEquations, so pretty much the function will be the same for an equation but we'll use > or < instead of =, but fairly the function is basically the same, the behaviour differs a bit.

we have a line passing through (-6,0) and (0,8), side one

we have a line passing through the x-axis and -6, namely (-6,0) and the y-axis and -4, namely (0,-4), side two

we have a line passing through (0,-4) and (6,4), side three

now, side four is simply the line connecting one and three.

the intersection of all four lines looks like the one in the picture below, so what are those lines with their shading producing that quadrilateral?

well, we have two points for all four, and that's all we need to get the equation of a line, once we get the equation, with its shading like that in the picture, we'll make it an inequality.

\((\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{8 -0}{0 +6} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = \cfrac{4}{3} ( x +6) \\\\\\ y=\cfrac{4}{3}x+8\hspace{5em}\stackrel{\textit{side one} }{\boxed{y < \cfrac{4}{3}x+8}}\)

\(\rule{34em}{0.25pt}\\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{-4 -0}{0 +6} \implies \cfrac{ -4 }{ 6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = - \cfrac{2}{3} ( x +6) \\\\\\ y=-\cfrac{2}{3}x-4\hspace{5em}\stackrel{\textit{side two} }{\boxed{y > -\cfrac{2}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(\stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{(-4)}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{0}}} \implies \cfrac{4 +4}{6 -0} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{0}) \implies y +4 = \cfrac{4}{3} ( x -0) \\\\\\ y=\cfrac{4}{3}x-4\hspace{5em}\stackrel{ \textit{side three} }{\boxed{y > \cfrac{4}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\((\stackrel{x_1}{6}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{6}}} \implies \cfrac{ 4 }{ -6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{6}) \\\\\\ y=-\cfrac{2}{3}x+8\hspace{5em}\stackrel{ \textit{side four} }{\boxed{y < -\cfrac{2}{3}x+8}}\)

now, we can make that quadrilateral a trapezoid by simply moving one point for "side four", say we change the point (0 , 8) and in essence slide it down over the line to  (-3 , 4).  Notice, all we did was slide it down the line of side one, that means the equation for side one never changed and thus its inequality is the same function.

now, with the new points for side for of (-3,4) and (6,4), let's rewrite its inequality

\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{(-3)}}} \implies \cfrac{4 -4}{6 +3} \implies \cfrac{ 0 }{ 9 } \implies 0\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{ 0}(x-\stackrel{x_1}{(-3)}) \implies y -4 = 0 ( x +3) \\\\\\ y=4\hspace{5em}\stackrel{ \textit{side four changed} }{\boxed{y < 4}}\)

Answer:

a)

 103

         |

       96 +

         |

       92 |     *  

         |    * *  

       88 +--*    

         | *      

       84 |        

         |*        

       80 +        

         |        

       79 |        

         |        

       72 +        

         |        

       70 |

         |

b)b. The range is the difference between the highest and lowest scores: 103 - 45 = 58.

The IQR is the interquartile range, which is the range of the middle 50% of the scores. To find it, we first need to find the first and third quartiles:

   The first quartile (Q1) is the median of the lower half of the scores, which are 45, 70, 72, 79, and 80. The median of this set is (72+79)/2 = 75.5.

   The third quartile (Q3) is the median of the upper half of the scores, which are 84, 87, 88, 92, and 96. The median of this set is (88+92)/2 = 90.

Therefore, the IQR is 90 - 75.5 = 14.5.

c)c. To find any outliers, we need to first define the "fences" of the box and whisker plot. The lower fence is Q1 - 1.5IQR = 75.5 - 1.514.5 = 53.25. The upper fence is Q3 + 1.5IQR = 90 + 1.514.5 = 112.75.

There is one score that is outside the fences: 103. Therefore, 103 is an outlier.

Step-by-step explanation:

1a. The percentage total return is -19.56%

1b. The dividend yield is 2.42%.

1c. The capital gains yield is -21.98%.

2a. The arithmetic average annual return on large-company stocks in nominal terms is 14.5%.

2b. The arithmetic average annual return on large-company stocks in real terms is 9.67%.

3a. The real return on long-term government bonds is 3.195%

3b. The real return on long-term corporate bonds is 3.291%

In Financial accounting, the percentage total return (P) can be calculated by using this formula;

P = [(Ending price - Initial price) + Dividend] ÷ Initial price

P = [(71 - 91) + 2.20] ÷ 91

P = -0.1956 or -19.56%

1b. For the dividend yield, we have:

Dividend yield = Dividend ÷ Initial price

Dividend yield = 2.20 ÷ 91

Dividend yield = 0.0242 or 2.42%

1c. For capital gains yield, we have:

Capital gains yield = (Ending price - Initial price) ÷ Initial price

Capital gains yield = (71 - 91) ÷ 91

Capital gains yield = -0.2198 or -21.98%.

Part 2.

a. The arithmetic average of annual return on large-company stocks in nominal terms is equal to 14.5%.

b. For arithmetic average annual return in real terms, we have:

(1 + 0.145) = (1 + r)(1 + 0.044)

r = (1.145/1.044) - 1

r = 9.67%

Part 3.

a. For real return on the long-term government bonds, we would apply Fisher equation:

(1 + i) = (1 + r)(1 + h)

Where:

(1 + 0.066) = (1 + r)(1 + 0.033)

1 + r = 1.066/1.033

r = 3.195%

b. For real return on long-term corporate bonds:

(1 + 0.067) = (1 + r)(1 + 0.033)

1 + r = 1.067/1.033

r = 3.291%

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Answer:

x=-1, y=4. (-1, 4).

Step-by-step explanation:

-6x-y=2

-7x-4y=-9

----------------

y=-6x-2

-7x-4(-6x-2)=-9

-7x+24x+8=-9

17x=-9-8

17x=-17

x=-17/17

x=-1

-6(-1)-y=2

6-y=2

y=6-2=4

In-state corresponds to students who are residents of the same state as the university, out-of-state corresponds to students from different states, and foreign corresponds to students from countries other than the university's country.

To match the vocabulary word with its corresponding example in the context of the state university survey, we need to understand the terms and their meanings.

Here are the vocabulary words and their corresponding examples:

Vocabulary Word: In-state

Example: A student who is a resident of the same state where the university is located.

They pay lower tuition fees compared to out-of-state or foreign students.

Vocabulary Word: Out-of-state

Example: A student who is not a resident of the state where the university is located.

They typically pay higher tuition fees compared to in-state students.

Vocabulary Word: Foreign

Example: A student who is from a country other than the country where the university is located.

They are international students who may have different visa requirements and tuition fees.

To match these vocabulary words with their corresponding examples:

In-state: A student from the same state as the university, paying lower tuition fees.

Out-of-state: A student from a different state than the university, paying higher tuition fees.

Foreign: A student from a country other than the country where the university is located, with potential differences in visa requirements and tuition fees.

By associating each vocabulary word with its respective example, we can accurately describe the three categories of students based on their residency and origin in the context of the state university's survey.

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Answer:

A. the angular speed is 3771.4 rad/min

b. 5921 rpms

Step-by-step explanation: I just got this same question right on a test.

Answer: $46

Step-by-step explanation:

The freighter is approximately 164.33 miles from the city.

We can use the Law of Cosines to solve this problem. Let's label the distances as follows:

d: distance between the city and the freighter

x: distance between the city and the island

y: distance between the island and the freighter

First, we need to find x using the given coordinates:

N23°38'W is equivalent to S23°38'E, so we have:

cos(23°38') = x/48

x = 48cos(23°38') ≈ 42.67 miles

Next, we can use the coordinates of the freighter to find y:

N11°26'E is equivalent to E11°26'N, and N12°16'W is equivalent to S12°16'E. This means that the angle between the island and the freighter is:

23°38' + 11°26' + 12°16' = 47°20'

cos(47°20') = y/d

We can rearrange this equation to solve for y:

y = dcos(47°20')

Now we can use the Law of Cosines to solve for d:

d² = x² + y² - 2xy cos(90° - 47°20')

d² = 42.67² + (d cos(47°20'))² - 2(42.67)(d cos(47°20')) sin(47°20')

d² = 1822.44 + d² cos²(47°20') - 2(42.67)(d cos(47°20')) sin(47°20')

d² - d² cos²(47°20') = 1822.44 - 2(42.67)(d cos(47°20')) sin(47°20')

d² (1 - cos²(47°20')) = 1822.44 - 2(42.67)(d cos(47°20')) sin(47°20')

d² sin²(47°20') = 1822.44 - 2(42.67)(d cos(47°20')) sin(47°20')

d² = (1822.44 - 2(42.67)(d cos(47°20')) sin(47°20')) / sin²(47°20')

d ≈ 164.33 miles

Therefore, the freighter is approximately 164.33 miles from the city.

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Answer:

2√2 units.

Step-by-step explanation:

To find the length of the line joining points A(3, 5) and B(1, 3), we can use the distance formula. The distance formula is given by:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Substituting the coordinates of points A and B into the formula, we have:

d = sqrt((1 - 3)^2 + (3 - 5)^2)

  = sqrt((-2)^2 + (-2)^2)

  = sqrt(4 + 4)

  = sqrt(8)

  = 2sqrt(2)

Therefore, the length of the line joining points A and B is 2√2 units.

Answer:

Step-by-step explanation:

Answer to number 1 is a slope of -3 and the y=-3x-26 For number 2 the slope is 5 and y=5x+5 and for number 3 the slope is 2/3 and b is y=2/3x-20/3 for number 4 its 4 in the x section and 5 for the y section number 5 is --5 and for number 6 its -12. I found the slopes by using this formula y2-y1/x2-x1 and for the b I used y=mx+b and used one of the points to figure it out! I hope this helped out :3

Answer:

8p + 2s <= 150

Step-by-step explanation:

Let p = number of a pizza.

Let s = price of a bottle of soda.

The inequality is

8p + 2s <= 150

The residual value with an actual value of 10 and a predicted value of 14 will be 4. Then the correct option is D.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

PEMDAS rule means for the Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to solve the equation in a proper and correct manner.

We know that the difference between the predicted value and to actual value is known as the residual value.

Residual value = Predicted value - Actual value

If the observed (actual) y value is 10, and the predicted value is 14. Then the residual value will be

Residual value = 14 - 10

Residual value = 4

The residual value will be 4. Then the correct option is D.

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Answer:

See below

Step-by-step explanation:

Answer:

you could be correct but I think it's B

For each pound of the blend, Cold Beans should use 3 pounds of Guatemalan coffee.

This means that in a 6-pound bag of the blend, they would use \(3 \times 6 = 18\)pounds of Guatemalan coffee.

Let's assume that x pounds of Guatemalan coffee are used per pound of the blend.

Given information:

Cost of Guatemalan coffee = $11/lb

Cost of the other coffee = $5/lb

Desired cost of the blend = $8/lb

Total weight of the blend = 6 pounds

To find the ratio of Guatemalan coffee to the total blend, we can set up the equation:

\((x \times 11 + (6 - x) \times 5) / 6 = 8\)

In this equation, \((x \times 11)\) represents the cost of the Guatemalan coffee in the blend, and\(((6 - x) \times 5)\) represents the cost of the other coffee in the blend.

The numerator is the total cost of the blend, and we divide it by 6 (the total weight of the blend) to find the cost per pound.

Now, let's solve the equation for x:

(11x + 30 - 5x) / 6 = 8

6x + 30 = 48

6x = 48 - 30

6x = 18

x = 18/6

x = 3

Therefore, for each pound of the blend, Cold Beans should use 3 pounds of Guatemalan coffee.

This means that in a 6-pound bag of the blend, they would use \(3 \times 6 = 18\)pounds of Guatemalan coffee.

To summarize, to achieve a cost of $8 per pound for a 6-pound bag of blend, Cold Beans should use 3 pounds of Guatemalan coffee per pound of the blend.

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The value of x for the chord is:

x = 12

A chord of a circle is a straight line segment whose endpoints both lie on a circular arc.

Recall that: If two chords intersect inside the circle, then they cut each other in such a way that the product of the lengths of the parts is the same for the two chords.

Using the above principle, we can say:

3 * x = 4 * 9

3x = 36

x = 36/3

x = 12

Thus, the value of x for the chord is 12.

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Answer:

4 i took the k12 quiz

Step-by-step explanation:

Answer: i swear people were saying it was 14 and 3 glad i got the right answer  

Step-by-step explanation:

Answer:

a) 263,158

b) $164,500

c) Ethical issues companies face when deciding to move operations: job loss for employees, poor working conditions and exploitation of workers, negative environmental impact,...

Step-by-step explanation:

a)

Total cost = (0.25 + 0.02 + 0.03 + 0.15) x + 250,000

Total revenue = 1.40x

Setting the two equations equal to each other and solving for x, we get:

(0.45)x + 250,000 = 1.40x

0.95x = 250,000

x ≈ 263,158

b)

If the company sells 270,000 candy bars at $1.40 each, the total revenue generated is:

270,000 * $1.40 = $378,000

The total cost of producing 270,000 candy bars is:

(0.25 + 0.02 + 0.03 + 0.15) * 270,000 + $250,000 = $213,500

Therefore, the company's profit is:

$378,000 - $213,500 = $164,500

c)

Ethical issues companies face when presented with the decision to move operations: job loss for employees, poor working conditions and exploitation of workers, negative environmental impact,...

Write the times for each hour from start time:

10:25 am

11:25 am

12:25 pm

1:25 pm

2:25 pm

3:25 pm

4:25 pm

5:25 pm

6:25 pm

There are 8 hours between 10:25 am and 6:25 pm.

they finished at 6:15 which is 10 minutes before 6:25 ( 25-15 = 10)

10 minutes less than a full hour is 50 minutes ( 60 - 10 = 50)

8 hours - 1 hour = 7 hours

7 hours + 50 minutes = 7 hours 50 minutes total time.

Answer:

seven hours and 50 minutes

Step-by-step explanation:

Given the Absolute Value Function:

You need to remember that the form of an Absolute Value Function is:

Where "h" is the x-coordinate of the vertex, and "k" is the y-coordinate of the vertex. If "a" is positive the function opens up, and if it is negative, the function opens down.

By definition:

- If "a" is positive, then the Range of the function is:

- If "a" is negative, the Range of the function is:

In this case, you can identify that:

Therefore, you can determine that its Range is:

Hence, the answer is: Second option.

Answer: It would be the first one (20 pens for 8$)

Step-by-step explanation: If you divide 20 by 8 then each pencil will be 2.50$. However if you divide 30 by 10 it will be 3 dollars for each pencil so the first deal will be better since you spend less money.

Answer:

x = 2

Step-by-step explanation:

Using a table

We want to find the value of x when f(x) = -69.2

From the table we see that when f(x) = -69.2, x = 2