In the radioactive decay of tritium (hydrogen-3) to helium-3, a beta particle is involved to ensure that the total numbers of neutrons and protons remain unchanged.
The decay can be represented by the following equation:
¹H₃ (tritium) → ²He₃ (helium-3) + β⁻ (beta particle)
In this process, one neutron from tritium is converted into a proton, forming helium-3, and a beta particle (electron) is emitted to conserve the total number of neutrons and protons.
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to remove the cannula at the end of a laparoscopy, the surgeon pulls on the cannula with increasing force. how does the frictional force vary with the applied pulling force before and after the cannula begins to slide?
When the pulling force is first applied, the cannula doesn't move because of the static friction. After a while, at a certain amount of applied force, friction increases until the limit reached its threshold for the motion.
Friction is the force that resists the sliding motion between two surfaces. It can be kinetic or static. Static friction happens when the two surfaces don't slide because the amount of static friction fully counteracts an applied force. It happens until the upper limit is reached, which will happen when one applied enough amount of force to the surface. Once the upper limit is reached, the surfaces will start to slide against each other, in which the static friction becomes kinetic friction.
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(a) By solving the diffusion equation for a planar source the diffusion kernel for an infinite slab of thickness a is given by located at x, show that - x sinh
(b) Using this kernel calculate the flux in a slab containing uniformly distributed sources emitting S neutrons/cm3-sec.
The one-dimensional diffusion equation or Fick's second law is the name of this equation. For the geographically and temporally variable concentration, it is solvable.
A diffusion explanation is what?
The movement of molecules along a concentration gradient is known as diffusion. It is a significant process that all living things go through. Diffusion facilitates the flow of materials into and out of cells.
Which definition of diffusion is the best?
Diffusion is the movement of molecules from a region where they are more concentrated to one where they are less concentrated. Therefore, "Movement of molecules from a region of their greater concentration to a region of their lower concentration" is the right response.
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a car of mass 1500 kg is moving with the speed of 72 km/ hr (calculated it's kinetic energy)
Answer:
So work require will be 3888×10×10³J
Explanation:
⇒Work done=Change in kinetic energy
⇒KE=1/2mv²
⇒Mass->15000kg
⇒Velocity->72km/h
⇒KE=1/2×15000×(72)²
⇒KE=1/2×15000×5184
⇒KE=7500×5184
⇒KE=3888×10×10³J
An object originally at rest, is accelerated uniformly along a straight line to a speed of 8m/s in 2s. What is the acceleration of the object?
Answer:
4m/s²
Explanation:
Initial velocity (u) = 0 m/s
Final velocity (v) = 8 m/s
Time taken (t) = 2 sec
Acceleration (a) = ?
We know
\(a = \frac{v - u}{t} \\ = \frac{8 - 0}{2} \\ = \frac{8}{2} \\ = 4 \: m |s ^{2} \)
Hope it will help :)
Which has more kinetic energy, a 40 kg cheetah running at 25 m/s or a 4,000 kg elephant moving at 2 m/s? How much more energy does it have?
Answer:
1st case; mass=40 kg
v=25m/s
K.E.=1/2[40][25]^2=12,500 J
2nd case; mass=4,000 kg
v=2 m/s
K.E.=1/2[4000][2]^2=8000J
in case 1 Kinetic energy is greater.
Explanation:
Using the Left Hand Rule, if current points up and
the field is toward you, which way does the motion
point?
A. Left
B. Down
c. Up
D. Right
Using the left hand rule, if current points up and the field is toward you, the motion points up.
What is the left hand rule?The left hand rule states that if the thumb, the fore finger and the middle finger are held mutually perpendicular to each other, the thumb points in the direction motion, the middle finger points in the direction of current while the fore finger points in the direction of the magnetic field.
Thus using the left hand rule, if current points up and the field is toward you, the motion points up.
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A scooter has a mass of 250 kg. A constant force is exerted on it for 60.0 s. During the time the force is exerted, the scooter increases its speed from 0.00 m/s to 28.0 m/s. What is the magnitude of the force exerted on the scooter?
Answer:
5500
Explanation:
I cant explain it but when i asked my teacher thats what he told me
You are running 4.2 m/s along a tall roof top. You have 590,646 Joules of ME and have a mass of 300 kg. How tall is the building?
You are running 4.2 m/s along a tall roof top. You have 590,646 Joules of mechanical energy and have a mass of 300 kg. The building is 200 meter tall.
What is energy?Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
kinetic energy + potential energy = mechanical energy
Kinetic energy = \(\frac{1}{2} mv^{2}\) = 2646 joule
potential energy = ME - KE
P E = 590646 - 2646 = 588000 Joule
P E = mgh
h = P E / mg
h = 200 meter
You are running 4.2 m/s along a tall roof top. You have 590,646 Joules of mechanical energy and have a mass of 300 kg. The building is 200 meter tall.
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The first step of the scientific method is
Answer: make objective observations.
Explanation:
Answer: Objective Observations
Explanation: The first step in the Scientific Method is to make objective observations. These observations are based on specific events that have already happened and can be verified by others as true or false.
6. What is the uncertainty in position of a proton with mass 1.673 x 10-27 kg and kinetic energy 1.2 keV?
According to Heisenberg's Uncertainty Principle, it is impossible to determine the position and momentum of a particle with absolute certainty at the same time. The Uncertainty Principle is defined as Δx * Δp ≥ h/4π, where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is Planck's constant.
For the given problem, the uncertainty in position of a proton with mass 1.673 x 10-27 kg and kinetic energy 1.2 keV can be calculated as follows:
We know that the momentum p of a particle is given by p = mv, where m is the mass of the particle and v is its velocity.
The kinetic energy of the proton can be converted to momentum using the equation E = p²/2m, where E is the kinetic energy.
1.2 keV = (p²/2m) (1 eV = 1.6 x 10^-19 J)
p²/2m = 1.92 x 10^-16 J
The momentum p of the proton can be calculated by taking the square root of both sides:
p = √(2mE) = √(2 x 1.673 x 10^-27 x 1.6 x 10^-16) = 7.84 x 10^-22 kg m/s
Using Heisenberg's Uncertainty Principle, we can calculate the uncertainty in position as follows:
Δx * Δp ≥ h/4π
Δx ≥ h/4πΔp
Substituting the values of h, Δp, and solving for Δx:
Δx ≥ (6.626 x 10^-34)/(4π x 7.84 x 10^-22)
Δx ≥ 2.69 x 10^-12 m
Therefore, the uncertainty in position of the proton is 2.69 x 10^-12 m.
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1. The longest banana split ever made was 8.04 km long (needless to say, more than one banana
was used). If an archer were to shoot an arrow horizontally from the top of Mount Everest, which
is located 8848 m above sea level, would the arrow's horizontal displacement be larger than 8.04
km? Assume that the arrow cannot be shot faster than 100.0 m/s, that there is no air resistance,
and that the arrow lands at sea level.
Answer: If an archer were to shoot an arrow horizontally from the top of Mount Everest, which is located 8848 m above sea level, would the arrow's horizontal
Explanation:
an object of mass 20kg is lifted to a 25m building. how much potential energy is stored on a mass?(take g=10m/s²)
Answer:
5000J
Explanation:
hope this helps you
Which of these sources are used to generate electrical energy in power plants? Check all that apply.
coal
natural gas
biodiesel
nuclear reactions
wind
batteries
water
Answer:
all but biodeisel and batteries
Explanation:
well batteries are used to STORE energy not generate it
An object of mass m moves at a constant speed v in a circular path of radius r. The force required to produce the centripetal component of acceleration is called the centripetal force and is given by F = mv2/r. Newton's Law of Universal Gravitation is given by F = GMm/d?, where d is the distance between the centers of the two bodies of masses M and m, and G is a gravitational constant. The speed required for circular motion is v = V GM/r. Use the result above to find the speed necessary for the given circular orbit around Earth.
speed required for the predetermined elliptical trajectory of the planet is 7908m/s
The speed necessary for the given circular orbit around Earth is given as follows;v = V GM/r.Here is the solution; Given formula:v = V GM/r.We know that the mass of the earth is 5.77 x \(10^(24)\) kg and the radius of the orbit is 6.38 x\(10^6\)m.
The gravitational constant is 6.67 x \(10^-11 m^3/(kg s^2).\)We can now substitute the values into the equation to get the speed:v = V GM/r = V (6.67 ×\(10^( 11)\) Nm²/kg²) (5.97 × \(10^{24}\)kg)/ (6.38 m) = 7908 m/s. Therefore, the speed necessary for the given circular orbit around Earth is 7908 m/s.
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To understand the terms in the Doppler shift formula.
The Doppler shift formula gives the frequency fL at which a listener L hears the sound emitted by a source S at frequency fS:
fL=fSv+vLv+vS,
where v is the speed of sound in the medium, vL is the velocity of the listener, and vS is the velocity of source.
Part F Now, imagine that the source is to the left of the listener, so that the positive reference direction is in the ?x direction. If the source is stationary, what value does fL approach as the listener's speed (moving in the +x direction) approaches the speed of sound?
a) 0 b) 1/2 fs c) 2fs d) it approaches infinitly
Part G In this last case, imagine that the listener is stationary and the source is moving toward the listener at the speed of sound. (Note that it is irrelevant whether the source is moving to the right or to the left. ) What is fL when the sound waves reach the listener?
a) 0 b) 1/2 fs c) 2fs d) it approaches infinitly
Part F If the source is stationary, then vS=0 and the Doppler shift formula for frequency fL simplifies to:fL=fSv+vLv Substituting v=vS=vL for the velocity of sound and listener, respectively, we have:fL=fS(v+vL/v)vL approaches v for the Doppler shift formula when the listener's speed approaches the speed of sound.
Therefore, the answer is option (c) 2fs.Part G In this case, the Doppler shift formula for frequency fL is:fL=fSv+vLv-vS = fS(v+vL/v-vS/v)Here, v=vL=vS for the velocity of sound, listener, and source, respectively. Therefore:fL=fS(v+vL/v-vS/v) = fS(v+v/v-v/vS) = fS(v/v) = fSIf the sound waves reach the listener, the listener and the source must be at rest relative to the medium. This means vL=vS=0. Therefore, the answer is option (b) 1/2 fs.
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Recoil is noticeable if we throw a heavy ball while standing on roller skates. If instead we go through the motions of throwing the ball but hold onto it, our net recoil will be?.
Answer:
zero
Explanation:
science classroom have electrical outlets in them . which design would be best if there were an emergency where the electricity needed to be shut off of the lab stations
In an emergency situation where the electricity needs to be shut off in a science classroom, it is essential to have a design that allows for quick and easy access to the electrical outlets. One option could be to install a master power switch that controls the power supply to all the lab stations in the classroom.
This switch should be located in a prominent and easily accessible location, such as near the classroom entrance or by the teacher's desk.
Another option could be to use individual power strips for each lab station, but with a centrally located main power switch that controls all of the power strips. This would allow for a more flexible setup and easier access to the power supply in case of an emergency. In this case, it is important to ensure that the power strips are rated for the maximum electrical load that the lab equipment may require.
Regardless of the design chosen, it is important to ensure that the emergency shut-off switch or power strip is clearly marked and easily identifiable, so that in an emergency situation, anyone can quickly and easily turn off the power to the lab stations.
Additionally, it is important to have clear protocols and procedures in place for shutting off the power supply in the event of an emergency, and to ensure that all students and staff are trained on these protocols.
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a motorcycle traveling on the highway at a velocity of 120 kilometre-per-hour passes a car traveling at a velocity of 90 kilometre-per-hour from the point of view of a passenger on the car what is the velocity of a motorcycle
Answer:
The relative velocity of the motorcycle to a passenger in the car is 30 km/h
Explanation:
The question relates to the principle of relative velocity and reference frames
The given parameters are;
The velocity of the motorcycle, v₁ = 120 km/h
The velocity of the car, v₂ = 90 km/h
The relative velocity of an object X with regards to another object Y is the velocity the object X will seem to be moving with to an observer in the rest frame of object Y written as \(\underset{v}{\rightarrow}_{X|Y}\) = \(\underset{v}{\rightarrow}_{X}\) - \(\underset{v}{\rightarrow}_{Y}\)
Therefore, the relative velocity of the motorcycle to the car is \(v_{1|2}\) = v₁ - v₂, which give;
\(v_{1|2}\) = 120 km/h - 90 km/h = 30 km/h
The relative velocity of the motorcycle to a passenger in the car = 30 km/h.
Explain why ethylated spirit at room temperature when dropped at the back of the Palm makes the Palm to feel very cold.
Answer:
methylated spirit is in fact methanol added to ethanol (usually 10% methanol is used). The liquid evaporates which means that the liquid converts to a gaseous state. This process requires energy which it extracts from your body in the form of heat.
Explanation:
common voltage values for motor starter coils (in volts ac) are: 24, 120, 208, 240, 277, 480, and 560.
Common voltage values for motor starter coils (in volts AC) are 24, 120, 208, 240, 277, 480, and 560.
These specific voltage values are commonly utilized in motor control systems for various applications. The selection of the appropriate voltage rating for a motor starter coil is crucial to ensure compatibility and reliable operation. Factors such as the power rating of the motor, electrical system requirements, and industry standards influence the choice of voltage. Using the correct voltage rating helps maintain the integrity of the motor control system, prevents potential electrical issues, and promotes safe and efficient motor performance. Therefore, it is important to consider these standard voltage values when selecting motor starter coils for different applications.
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2.
Mass of car = 200 kg and g = 10 m/s? or 10 N/kg (approx. value)
position of car
GPE (J) = mgh KE (J) =
GPE + KE
0.5mv2
(height)
60.000
top (30 m) before
ride starts so v=0
Halfway (15 m)
30,000
34 way down (7.5
4,000
m)
bottom(0 m)
0
3.
Newly created features always add to the end of the Feature list.
Choose the correct answer and select Next Question
A. True
B. False
Answer:
Explanation:
True
Which condition causes a hurricane to rotate?
a local storm surge
the Coriolis effect
several large waves
severe coastal flooding
Answer:
b
Explanation:
The Coriolis effect is a condition which causes a hurricane to rotate in a particular direction. Thus, the correct option is B.
What is the Coriolis effect?Hurricanes are the enormous storms which come with a rotating wind speed of about 74 miles per hour. The rotating wind that swirls across the warm water of the tropics and also comes with a terrifying force.
The Coriolis force is an inertial or the fictitious force, which acts on the objects which are in motion within a frame of reference that rotates them with respect to an inertial frame. In a reference frame, with the clockwise rotation, the force acts to the left of the motion of the object. Whereas, in one with anticlockwise or counterclockwise rotation, the force acts to the right of the object. The deflection of an object due to this Coriolis force is called as the Coriolis effect.
Therefore, the correct option is B.
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Michael has a constant elasticity of substitution (CES) utility function, U(q 1
,q 2
)=(q 1
rho
+q 2
rho
) rho
1
, where rho
=0 and rho≤11 14
Given that Michael's rho<1, what are his optimal values of q 1
and q 2
in terms of his income and the prices of the two goods? Answer 1. Substitute the income constraint into Michael's utility function to eliminate one control variable. Michael's constrained utility maximization problem is max q 1
,q 2
U(q 1
,q 2
)=(q 1
rho
+q 2
rho
) rho
1
s.t. Y=p 1
q 1
+p 2
q 2
We can rewrite Michael's budget constraint as q 2
=(Y−p 1
q 1
)/p 2
. Substituting this expression into his utility function, we can express Michael's utility maximization problem as: max q 1
U(q 1
, p 2
Y−p 1
q 1
)=(q 1
rho
+[ p 2
Y−p 1
q 1
] rho
) 1/rho
. By making this substitution, we have converted a constrained maximization problem with two control variables into an unconstrained problem with one control variable, q 1
2. Use the standard, unconstrained maximization approach to determine the optimal value for q 1
. To obtain the first-order condition, we use the chain rule and set the derivative of the utility function with respect to q 1
equal to zero: rho
1
(q 1
rho
+[ p 2
Y−p 1
q 1
] rho
) rho
1−rho
(rhoq 1
rho−1
+rho[ p 2
Y−p 1
q 1
] rho−1
[−− p 2
p 1
])=0 Using algebra, we can solve this equation for Michael's optimal q 1
as a function of his income and the prices: 15 (3.18) q 1
= p 1
1−σ
+p 2
1−σ
Yp 1
−σ
where σ=1/[1−rho]. By repeating this analysis, substituting for q 1
instead of for q 2
, we derive a similar expression for his optimal q 2
: (3.19) q 2
= p 1
1−σ
+p 2
1−σ
Yp 2
−σ
Thus, the utility-maximizing q 1
and q 2
are functions of his income and the prices.
The optimal values of \(q_1\) and \(q_2\) are determined by these equations, which are functions of Michael's income and the prices of the goods.
The given problem describes Michael's utility maximization problem with a constant elasticity of substitution (CES) utility function. The objective is to find the optimal values of \(q_1\) and \(q_2\) in terms of Michael's income (Y) and the prices of the two goods (\(p_1\) and \(p_2\)).
1. Substitute the income constraint into Michael's utility function:
\(U(q_1, q_2) = (q_1^\rho + q_2^\rho)^(1/\rho)\)
s.t. \(Y = p_1q_1 + p_2q_2\)
We can rewrite Michael's budget constraint as \(q_2 = (Y - p_1q_1)/p_2\). Substituting this expression into his utility function, we have:
\(U(q_1, p_2, Y) = (q_1^\rho + [p_2(Y - p_1q_1)/p_2]^\rho)^{(1/\rho)\)
By making this substitution, we have converted the constrained maximization problem with two control variables (\(q_1\) and \(q_2\)) into an unconstrained problem with one control variable \((q_1)\).
2. Use the standard unconstrained maximization approach to determine the optimal value for \(q_1\). To obtain the first-order condition, we differentiate the utility function with respect to \(q_1\) and set it equal to zero:
\(\delta U / \delta q_1 = \rho(q_1^{(\rho-1)} + \rho[p_2(Y - p_1q_1)/p_2]^{(\rho-1)}(-p_1/p_2)) = 0\)
Simplifying and solving for \(q_1\):
\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[p_2(Y - p_1q_1)/p_2]^{(\rho-1)} = 0\)
\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)} = 0\)
\(\rho q_1^{(\rho-1)} = \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)[Y - p_1q_1]^{(\rho-1)\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}[Y - p_1q_1]^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y - p_1q_1)^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y^{(\rho-1)} - (\rho-1)p_1q_1(Y - p_1q_1)^{(\rho-2)})\)
This equation represents Michael's optimal \(q_1\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).
3. Similarly, we can derive a similar expression for his optimal \(q_2\):
\(q_2^{(\rho-1)} = (p_2/p_1)^(1-\rho)(Y^{(\rho-1)} - (\rho-1)p_2q_2(Y - p_1q_2)^{(\rho-2)})\)
This equation represents Michael's optimal \(q_2\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).
Therefore, these equations, which depend on Michael's income and the prices of the commodities, determine the ideal values of \(q_1\) and \(q_2\).
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if you apply a 300 newton force to a bowling ball, to send it rolling down towards the pins, and that bowling ball weighs 20 kg, what acceleration will the bowling ball feel at the moment it is released from your hand?
The acceleration of the bowling ball at the moment it is released from your hand is 15 m/s².
To calculate the acceleration, we will use Newton's second law of motion, which states that Force (F) equals mass (m) times acceleration (a). Mathematically, it is represented as:
F = m * a
We are given the force (F) as 300 N and the mass (m) as 20 kg. We need to find the acceleration (a). Rearranging the formula to solve for acceleration, we get:
a = F / m
Substituting the given values:
a = 300 N / 20 kg
a = 15 m/s²
When you apply a 300 N force to a 20 kg bowling ball, it will experience an acceleration of 15 m/s² at the moment it is released from your hand.
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two long, straight, parallel wires 6.6 cm apart carry currents of equal magnitude i. they repel each other with a force per unit length of 3.1 nn/m. find the current i.
According to the given statement is currents of equal magnitude the current I is 30mA.
What do you mean of Current?Current is the movement of electrical charge carriers, which are frequently electrons or atoms lacking in electrons. Current is frequently represented with the capital letter I. The common unit is the ampere, which is represented by the letter A.
What is current formula?According to Ohm's equation, V = IR, the current flowing through a conductor is proportional to the voltage V and resistance R. I = V/R is an alternate formulation of Ohm's law.
Briefing:Distance, r = 6.6 cm
Force per unit length, = 3.1 nN/m
Current passes, when wire is parallel:
→ I₁ = i₂
We know the relation,
\(\frac{F}{l}=\frac{\mu_0}{2 \pi} \times \frac{I_1 \times I_2}{r}\)
By substituting the values, we get
3.1 × 10⁻⁹ = \(\frac{3 \pi \times 10^{-7}}{2 \pi} \times \frac{I^2}{6.6 \times 10^{-2}}\)
The current will be:
I = 0.030884 A
= 30mA
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please write with good handwriting.
Given the following triangle, find the angle A using the appropriate sine or cosine 5.3 7 A=? law: 8.2 Given the following triangle, find the length of side x using the appropriate sine X 101° 38° o
The angle A using the appropriate sine or cosine law is 43.29 degrees.
To find angle A, we can use the cosine law, which states that $a^2 = b^2 + c^2 - 2bc \cos{A}$. We have $b=5.3$, $c=7$, and $a=8.2$, so we can plug in and solve for $\cos{A}$:$$8.2^2 = 5.3^2 + 7^2 - 2(5.3)(7) \cos{A}$$$$\cos{A} = \frac{8.2^2 - 5.3^2 - 7^2}{-2(5.3)(7)} = 0.509$$$$A = \cos^{-1}{(0.509)} \approx 43.29^\circ$$The length of side x using the appropriate sine X is 61.32 units.
We can use the sine law, which states that $\frac{a}{\sin{A}} = \frac{b}{\sin{B}} = \frac{c}{\sin{C}}$. We know that $A=101^\circ$ and $a=x$, so we can use the ratio $\frac{a}{\sin{A}}$ to solve for $x$:$$\frac{x}{\sin{101}} = \frac{c}{\sin{38}}$$$$x = \sin{101} \cdot \frac{c}{\sin{38}} \approx 61.32$$Therefore, the length of side x is approximately 61.32 units.
In geometry, the Cosine Decide says that the square of the length of any side of a given triangle is equivalent to the amount of the squares of the length of different sides short two times the result of the other different sides duplicated by the cosine of point included between them.
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is atmosphere pressure at high altitudes is less than the pressure at ground, true or false
Answer:
The answer is true I guess!!!
This is because the more you go up to less air it is and the pressure also gets less!!!!!!!!
Explanation:
I HOPE THAT I WAS HELPFUL TO YOU!
PLEASE HELP WITH THE 6 FOLLOWING SCIENCE QUESTIONS (the topic is circuit symbols and equations):
1. How much charge flows through a speaker if it is on for 20 minutes and has a current of 10A?
2. 500 coulombs of charge flow through a bulb for 25 seconds. Calculate the current trough the bulb.
3. 12A of current and 984C of charge flow through a kettle. How long was the kettle switched on for?
4. A laptop is switched on for 5 hours. It has a current flowing through it of 12A. What is the total amount of charge that flowed through the laptop?
5. An ipad is left in standby mode for 3 hours. During this time, 2.16C of charge flowed through the ipad. How much current flowed through the ipad?
6. A small LED light as 200mA of current flowing through it and a charge flow of 150C. How many minutes and seconds was the light switched on for?
genuine answers please, don't waste answer slots if you don't actually have an answer, it's rather irritating x
1) I=Q/T then Q= I ×T 10* ( 20*60) = 10 (120) therefore the answer is 1200C
2) I= Q/T that is 500/ 25 and the answer is 20A
what does it mean if you score 50% in the energy catogory of the 16 personalities test ?