Which of the following is defined as a force that pushes and pulls the current through the circuit? Group of answer choices D) resistance B) electricity A) current C) voltage
Answer:
C voltage
Explanation:
Voltage is the change in electric potential so basically current flows from high potential to low potential due to voltage.
An object is attached to a spring having a spring constant of k and spring is pinned from its one end to the wall. By neglecting the friction, the mass is released by pulling up along the x-axis from the its equilibrium position. a) By using Newton's laws, find the equation of motion and the oscillation frequency. b) For the mass-spring system, obtain the Lagrangian function and then write the equation of motion. c) For the mass-spring system, obtain the Hamilton function.
Equation of motion: To find the equation of motion and the oscillation frequency of a mass-spring system, we'll use Newton's second law of motion.
Force (F) = mass (m) × acceleration
F = ma
The force acting on a spring is given by Hooke's law:
F = -k x
where k is the spring constant and x is the displacement from the equilibrium position.
Thus, combining these two equations gives us the following equation of motion for a mass-spring system:
ma = -k x
Rearranging this, we get:
m(d²x/dt²) + k x = 0
This is the differential equation of motion of the mass-spring system.
Oscillation frequency:
The oscillation frequency can be calculated using the equation:
f = (1/2π) √(k/m)
where f is the frequency, k is the spring constant, and m is the mass.
Lagrange function:
The Lagrange function for a mass-spring system can be written as:
L = T - VL
is the difference between the kinetic energy (T) and potential energy (V) of the system.
The kinetic energy of the system is given by:
T = (1/2) mv²where m is the mass and v is the velocity.
The potential energy of the system is given by:
V = (1/2) kx²
where k is the spring constant and x is the displacement from the equilibrium position.
L = (1/2) mv² - (1/2) kx²
Equation of motion:
Using the Euler-Lagrange equation, the equation of motion for a mass-spring system can be derived.
It is given by:
d/dt (∂ L/∂v) - ∂L/∂x = 0
Substituting the values from the Lagrange function:
L = (1/2) mv² - (1/2) kx²∂L/∂v = m v ∂L /∂x = -k x.
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Determine the separation distance between two balloons with charges of +3.6*10^-8 C and -3.2*10^-8 C. They generate an electrical force of -2.2*10^-2 between them.
Answer:
0.0217 m
Explanation:
Ftom the question,
Applying Coulomb's law
F = kqq'/r²............... Equation 1
Where F = Electric Force, q and q' = First and second charge respectively, r = distance between the charges, k = coulomb's constant.
make r the subeject of the equation
r = √[(kqq')/F]............. Equation 2
Given: q = +3.6×10⁻⁸ C, q' = -3.2×10⁻⁸ C, F = -2.2×10⁻² N
Constant: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation
r = √(+3.6×10⁻⁸×-3.2×10⁻⁸×8.98×10⁹/-2.2×10⁻²)
r = √(-103.4489×10⁻⁷/-2.2×10⁻²)
r = √(47.02×10⁻⁵)
r = 21.68×10⁻³
r ≈ 21.7×10⁻³ m.
r ≈ 0.0217 m
Hence the seperation between the two balloons is 0.0217 m
What is the upper limit to the mass of a white dwarf? there is no upper limit. there is an upper limit, but we do not yet know what it is. 1.4 solar masses 1 solar mass 2 solar masses
Answer:
Around \(1.4\) solar mass.
Explanation:
In a white dwarf, electron degeneracy prevents the star from collapsing into itself. However, if the mass of the star exceeds the Chandrasekhar Limit, gravity would overcome electron degeneracy and star would collapse further.
The value of the Chandrasekhar Limit is approximately \(1.4\; M_{\odot}\) (\(1.4\) times the mass of the sun.) While this mass is the maximum possible mass of a stable white dwarf, the original mass of the star that formed this white dwarf tends to be much greater.
what is actually located at the event horizon of a black hole, to define this entity?
The event horizon of a black hole is the point of no return where the gravitational pull is so strong that not even light can escape. It is a boundary surrounding the black hole where the escape velocity exceeds the speed of light. At the event horizon, time and space are so distorted that the laws of physics as we know them cease to exist.
The exact nature of what lies beyond the event horizon is still a mystery as nothing can be observed beyond it. However, it is believed that all matter and energy that falls into the black hole accumulates at its center, known as the singularity.
The singularity is a point of infinite density and zero volume where the laws of physics break down completely, making it one of the most fascinating and mysterious entities in the universe.
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Question 10 of 10
What is density?
A. The net energy transferred between two objects
B. A measure of mass per unit volume
OC. The force exerted on an area
OD. A measure of the movement of molecules
Answer:
B. A measure of mass per unit volume
Explanation:
trust me
Answer:ITS C I PASSED THE TEST
Explanation:I DID THE PLATO
The distribution of the dark matter in a spiral galaxy is
A) approximately spherical and about the same size as the galaxy halo.
B) approximately spherical and about ten times the size of the galaxy halo.
C) flattened in a disk and about the same size as the stellar disk.
D) flattened in a disk but about ten times larger than the stellar disk.
E) predominantly concentrated in the spiral arms.
The distribution of the dark matter in a spiral galaxy is
A) approximately spherical and about the same size as the galaxy halo.B) 10 times larger than the galaxy halo and roughly spherical.C) compressed into a disk that is roughly the size of the star disk.D) a disk that was flattened but was ten times bigger than the star disk.E) predominantly concentrated in the spiral arms.The dark matter in a spiral galaxy is distributed in flattened disk and approximately ten times larger than the stellar disk. The presence of dark matter in the Universe has long been established, and it has been found to play an important role in the evolution of the Universe. Dark matter is a type of matter that is thought to make up approximately 85% of the Universe's total mass.
It is thought that it exists in the form of massive particles that do not interact with light or any other kind of electromagnetic radiation, making it invisible to telescopes. Scientists believe that dark matter plays a key role in the formation of galaxies and other large-scale structures in the Universe. All options are correct.
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Asky wave is incident on the ionosphere at an angle of 60°. The electron density of this ionosphere layer is N = 24.536 × 10¹¹ electrons/m³
a. For the point of reflection, determine the refractive index of the ionospheric layer. (3 Marks)
b. Identify the critical frequency for the communication link. (2 Marks)
c. Determine the maximum usable frequency (2 Marks)
d. Give reasons why the transmissions would fail the following frequencies if the frequencies were 10 MHz and 30 MHz respectively. (4 Marks)
e. The lonosphere bends high frequency radio waves towards Earth. Discuss this bending phenomenon.
We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)
(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.
The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.
Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).
(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).
(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.
(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.
(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.
As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.
This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.
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An arrow is shot horizontally with a speed of 20 m/s from the top of a tower 60 m high. The time to reach the ground will be -----------------.
Answer:
3
Explanation:
You will do 60÷20=30
This is the answer and please follow me
What is the range of an arrow shot horizontally at 85.3 m/s if it is initially 1.50 m above the ground?
range of arrow =
Answer:
47.2m
Explanation:
A student drops a ball off the top of building and records that the ball takes 2.55s to reach the ground. Determine all unknowns and answer the following questions. Neglect drag.
The unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
The given parameter;
time of motion of the ball, t = 2.55 sThe equations that model the motion of the ball is given as follows;
\(h = v_0_y + \frac{1}{2} gt^2\)
\(v_f = v_0_y + gt\)
All the unknown variables in the equations include;
\(v_0_y\) is the initial vertical velocity of the ball, = 0g is the acceleration due to gravity = 9.8 m/s²h is the vertical distance traveled by the ball = ?\(v_f\) is the final velocity of the ball = ?The vertical distance traveled by the ball is calculated as follows;
\(h = \frac{1}{2} gt^2\\\\h = 0.5 \times 9.8 \times 2.55^2\\\\h = 31.86 \ m\)
The final velocity of the ball is calculated as follows;
\(v_f = 0 + 9.8(2.55)\\\\v_f = 25 \ m/s\)
Thus, the unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
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Newton's first law of motion is also called the law of
pls help
Answer:
looks like law of inertia
Explanation:
Answer:
The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. Newton's first law of motion is often stated as. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
NEED HELP WITHIN THE NEXT 10 MIN! WILL MARK BRAINLIEST
For Part 3, describe the motion of the ball as it moves from the top of the ramp and comes to rest against the block. Explain how the motion changes in terms of the velocity, distance, acceleration, and force that you measured. Use your data and Newton’s laws to calculate these values and explain the situation. Include the tables you used to calculate average initial velocity and average displacement. Also show your work for your calculations of acceleration and net force
The motion of the ball as it moves from the top of the ramp and comes to rest against the block can be described as follows:
Velocity: The initial velocity of the ball as it is released from the top of the ramp can be calculated by using the kinematic equation v_f = v_i + at, where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time.
Distance: The distance traveled by the ball as it moves from the top of the ramp to the point where it comes to rest against the block can be calculated using the kinematic equation d = v_i*t + (1/2)at^2.
Acceleration: The acceleration of the ball can be calculated by using the formula a = (v_f - v_i) / t, where v_f is the final velocity, v_i is the initial velocity, and t is the time.
Force: The net force acting on the ball can be calculated using Newton's second law of motion, F = ma, where F is the net force, m is the mass of the ball, and a is the acceleration.
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Two measurments that are the same as each other are called_____?
What are they called???
Precision refers to the closeness of two or more measurements to each other. Using the example above, if you weigh a given substance five times, and get 3.2 kg each time, then your measurement is very precise. Precision is independent of accuracy.
A block of mass M is placed on a semicircular track and released from rest at point P, which is at vertical height H1 above the track's lowest point. The surfaces of the track and block are considered to be rough such that a coefficient of friction exists between the track and the block. The block slides to a vertical height H2 on the other side of the track. How does H2 compare to H1?
Therefore, H2 will be less than H1 because the initial potential energy possessed by the block at point P will be converted to kinetic energy and some energy will be dissipated as heat due to friction. So, the final vertical height of the block on the other side of the track will be less than the initial vertical height from where it was released.
The block of mass M placed on a semicircular track and released from rest at point P, which is at vertical height H1 above the track's lowest point, will slide on the track to the other side. Due to the rough surface of both the track and the block, a coefficient of friction exists between them. When the block reaches the other side of the track, it will come to rest at a vertical height H2.
The amount of energy possessed by the block at the beginning of the slide is equal to its potential energy at point P, which is Mgh1, where g is the acceleration due to gravity. As the block slides down the track, some of this energy is converted to kinetic energy, and some is dissipated as heat due to friction. By the time the block reaches the other side of the track, it will have lost some of its initial potential energy due to friction.
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Look at pic attached
Answer:
d=75 m
Explanation:
The horizontal launching speed is, v = 30 m/s
The vertical distance above the ground is= h m
The time of flight t= 2.5 s
The formula for free fall to apply here is:
h=1/2 *g * t² where g is acceleration due to gravity = -9.8 m/s² and t=2.5 s
Finding h, as ;
h= 1/2 * -9.8 * 2.5² = 30.63 m
Applying the formula for range (distance d)
R= v * t
R= 30 *2.5 =75 m
The range is 75 meters.
how wide is the central diffraction peak (the distance between the dark spots on either side) on a screen 2.30 m behind a 0.0348-mm-wide slit illuminated by 558-nm light?
The width of the central diffraction peak in Young's double-slit experiment can be determined using the formula:
w = (λ * D) / d
Where:
w is the width of the central diffraction peak,
λ is the wavelength of light (558 nm or 558 × 10^(-9) m),
D is the distance between the slit and the screen (2.30 m), and
d is the width of the slit (0.0348 mm or 0.0348 × 10^(-3) m).
Plugging in the given values, we get:
w = (558 × 10^(-9) m * 2.30 m) / (0.0348 × 10^(-3) m)
Calculating the result:
w ≈ 0.0368 m
Converting to millimeters:
w ≈ 36.8 mm
Therefore, the width of the central diffraction peak, or the distance between the dark spots on either side, is approximately 36.8 mm.
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Particles q1 = -20.5 UC, q2 = -9.30 uC, and q3 = -31.6.0 uC are in a line. Particles q, and q2 are separated by 0.980 m and particles q2 and q3 are separated by 0.750 m. What is the net force on particle q2?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
The net force on particle q2 can be calculated by finding the net electric force acting on it. The net electric force acting on a particle is the vector sum of the forces exerted by all the other charges on it.
The electric force between two charges q1 and q2 is given by Coulomb's law: F = k * (q1 * q2)/r^2, where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.
The force on particle q2 due to q1 will be:
F1 = k * (q1 * q2) / (0.980m)^2
The force on particle q2 due to q3 will be:
F2 = k * (q2 * q3) / (0.750m)^2
The net force acting on q2 will be the vector sum of F1 and F2.
Keep in mind, q1 and q3 have opposite charges, so they attract each other, while q2 has the same charge as q1, so they repel each other.
Note: The unit of charge is Coulomb (C), but in this problem you are given the charges in microCoulomb (uC) so you need to convert it to Coulomb.
what is the power of 600 joules of work done in 4 seconds?responses 150 watts 150 watts 240 watts 240 watts 600 watts 600 watts 2,400 watts
150 Watts is the power of 600 J of work completed in 4 seconds.
The rate at which work is completed is referred to as power. It has the following mathematical expression:
\(Power = work/time\)
The power can be obtained using the above formula.
From the mentioned query, the following information was observed:
Work = 600 J
Time = 4 s
Power =?
\(Power = Work/Time \\Power = 600/4\)
power = 150 watts
Thus, 150 Watts are generated by 600 J of work completed in 4 seconds.
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If ocean water did not move it would be hot in the _ region and frigid in the _ region
If ocean water did not move, it would be hot in the equatorial region and frigid in the polar regions.
Ocean currents are responsible for redistributing heat around the planet. Without these currents, the equatorial region would receive more sunlight and heat than it loses, resulting in an accumulation of heat in the water. On the other hand, the polar regions would lose more heat than they receive, resulting in frigid temperatures.
The rotation of the Earth also influences the movement of ocean water through the Coriolis effect. Without this effect, ocean currents would be less predictable, and their impact on climate and temperature distribution would be more severe. Therefore, ocean currents play a crucial role in regulating Earth's climate, and their disruption could have significant consequences for both marine life and global weather patterns.
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All circular motions are usually periodic but all periodic motions are not circular why
All periodic motions are not circular bcox they aren't similar to each other as u know the motion repeats the periodic table and also repeats itself of the tym perform the motion of the periodic...
Answer:
t is usually seen that all circular motions are usually periodic
Explanation:
but all periodic motions are not circular
this can be proved by an example for example when vehicles runs in uniform speed of motion then its speed is called periodic motion
where is his speed might not be called circular motion
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the total energy of a system is 300j. if the potential energy is 40j what is the kinetic energy if the object started 300m above the ground?
Answer:
43.3 m/s.
Explanation:
Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:
Total energy = Potential energy + Kinetic energy
Kinetic energy = Total energy - Potential energy
Kinetic energy = 300 J - 40 J = 260 J
However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:
Potential energy = mgh
40 J = m(9.81 m/s^2)(300 m)
m = 0.137 kg
Now we can use the kinetic energy to find the velocity:
Kinetic energy = (1/2)mv^2
260 J = (1/2)(0.137 kg)v^2
v^2 = (2*260 J) / 0.137 kg
v = 43.3 m/s (rounded to one decimal place)
Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.
If a vehicle is not equipped with Daytime Running Lights (DRL), it is recommended that drivers turn on the low beams. The reason for turning them on:
Turning on the low beams is recommended if a vehicle is not equipped with Daytime Running Lights (DRL) to enhance visibility and improve safety.
When a vehicle lacks DRL, turning on the low beams during daytime hours helps increase visibility to other road users. Low beams emit a brighter light compared to parking lights or the standard daytime lights, making the vehicle more noticeable. This is particularly important in conditions where visibility is reduced, such as during bad weather, fog, or low-light situations. By activating the low beams, drivers can ensure that their vehicle is easily seen by other drivers, reducing the risk of accidents and improving overall road safety.
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Turning on the low beams is recommended if a vehicle is not equipped with Daytime Running Lights (DRL) to enhance visibility and improve safety.
When a vehicle lacks DRL, turning on the low beams during daytime hours helps increase visibility to other road users. Low beams emit a brighter light compared to parking lights or the standard daytime lights, making the vehicle more noticeable. This is particularly important in conditions where visibility is reduced, such as during bad weather, fog, or low-light situations. By activating the low beams, drivers can ensure that their vehicle is easily seen by other drivers, reducing the risk of accidents and improving overall road safety.
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Part 1: How many "pathways" are in this circuit?
Part 2: Therefore, is this a series or parallel circuit?
Part 1: Zero pathways
Part 1: One pathway
Part 1: Two pathways
Part 1: Three pathways
Part 1: Four pathways
Part 1: Five pathways
Part 2: Series circuit
Part 2: Parallel circuit
Part 1: The number of pathways in a circuit determines the possible routes for electric current to flow.
There are maximum of five pathways in this circuit, depending on its complexity and the arrangement of components.
Part 2: Determining whether the circuit is series or parallel requires more information.
In a series circuit, components are connected in a single path, and the current flows through each component sequentially.
If the circuit has only one pathway (zero or one pathway), it suggests a series circuit.
However, if the circuit has multiple pathways (two or more pathways), it indicates a parallel circuit.
To conclusively determine the circuit's nature, we need to analyze the circuit diagram or obtain additional details regarding the component connections and their interactions.
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Given that R is dominant trait for round and r is a recessive trait for wrinkled, the cross in parental genotypes of Rr and Rr will have ______ of its phenotypes.
¾ round and ¼ wrinkled
½ round and ½ wrinkled
¼ round and ¾ wrinkled
All round
The cross in parental genotypes of Rr and Rr will have ¾ round and ¼ wrinkled of its phenotypes. The correct option is A.
What is phenotype?The set of qualities or characteristics that can be observed in an organism are known as its phenotype in genetics.
The word includes an organism's anatomy, developmental processes, physiological and biochemical characteristics, behaviour, and the outcomes of behaviour.
In the given scenario, the alleles that will be formed are RR, Rr, and rr. The ratio of this will be 3:1.
It means, there will be 3 round phenotype out of 4 and one will be wrinkled.
Thus, the correct option is A.
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What units are used to measure mass?
Answer:
I think kilogram.
Explanation:
If you refer to science book you can find.
Does water go down the drain counterclockwise in the northern hemisphere and clockwise in the southern hemisphere?
The direction in which water flows down a drain is not affected by whether you are in the northern or southern hemisphere.
What is the movement of water in hemispheres?
The idea that water drains counterclockwise in the northern hemisphere and clockwise in the southern hemisphere is a popular myth.
The direction in which water flows down a drain is actually determined by a combination of factors such as the shape of the basin or container, the location of the drain, and any other forces acting on the water, such as the Coriolis force.
The Coriolis force is a real phenomenon that affects the movement of objects in the atmosphere and oceans, but its effect on the flow of water down a drain is generally too weak to be noticeable. In fact, the direction of rotation of the Earth has very little impact on the direction in which water flows down a drain.
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A closed container with a volume of 6.00 l holds 10.0 g of liquid helium at 25.0 k and enough air to fill the rest of its volume at a pressure of 1.00 atm. the helium then evaporates and the container warms to room temperature (293 k). what is the final pressure inside the container?
According to the given statement the final pressure inside the container P = 1015 atm.
How is the final partial pressure calculated?Partial pressures can be calculated in one of two ways: To determine the individual pressure of each gas in a mixture, use PV = nRT. Calculate the proportion of pressure from the total pressure that may be assigned to each individual gas using the mole fraction of each gas.
Briefing:You use the ideal-gas law:
PV = nRT
We are aware of V (volume), R (the ideal gas law constant, which, when applied to L and moles, is 8.314), and T. (293 K)
There are 10 g of helium, we divide by helium's molar mass in order to find the amount of moles.
10 g / (4.00 g/mol) = 2.5 moles of Helium
Since we now know all the variables, we can use the ideal-gas law to find the pressure. We'll take the equation and solve for P:
PV = nRT
P = (nRT)/(V)
P = (2.5)(8.314)(293)/(6)
P = 1015 atm
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DO boys cheat more than girls?
Answer:
I'm not sure.
Explanation:
Look up the statistics
Answer: honestly girls cheat more than guys, its statically proven that females cheat more than guys its because they dont believe in value in a relationship
Explanation:
a boy wishes to cross a river in the shortest possible time, without necessarily landing directly across from his starting point. he can row at 2 m/s in still water and the river is flowing at 1 m/s. at what angle θ should he point the bow (front) of his boat?
He should bow his boat at 90° to cross the river.
While the water will push him in side ways, it will not affect the time it takes to actually cross the river.
Hence, the correct answer is 90°.
Factors that have an effect on the velocity of a river consist of the slope gradient, the roughness of the channel, and tides. Rivers generally tend to drift from a higher elevation to a lower elevation. The gradient is the drop of the elevation of a river.
Reverberation is the time taken for the sound to fall beneath the minimal audibility measured from the immediate whilst the supply stopped sounding. Therefore if the reverberation time will become too massive it produces an echo.
Due to velocity of water drift in river, a person either swimming or floating stationary within the river reports a pushing force alongside the flow direction.
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