what is Newton's second law?
F=mXa
a=F/m
m=F/a
All of the above

Answers

Answer 1

It should be the first one, F= mXa (F = m times a).


Related Questions

a car is traveling along a circular track with a radius of 100 meters. the car completes one full lap around the track in 40 seconds. what is the car's speed in meters per second?

Answers

A car is traveling along a circular track with a radius of 100 meters and the car completes one full lap around the track in 40 seconds. The car's speed is 15.7 meters per second.

To find the car's speed, first, we need to determine the circumference of the circular track, which is given by the formula C = 2 * π * r, where C is the circumference, π is approximately 3.14, and r is the radius.
1. Plug in the given radius: C = 2 * π * 100 meters
2. Calculate the circumference: C ≈ 2 * 3.14 * 100 meters = 628 meters
3. Next, we need to convert the time taken to complete one lap into seconds: 40 seconds
4. Finally, we can calculate the speed by dividing the circumference by the time taken: Speed = C / time = 628 meters / 40 seconds = 15.7 meters per second.

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What is the mass of an object that has a potential energy of 57J and is 10m above the ground?

Answers

PE = mass times gravity times height

57 = mass (9.8) (10)

57 = mass (98)

57/98 = mass

0.5816 = mass

In lenses,the ray that strikes in parallel,emerging in such way that it’s prolongation passes through the focus, is called:A:divergent rayb:converging rayc:parallel rayd:light ray

Answers

First, let's draw a lens and a ray that has the given characteristics:

If the ray strikes in parallel and then diverges from the axis of the lens, that means we have a divergent ray.

Therefore the correct option is A.

In lenses,the ray that strikes in parallel,emerging in such way that its prolongation passes through

What type of stored energy is transferred by burning fuels

Answers

The type of stored energy that is transferred by burning fuels is chemical energy. Chemical energy is a form of potential energy that is stored within the chemical bonds of substances, such as the molecules of fuels. When fuels undergo combustion, such as the burning of gasoline, the chemical bonds within the fuel molecules are broken, and new bonds are formed.

During this chemical reaction, energy is released in the form of heat and light. The released energy is a result of the conversion of the potential energy stored in the chemical bonds of the fuel into other forms of energy, primarily thermal energy. This thermal energy can then be harnessed and used for various purposes, such as heating, generating electricity, or powering engines.

The process of burning fuels involves the oxidation of the fuel molecules, where they react with oxygen from the air. This reaction releases the stored chemical energy and converts it into thermal energy. The combustion process is exothermic, meaning it releases energy in the form of heat.

It's important to note that burning fuels also produces other byproducts, such as carbon dioxide and water vapor. These byproducts result from the chemical reactions occurring during combustion but do not directly represent the transfer of stored energy. The primary transfer of stored energy in the burning of fuels occurs through the conversion of chemical energy to thermal energy.

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Nuclear engineer Meena Mutyala argues that nuclear power is an environmentally _____ technology, operating with essentially no emissions.
A hostile
B culpable
C inimical
D benign
E capricious
F innocuous

Answers

Nuclear engineer Meena Mutyala argues that nuclear power is an environmentally benign technology, operating with essentially no emissions.

How does nuclear power function and what is it?

The fission of uranium nuclei, also known as nuclear fusion, is the source of nuclear energy. As a result, heat is produced, which turns into steam, which then turns into energy in a turbine generator. Nuclear energy facilities don't release greenhouse gas emissions because they don't burn fuel.

New applications for nuclear electricity or material are being studied by nuclear engineers. To help in the development of preventive steps, they investigate nuclear accidents and analyze the data. Some examine the viability of various approaches to using, controlling, and recovering nuclear material.

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HEY GUYS IS THIS TRUE OR FALSE????????

HEY GUYS IS THIS TRUE OR FALSE????????

Answers

True it is true so put true

curls provide maximum lift or volume, since the curl is placed very high on its base. a. full-base b. half-base c. volume-base d. thermal

Answers

Curls provide maximum lift or volume, since the curl is placed very high on its base  is full-base .So option a is correct.

Full-base curls are placed directly on their base, which is the section of hair that the curl is formed on. This placement creates maximum lift and volume, since the curl is placed very high on its base. Half-base curls are placed halfway on their base, which creates less lift and volume than full-base curls. Volume-base curls are placed off their base, which creates the least amount of lift and volume. Thermal curls are created with a curling iron, and the amount of lift and volume they create depends on the size of the curling iron and how it is used.Therefore option a is correct.

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an object is located inside the focal point of a concave mirror. will the image of the objectr be nearer or farther from the observer than the object tiself? explain

Answers

When an object is placed inside the focal point of a concave mirror, the image formed will be virtual, upright, and magnified.

This occurs because the light rays reflecting off the mirror diverge and never intersect on the real side of the mirror. Instead, they appear to converge on the virtual side, behind the mirror.

As a result, the image of the object will be farther from the observer than the object itself. The observer will see the image behind the mirror, which is not the actual position of the object, making it appear more distant than it truly is.

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Two blocks are attached by a compressed spring and are initialky held by at rest on a frictionless surface. the blocks are then released simuntaniusly. if block 1 has four times the mass of block 2 what is the acceleration of block 1 comoared to block 2

Answers

Answer: move with constant vilocity

Explanation:

If a 30 kg child is swinging on a swing, how much higher above the ground must she be pushed to increase her PE by 600 J?

Answers

Answer:

600-30=570, 570+30=600. The child needs to be pushed 570m away from the ground

if the resulting potential difference between the two conductors is 420 v, what is the capacitance, in nanofarads, of the cable?

Answers

The  the capacitance of the cable is 18 nF, when the resulting potential difference between the two conductors is 420 V.

The capacitance of a cable is 125 nF when the resulting potential difference between the two conductors is 60 V. If the resulting potential difference between the two conductors is 420 V, what is the capacitance, in nanofarads, of the cable

Given:

Capacitance, C = 125 nF

Initial potential difference, V1 = 60 V

Final potential difference, V2 = 420 V

To find:

The capacitance of the cable is given by the formula:

Capacitance, C = (Charge, Q) / (Potential difference, V)

Or,

Charge, Q = C × V

We know that,

Charge, Q1 = C × V1

Charge, Q2 = C × V2

If we divide Q2 by Q1, then we get:

C × V2 / C × V1

= Q2 / Q1

Or,

C × V2 / C × V1 = (Final charge) / (Initial charge)

From the principle of conservation of charge, we know that:

Charge cannot be created or destroyed; it can only be transferred from one place to another.

Therefore, the initial charge and final charge are the same.

So, we can say that:

Charge, Q2 = Charge, Q1

Hence, C × V2 = C × V1

Or,

C = V1 / V2 × C1

Substituting the values, we get:

C = 60 V / 420 V × 125nF

= 18 nF (approximately)

Therefore, the capacitance of the cable is 18 nF, when the resulting potential difference between the two conductors is 420 V.

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a 2.0-kg mass is attached to the end of a horizontal spring of spring constant 50 n/m and set into simple harmonic motion with an amplitude of 0.10 m. what is the total mechanical energy of this system?

Answers

Answer:

0.25 J

Explanation:

Select two of Earth's spheres and explain how they interact with each other.
atmosphere, biosphere, cryosphere, geosphere and hydrosphere
HELPPPPPPPP!!!!!

Answers

Answer and Explanation: The geosphere interacts with the cryosphere when glaciers and sheets of ice from the cryosphere erode the rocks located on the geosphere. This happens as ice passes over the land and carries eroded rocks to new locations. The cryosphere can also cause soil to become icy and take hold of greenhouse gases from the atmosphere. The geosphere is the part of the Earth that has rocks, minerals, sand, and lava. The cryosphere has frozen water, ice, and glaciers. The cryosphere also interacts frequently with the hydrosphere because it draws water from the hydrosphere and freezes it during cold temperatures. Warmer temperatures cause the cryosphere to melt and release water back to the hydrosphere.

procedure C, describe how you thought the time to drop the pen from 1.0 meters high would
compare to dropping from 50.0 meters? Do you think it would take 50 times longer to drop from
50 meters? Explain.

Answers

1.428 s is the calculated time.

distances relative to the earthly acceleration do not take any initial distance or initial speed if you set the origin of your referential on the origin of your movement and assume that your ball has no initial speed as it is. The most amazing and unexpected truth about falling things is that, in a given location, all items fall toward the center of the Earth with the same constant acceleration, regardless of their mass, if air resistance and friction are low.

So here is the most straightforward formula for this:

+(1/2) *(9.81 m/s^ (2)) *t^ (2) = +10 m.

The result is that t = √ (20 m/ (9.81 m/s (2)))

=√ (2.039 s2)

distances relative to the earthly acceleration do not take any initial distance or initial speed if you set the origin of your referential on the origin of your movement and assume that your ball has no initial speed as it is. The most amazing and unexpected truth about falling things is that, in a given location, all items fall toward the center of the Earth with the same constant acceleration, regardless of their mass, if air resistance and friction are low.

vertical (and only) axis of a drawing must be pointed downward.

So here is the most straightforward formula for this:

+(1/2)*(9.81 m/s^(2))*t^(2) = +10 m.

The result is that t = √ (20 m/(9.81 m/s(2)))

= √(2.039 s2)

=1.428 s.

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During the push-up, the hips should never hit the ground and should move 1 point
in time with the shoulders. *
True
False
Other:

Answers

Hahahahahahahahahha true

1. Think of an engineering problem where having an object with a high (k) value would be a benefit?

2. Think of an engineering problem where having an object with a low (k) value would be a benefit?

Answers

An example of a project where an object with a high (k) value would be a benefit is one that has to do with the design of a rocket engine. Metals that have very high thermal conductivity are useful for building rocket engines. This is because of the amount of energy/heat that is required to be combusted by these parts to achieve a break from the earth's force field of gravity.

While engineering problems where having an object with a low (k) value would be a benefit is those that have to do with buildings. Buildings are made from concrete and brisk with have low thermal conductivity hence low

What does (k) Value mean?

A k-value (also known as a k-factor or lambda value) is a measure of a material's thermal conductivity, or how quickly heat moves through it. It is a basic quality that is independent of material quantities.

Thermal conductivities of different building materials may be compared using k-values. This is often useful in determining the possibility of heat transmission between the inside and exterior of a structure.

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is the sky made of cheese

Answers

Answer:

No.

Explanation:

The atmosphere is made mostly of gases. Mainly nitrogen and oxygen. That's a nice suggestion though.

Describe the barriers that prevent energy efficiency reaching its potential.

Answers

There are several barriers that prevent energy efficiency from reaching its full potential. These barriers include upfront costs, lack of information and awareness, split incentives, market failures, and policy and regulatory challenges.

1. Upfront Costs: Investing in energy-efficient technologies and systems often requires a significant upfront investment. Many individuals and businesses may be hesitant to incur these costs, especially if they have limited financial resources or short-term perspectives.

2. Lack of Information and Awareness: Limited knowledge about energy-efficient practices and technologies can hinder adoption. People may not be aware of the potential energy savings or the available options to improve efficiency.

3. Split Incentives: In situations where landlords own the buildings but tenants pay the energy bills, there is a split incentive problem. Landlords may have little motivation to invest in energy efficiency measures since they don't directly benefit from the reduced energy costs.

4. Market Failures: Market failures, such as information asymmetry and externalities, can impede energy efficiency. For example, consumers may not have access to accurate information about the energy efficiency of products or may not consider the long-term cost savings.

5. Policy and Regulatory Challenges: Inconsistent or inadequate policies and regulations can hinder energy efficiency efforts. Insufficient incentives, lack of enforcement, and complicated procedures for accessing incentives or grants can discourage investment in energy efficiency.

Overcoming these barriers requires a multi-faceted approach involving public awareness campaigns, financial incentives, targeted policies, and streamlined regulations. Governments, businesses, and individuals need to collaborate to address these barriers and unlock the full potential of energy efficiency, leading to significant energy savings and environmental benefits.

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A rope pulls a 32.5-kg block upward with a constant acceleration of 5.21 meters per second squared. What is the tension in the rope? (a) 150 N(b) 488 N(c) 624 N(d) 748 N

A rope pulls a 32.5-kg block upward with a constant acceleration of 5.21 meters per second squared. What

Answers

Free body diagram:

The free body equation is given as,

\(T-mg=ma\)

Therefore, tension in the rope T is given as,

\(T=m(g+a)\)

Subsriruring all known values,

\(\begin{gathered} T=32.5\times(9.81+5.21) \\ =488.15\text{ N} \end{gathered}\)

Therefore, the tension in the rope is 488.15 N. Hence, option (b); 488 N is the best choice.

A rope pulls a 32.5-kg block upward with a constant acceleration of 5.21 meters per second squared. What

17. A spinning disc rotating at 130 rev/min slows and stops 31 s later. How many revolutions did the disc make during this time?
A) 34
B) 67
C) 8.4
D) 17
E) 4.2

Answers

The number of revolutions the spinning disc makes during the given time is 34 revolutions .

To find the number of revolutions the spinning disc makes during the given time, we need to first find the average angular velocity and then multiply it by the time.
Step 1: Calculate the initial angular velocity (ω₁).
Given that the spinning disc rotates at 130 revolutions per minute (rev/min), we first convert it to revolutions per second (rev/s) by dividing by 60:
ω₁ = 130 rev/min / 60 = 2.167 rev/s
Step 2: Calculate the final angular velocity (ω₂).
Since the disc stops, its final angular velocity is 0 rev/s.
Step 3: Calculate the average angular velocity (ω_avg).
The average angular velocity is the mean of the initial and final angular velocities:
ω_avg = (ω₁ + ω₂) / 2 = (2.167 + 0) / 2 = 1.0835 rev/s
Step 4: Multiply the average angular velocity by time to find the number of revolutions.
The given time is 31 seconds:
Number of revolutions = ω_avg × time = 1.0835 rev/s × 31 s ≈ 33.6 revolutions
The closest answer among the given choices is A) 34.

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a car reaches 80 kilometers per hour, then suddenly crashes into the concrete wall

Answers

Answer:

what is the question ? That is only a statement

I am really confused can someone please help and explain.

I am really confused can someone please help and explain.

Answers

B

They store the radioactive waste in pools of water until it is no longer dangerous. It is then transferred to a dry cask. :))

Like linear momentum, conservation of angular momentum is a fundamental principle which can be used to solve plyysical problems. (select the best answer) A. The sum of the external forces is not zero. B. Acted on by an external force. C. The sum of the external torques is not zero.
D. Acted on by an external torques.

Answers

Similar to the conserve of linear momentum, the preservation of rotary momentum is a basic idea that may be utilized to address physical issues. Option C is Correct.

"For a spinning system," it says, "there is no change in the angular momentum of the object until and unless an external torque is applied to it." When an object's mass (m) and velocity (v) are multiplied, the result is linear momentum (p): p = m x v.

The definition of the angle momentum (L), with some simplification, is the object's separation from the axis of rotation times a unit of linear momentum: L is equal to r*p or mvr. conservation of linear momentum is a fundamental physical principle that governs the concept of momentum. Option C is Correct.

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True or false. The sternal region is located medially from the thoracic region.

Answers

Answer:

hope it helps...

Explanation:

The answer is true

A gun is fired with muzzle velocity 1099 feet per second at a target 4750 feet away. Find the minimum angle of elevation necessary to hit the target. Assume the initial height of the bullet is 0 feet, neglect air resistance, and give your answer in degrees.

Answers

A gun is fired with muzzle velocity 1099 feet per second at a target 4750 feet away. The minimum angle of elevation necessary to hit the target is approximately 15.2 degrees.

To find the minimum angle of elevation, we can use the equation for the horizontal range of a projectile. The horizontal range is the distance traveled by the bullet in the horizontal direction, which in this case is 4750 feet. The equation for the horizontal range is: R = (v^2 * sin(2θ)) / g

where R is the range, v is the muzzle velocity, θ is the angle of elevation, and g is the acceleration due to gravity.

Rearranging the equation to solve for θ, we have: θ = 0.5 * arcsin((R * g) / v^2). Plugging in the given values, we have: θ = 0.5 * arcsin((4750 * 32.2) / (1099^2))

Evaluating this expression, we find that the minimum angle of elevation necessary to hit the target is approximately 15.2 degrees. This means that the gun should be elevated at an angle of approximately 15.2 degrees above the horizontal in order to hit the target 4750 feet away.

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A 155-g baseball is incoming at a velocity of 25 m/s. The batter hits the ball as shown in
the image. The outgoing baseball has a velocity of 20 m/s at the angle shown.
What is the magnitudde of the impulse acting on the ball during the hit?
a. 2.68 kg-m/s.
b. 5.42 kg-m/s.
c. 6.05 kg-m/s.
d. 8.11 kg-m/s.

Answers

The magnitude of the impulse acting on the ball during the hit is:

|J| = |Δp| = 0.775 kg-m/s

What is Velocity?

Velocity is a vector quantity that describes the rate at which an object changes its position in a particular direction. It is defined as the displacement of an object per unit time and includes information about both the speed and direction of motion.

We can use the impulse-momentum theorem to solve this problem. The impulse acting on the ball during the hit is equal to the change in momentum of the ball.

The initial momentum of the ball is:

p1 = m1v1 = (0.155 kg)(25 m/s) = 3.875 kg-m/s

The final momentum of the ball is:

p2 = m2v2 = (0.155 kg)(20 m/s) = 3.1 kg-m/s

The change in momentum of the ball is:

Δp = p2 - p1 = 3.1 kg-m/s - 3.875 kg-m/s = -0.775 kg-m/s

The negative sign indicates that the direction of the impulse is opposite to the direction of the initial momentum.

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What is the relationship between frequency and wavelength?

Answers

Answer:

Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength.

Explanation:

please help its in science CER, 30 points

please help its in science CER, 30 points

Answers

Answer:We have seasons because the earth is tilted (wonky) as it makes its yearly journey around the sun. The Earth's axis is tilted at an angle of 23.5 degrees. This means that the Earth is always "pointing" to one side as it goes around the Sun.

Explanation:

got this from the internet

two balls are at the same height. One ball is dropped and the other initially moves horizontally, as shown in the figure above. After one second, which ball has fallen the greatest vertical distance?

Answers

Answer:

do you have a picture we can see?

a centrifuge in a biology laboratory rotates at an angular speed of 3,800 rev/min, clockwise (when viewed from above). when switched off, it rotates through 48.0 revolutions before coming to rest. assuming it is constant, what is the magnitude of angular acceleration (in rad/s2)?

Answers

The magnitude of the angular acceleration of the centrifuge is 3.78 rad/s^2.

Convert the angular speed from revolutions per minute (rpm) to radians per second (rad/s).

1 revolution = 2π radians

ω = 3800 rev/min * (2π rad/rev) / (60 s/min) = 398.11 rad/s

\(\theta=\omega i t + (1/2)\alpha t^2\)

where θ is the angular displacement, ω_i is the initial angular velocity, α angular acceleration, t time.

At the instant the centrifuge is switched off, its angular speed is 398.11 rad/s. Angular displacement is 48 revolutions * 2π radians/revolution = 301.59 radians.

\(\omega f = \omega i +\alpha t\)

\(0 = -398.11 + \alpha t\)

\(t = 398.11/\alpha\)

\(θ = \omega_i t + (1/2)\alpha t^2\)

\(301.59 = (-398.11)(398.11/\alpha) + (1/2)α(398.11/\alpha)^2\)

Simplifying this equation, we get:

\(301.59 = -398.11^2/\alpha + 398.11^2/2\alpha\)

Multiplying both sides by 2α and rearranging, we get:

\(\alpha = 2 * 398.11^2 / (301.59 + 398.11^2/\alpha)\)

Solving for α, we get:

\(\alpha = 3.78 rad/s^2\)

Therefore, the magnitude of the angular acceleration of the centrifuge is 3.78 rad/s^2.

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