“while parachuting” does this has effectWhile parachuting, a 65.0kg person experiences a downward acceleration of 2.70m/s^2. What is the downward force on the parachute from the person?

The rock was thrown upward with an initial velocity and it's displacement after one second is 19.5 m.

According to Newton's second law, an object's acceleration is determined by its mass and the net force that is acting on it. The body's acceleration is inversely related to its mass and directly proportional to the net force acting on it.

The displacement-time relation,

X(t) - x = vt -1/2 gt^2

X(t) = Position of object after time t

x = Initial position of object

v = Initial velocity = 24.5 m/s

g = Acceleration due to gravity = - 10.0 m/s2 (Downward)

t = time = 1 s

The displacement of rock after 1 s => X(t) - x => (24.5 x 1) - 1/2 ( 10 x 1 x 1)

                                                               => 19.5 m

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The height of the acorn above the ground before falling is 2.9 m.

The initial velocity of the acorn is calculated as follows;

s = ut + ¹/₂gt²

where;

1.87 = 0.311u   +   ¹/₂(9.8)(0.311²)

1.87 = 0.311u  +  0.474

0.311u = 1.396

u = ( 1.396 ) / ( 0.311 )

u = 4.489 m/s

The height the acorn falls before reaching the top velocity of 4.489 m/s is calculated as follows;

v² = u² + 2gh

where;

v² = 0 + 2gh

h = v² / 2g

h = ( 4.489² ) / ( 2 x 9.8 )

h = 1.03 m

The total height of the oak tree = 1.87 m + 1.03 m = 2.9 m

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The car will move at a constant speed once it is unleashed, as is assumed. Hence, there is no acceleration. Newton's second law states that a straight line along zero will appear on the graph if F=ma=m(0)=0, F=0.

Acceleration is the rate at which an object changes its velocity. It is a vector quantity, which means it has both magnitude and direction. The standard unit of acceleration is meters per second squared (m/s²).

Acceleration can be caused by forces such as gravity, friction, and electromagnetism. When a force acts on an object, it causes a change in the object's motion, resulting in acceleration.

The relationship between acceleration, velocity, and time is described by the equation a = (v_f - v_i) / t, where a is acceleration, v_f is final velocity, v_i is initial velocity, and t is time.

The effects of acceleration can be seen in everyday experiences, such as feeling pushed back into your seat when a car accelerates or feeling weightless during freefall. Understanding acceleration is important in fields such as physics, engineering, and transportation.

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Answer:

8. Dinitrogen trioxide:

\({ \sf{N_{2} O_{3}}}\)

9. Nitrogen:

\({ \sf{N}}\)

10. Lithium oxide:

\({ \sf{Li_{2}O}}\)

11. Phosphorus trifluoride:

\({ \sf{PF_{3} }}\)

12. Vanadium oxide:

\({ \sf{V_{2} O_{3} }}\)

13. Silicon tetrafluoride:

\({ \sf{SiF _{4}}}\)

14. Sodium phosphide:

\({ \sf{Na_{3} P}}\)

(a) The circuit diagram is in the image attached.

(b) The current flowing through the resistor is 0.003 A.

(c) The power dissipated by the resistor is  0.135 W.

(b) The current flowing through the resistor is calculated by applying Ohm's law as follows;

V = IR

I = V/R

where;

I = 45 V / 15,000Ω

I = 0.003 A

(c) The power dissipated by the resistor is calculated as follows;

P = IV

where;

P = 0.003 x 45 V

P = 0.135 W

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Answer:

There is net loss of gravitational energy .

Explanation:

When Xanaxa is on the ground , her potential energy is assumed to be zero . When she leaps to a height of 153 m , she gains gravitational energy . When she dives and reaches the surface , she loses potential energy and on reaching the ground her potential energy becomes zero . When she further goes down inside ground to a depth of 17.5 m , she loses potential energy further . Her potential energy becomes less than zero or negative .

Ultimately her potential energy changes from zero to negative in the whole process . So there is net loss of potential energy .

Melvina's potential energy is 54,880 Joules.

To calculate Melvina's potential energy, we need to use the formula for gravitational potential energy:

Potential energy = mass × gravitational acceleration × height

Potential energy is a measure of the energy an object possesses due to its position relative to other objects. In this case, Melvina's potential energy is a result of her height above the ground. As she stands on the ledge of the burning building, her potential energy is stored and can be converted into other forms of energy if she were to jump or fall. The potential energy will decrease as she descends, and it will be converted into kinetic energy (energy of motion).

Given that Melvina has a mass of 70 kg and the ledge is 80 m above the ground, we can substitute the values into the formula:

Potential energy = 70 kg × 9.8 m/s² × 80 m

Calculating this, we find:

Potential energy = 54,880 Joules

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Answer:

his type of shock is called inelastic

Explanation:

This exercise is for vehicle crashes, which corresponds to exercise is momentum conservation.

We must begin by defining a system formed by the two cars so that the forces during the crash have been intense and the moment is preserved.

Looking for the moments

initial. Before the crash

           p₀ = m₁ v₁₀

final. After the crash

           p_f = (m₁ + m₂) v

the conservation of the moment is written

           p₀ = p_f

           m₁ v₁₀ = (m₁ + m₂) v

This type of shock is called inelastic and has the characteristics that the kinetic energy is not conserved.

The resultant velocity of the boat is 7.5 km/h.

The resultant displacement of the boat is calculated as follows;

Sum of the vertical displacement of the boat is calculated as;

∑Fy = -24 km sin(50)  + 8 km sin(60)

∑Fy = -11.5 km

Sum of the horizontal displacement of the boat is calculated as;

∑Fx = -24 km cos(50)  - 8 km cos(60)

∑Fx = -19.4 km

The resultant displacement is calculated as follows;

d = √ (-11.5² + 19.4²)

d = 22.55 km

The resultant velocity of the boat is calculated as follows;

v = ( 22.55 km ) / ( 3 hrs )

v = 7.5 km/h

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Hello!

a)
For a car on an incline, we only have the normal force and force of gravity acting on the car.

The car is only experiencing a net force caused by the sine component of the force of gravity vector, which causes it to slide down the incline towards the center of the curve.

Or, as an equation:

\(F_{net} = Mgsin\phi\)

This net force produces a centripetal force. Recall the equation for centripetal force:
\(F_c = \frac{mv^2}{r}\)

In reference to the 15° angle of the incline, the cosine component of the centripetal force is equivalent to the sine component of the force due to gravity (both parallel to the incline). So:
\(F_c cos\phi = Mgsin\phi \\\\\frac{mv^2}{r}cos\phi = mgsin\phi\)

Cancel out 'm' and solve for 'v'.

\(\frac{v^2}{r}cos\phi = gsin\phi\\\\v^2 = gr \frac{sin\phi}{cos\phi}\\\\v = \sqrt{grtan\phi}\)

Plug in the given values and solve.

\(v = \sqrt{(9.8)(85)tan(15)} = \boxed{14.94 \frac{m}{s}}\)

b)
Begin by converting 20.0 km/h to m/s.

\(\frac{20 km}{hr} * \frac{1 hr}{3600 s} * \frac{1000m}{1 km} = 5.556 \frac{m}{s}\)

For this situation, we also have the force of friction present along the axis of the sine component of the force of gravity that contributes to the net force.

Recall the equation of kinetic friction:
\(F_f = \mu_k N\)

In this situation, we have the sine (vertical) component of the centripetal force as well as the cosine component of the force of gravity making up the normal force, so:
\(F_f = \mu_k (\frac{mv^2}{r}sin\phi + mgcos\phi)\)

If a curve is banked at a slower speed than appropriate, the car will tend to slide towards the center. Thus, this force of friction points up the incline, opposite to the force due to gravity. We can do another summation of forces like above.

\(\frac{mv^2}{r} cos\phi= mgsin\phi - \mu_k (\frac{mv^2}{r}sin\phi + mgcos\phi)\)

Cancel out 'm' and simplify the equation further to solve for μ.

\(\frac{v^2}{r} cos\phi= gsin\phi - \mu_k (\frac{v^2}{r}sin\phi + gcos\phi)\\\\\mu_k (\frac{v^2}{r}sin\phi + gcos\phi)= gsin\phi - \frac{v^2}{r} cos\phi\\\\\mu_k = \frac{gsin\phi - \frac{v^2}{r} cos\phi}{(\frac{v^2}{r}sin\phi + gcos\phi)}\)

Plug in values.

\(\mu_k = \frac{9.8sin(15) - \frac{5.556^2}{85} cos(15)}{\frac{5.556^2}{85}sin(15) + 9.8cos(15)} = \boxed{0.2286}\)

When the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.

Hooke's law states that force or load applied to elastic material is directly proportional to the extension produced in the material. This law can be written as;

F = kx

where;

The speed of the block increases with decreasing displacement of the bock. This is because the kinetic energy of the block is maximum at zero displacement and minimum at maximum displacement of the block.

Thus, when the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.

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The pathogen that immunization helps to prevent is virus.

To reduce the risk of atherosclerosis cut down on saturated fatty foods.

Immunization is defined as the prevention of pathogenic viral organisms from harming a living human host through the exposure of the host to an attenuated form of the virus to develop immunity prior to a future exposure.

Atherosclerosis is the deposition of fatty substances on the arterial wall leading to blocking of the blood vessels.

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Answer: ok, so there should be no speed at the 5th second but there was somehow it was the car fault

∞ω∞

The sum of the figures given is determined as 362,003.245 m.

The sum of the figures given in the question is calculated as follows;

134.5 cm = 1.345 m

= 1.9 m + 1.345 m + 3.62 × 10⁵ m

= 1.9 m + 1.345 m + 362,000 m

= 362,003.245 m

Thus, the sum of the figures given is determined as 362,003.245 m.

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Time of flight = 1.6 s

Horizontal distance = 64 m

Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.

For the given case,

h = vt + ¹/₂gt²

h = height of tower

v = initial velocity

t = time of flight

55 = 50sin30t + ¹/₂9.8t²

55 = 25t + 4.9t²

4.9t² + 25t - 55 = 0

t = 1.6 s

X = vₓt

X = horizontal distance

vₓ = horizontal velocity

t = time of flight

X =  (50 x cos30) x 1.6

X =  64 m

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When a typical comet in the Oort cloud is only 1 km in diameter, then the mass of the Oort cloud is changes to  4.18×10⁹ kg.

The mass of each comet int he Oort cloud is,

mass = density × Volume

volume of sphere = 4/3(π×r²) where, r = radius of the sphere

From the given,

diameter = 1 km

radius = Diameter / 2 = 1/2(D)

Volume of the comet = 4/3 (π×r²) = 4/3 (π× (1/2 (10)³)²)

                                   = 4/3×(π) ×(1/8×10⁶)

Mass = density  × volume, where density = 1000 kg/m³

         = 1000  × 4/3×(π) ×(1/8×10⁶)

        = 4.18 ×10⁹ kg

When the typical comet in the Oort cloud is only 12 km in diameter the mass of Oort cloud is 4.18×10⁹ kg.

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Explanation:

I think it's option a..

I think this is it!

Answer:

electromagnetic waves, physical contact

Explanation:

The sun transfers heat to earth through electromagnetic radiation. This method of heat transfer is evidence that direct contact is not necessary for heat to move from place to place.

Heat transfer is defined as the flow of heat or thermal energy from one point to another due to the temperature difference between the two points.

Here,

Due to the temperature difference between, heat transfer occurs between two points through various methods such as conduction, convection and radiation.

Conduction is the process of heat transfer through which heat is transferred between two objects that are in direct contact with each other. It can occur in solids, liquids and gases.

Convection is the process of heat transfer through which the heat is transferred by the movement of fluids. Air and water currents are the examples for it.

Radiation is the process of heat transfer in which the heat is transferred in the form of electromagnetic waves.

The heat energy from the sun reaches the earth through the phenomenon called electromagnetic radiation. Mainly infrared radiations carry the heat towards earth.

Unlike conduction and convection, radiation does not require any matter to transfer the heat energy.

Hence,

The sun transfers heat to earth through electromagnetic radiation. This method of heat transfer is evidence that direct contact is not necessary for heat to move from place to place.

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Answer:

Explanation:

Hope this helps! Have a great day/night!

The population of ducks will evolve so that most ducks are better at finding food in wet areas.

Natural selection:

In evolution, the individual is selected on a certain parameters by nature.

For example- Selection parameter  is ability of finding food.

Here, the popution good at finding food in dry places will die and only the individuals with ability to find food in wet places will survive and reproduce.

Therefore, the population of ducks will evolve so that most ducks are better at finding food in wet areas.

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Answer:

250 m

Explanation:

Refer to the attachment for the graph. Here, we are asked to calculate the distance travelled.

⇒ Area under the graph = Distance travelled by the body

Area of trapezium = ½ × Sum of parallel sides × Height

\( \twoheadrightarrow \quad \sf {S = \dfrac{1}{2}\times (AD + BC) \times OC} \\ \)

\( \twoheadrightarrow \quad \sf {S = \dfrac{1}{\cancel{2}}\times (10+30) \times \cancel{10}} \\ \)

\( \twoheadrightarrow \quad \sf {S = 1\times 50 \times 5} \\ \)

\(\twoheadrightarrow \quad \boxed{\red{\sf{ S = 250 \; m}}}\\\)

❝ Therefore, distance travelled by the body is 250 m. ❞

Drawing (d) best represents the system after the stopcocks are opened and the system is allowed to come to equilibrium, as it shows equal pressure in all three bulbs.

Since the two bulbs contain different gases, the pressures in each bulb will be different. When the stopcocks are opened, the gases will flow into the empty bulb until the pressures are equalized. The final state will have equal pressure in all three bulbs.

What is an equilibrium?

An equilibrium is a state of balance or stability achieved in a chemical reaction when the forward reaction rate is equal to the reverse reaction rate. In other words, it is the point at which the concentrations of reactants and products no longer change with time, because the rates of the forward and reverse reactions are equal.

At equilibrium, the amounts of reactants and products are governed by the equilibrium constant (K), which is a measure of the relative concentrations of the reactants and products at equilibrium.

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Answer:

Explanation:

The resistor R2 is shorted out, so is not in the circuit. The remaining resistors are in a series circuit with a total resistance of ...

  R1 +R3 +R4 = 1k +4.7k +1k = 6.7k

The current is the ratio of the applied voltage to this total resistance:

  I = V/R = (9 v)/(6.7k) ≈ 1.3433 mA

The voltage across each resistor is the product of this current value and the resistance:

  R1 voltage = (1 kΩ)(1.3433 mA) = 1.3433 volts

  R2 voltage = 0

  R3 voltage = (4.7 kΩ)(1.3433 mA) = 6.3134 volts

  R4 voltage = (1 kΩ)(1.3433 mA) = 1.3433 volts

Answer: Days and Height (cm).

Explanation:

11.76m is the maximum height achieved by a track star who goes into a long jump at 12m/s at an angle of 20.0 about the horizontal

Define projectile motion.

An object or particle that is projected into a gravitational field, such as from the surface of the Earth, and moves along a curved route only under the influence of gravity is said to be experiencing projectile motion.

Most calculations make the assumption that the effects of air resistance are passive and insignificant in the specific instance of Earth projectile motion. Galileo demonstrated that the curved path of objects in projectile motion is a parabola; however, in the unique situation where an object is hurled directly upwards, it may also be a straight line. Such a trajectory is a ballistic trajectory, which is the study of such movements.

v = u + at

a = g = 9.8m/s2

v = 0

u = 12 sin 20

t = 12 sin 20 /9.8 = 0.42 s

s = ut +1/2 at2

s = 12sin20 + 1/2 *9.8*0.42*0.42

s = 10.9 +.864 = 11.76m

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Answer:

Your answers are correct

Explanation:

In my opinion, your answers are grouped in the appropriate columns.

Answer:

amplification

Explanation:

reflection can happen

some amount of lighr get absorbed

something gets refracted

but amplification cant

Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.

Explanation:

Answer:

0.784 A

Explanation:

From the question,

Note that the current in the circuit is the same as the current flowing through the inductor since they are both connected in series.

I = VL/XL....................... Equation 1

Where I = current flowing through the circuit, VL = Voltage drop across the inductor,  XL = reactance of the inductor.

XL = 2πfL................. Equation 2

Given: f = 28.9 Hz, L = 1.07 H, π = 3.143

XL = 2(3.143)(28.9)(1.07)

XL = 194.38 Ω.

VL = V-Vf

VL = 170-17.6

VL = 152.4 V

Substitute these values into equation 1

I = 152.4/194.38

I = 0.784 A

The current in the circuit when combination is connected  should be 0.784 A.

SInce

we know that

I = VL/XL....................... Equation 1

Here,

I = current flowing through the circuit,

VL = Voltage drop across the inductor,  

XL = reactance of the inductor.

And,

XL = 2πfL................. Equation 2

Here

f = 28.9 Hz, L = 1.07 H, π = 3.143

So,

XL = 2(3.143)(28.9)(1.07)

XL = 194.38 Ω.

Now

VL = V-Vf

VL = 170-17.6

VL = 152.4 V

Now

I = 152.4/194.38

I = 0.784 A

hence, The current in the circuit when combination is connected  should be 0.784 A.

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Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).