Why do we feel cool after perspiration/sweating?

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Answer:

1). Average speed = 1.5 m per second

2). Average velocity = 1.5 m per second

Explanation:

1). Since, speed is a scalar quantity

   Therefore, average speed of the trip = \(\frac{\text{Total distance covered}}{\text{Total time taken}}\)

    From the graph attached,

   Total distance covered = 10 + 10 + 20 + 0 + 20 + 30

                                           = 90 meters

   Total time taken = 60 seconds

    Average speed = \(\frac{90}{60}\)

                               = 1.5 meter per second

2). Velocity is a vector quantity.

    Therefore, average velocity = \(\frac{\triangle d}{\triangle t}\)

                                                   = \(\frac{d_{60}-d_0}{60-0}\)

                                                   = \(\frac{90-0}{60-0}\)

                                                   = 1.5 meter per second                        

6.25 x 10^18 electrons are "lost" flowing through the resistor if the voltage across the resistor is 10V and the resistance is 10 ohms.

Ohm's law states that the current flowing through a conductor is directly proportional to the voltage applied across it, and inversely proportional to the resistance of the conductor. In mathematical terms, Ohm's law can be expressed as I = V/R, where I is the current, V is the voltage, and R is the resistance of the conductor.

To determine how many electrons are "lost" flowing through a resistor, we need to use the formula:

I = V/R

where I is the current flowing through the resistor, V is the voltage across the resistor, and R is the resistance of the resistor.

Once we have calculated the current flowing through the resistor, we can use the formula:

Q = I*t

where Q is the charge passing through the resistor, I is the current, and t is the time period for which the current flows.

Finally, we can use the formula:

n = Q/e

where n is the number of electrons passing through the resistor, Q is the charge passing through the resistor, and e is the charge on a single electron.

Using these formulas and given values, we can calculate the number of electrons "lost" flowing through the resistor as:

I = V/R = 10V / 10 ohms = 1A

Q = I*t = 1A * 1s = 1C

n = Q/e = 1C / 1.6 x 10^-19 C/electron = 6.25 x 10^18 electrons

Therefore, approximately 6.25 x 10^18 electrons are "lost" flowing through the resistor if the voltage across the resistor is 10V and the resistance is 10 ohms.

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The test statistic (Z-score) is approximately 4.95.

To calculate the test statistic (Z-score) for this hypothesis test, we can use the formula:

Z = (sample mean - hypothesized population mean) / (standard deviation / sqrt(sample size))

Sample mean (X-bar) = 37

Hypothesized population mean (μ) = 30

Standard deviation (σ) = 8

Sample size (n) = 50

Substituting these values into the formula, we get:

Z = (37 - 30) / (8 / sqrt(50))

Z = 7 / (8 / 7.071)

Z = 7 / 1.414

Z = 4.95 (rounded to two decimal places)

A statistical hypothesis test is a technique for determining if the available data are sufficient to support a certain hypothesis. We can make probabilistic claims regarding population parameters using hypothesis testing.

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1.  61.11 m will be traveled in this period of inattention.

time(t)=2.0s

distance(d)=?

average speed=110 km/h

We need to have same unit of speed and time , so convert the avg speed into m/s

= (110km/1h) * (1h/3600sec) * (1000m/1km)

= 30.55 m/s

average speed(s) = distance (d) / time(t)

d= s*t

 = (30.55 m/s) * 2s

 = 61.11 m

2.  Average speed of the car must be 72.307 km/h to cover 235 km in 3.25 h

distance(d) = 235 km

time(t) = 3.25 h

average speed(s) = distance (d) / time(t)

                              = 235 km / 3.25 h

                              = 72.307 km/h

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Answer:

Explanation:The refractive index of a medium is the ratio of the speed of light in vacuum or air to the speed of light in that medium. In this case, we can calculate the refractive index of water as follows:

Refractive index of water = Speed of light in air / Speed of light in water

Refractive index of water = 3 x 10^8 m/s / 2.26 x 10^8 m/s

Refractive index of water = 1.33 (rounded to two decimal places)

Therefore, the refractive index of water is approximately 1.33.

Answer:

light is an example of a wave that is not mechanical .

it is different as it does not need material medium for its propagation

Answer:

Solution given:

velocity=40cm/s

wave length=5cm

we have

frequency =velocity/wavelength=40/5=8hertz.

the frequency of the wave is 8 hertz.

The answers to the given questions are as follows:

a) To design a simple comparator using a single 741 op-amp, the threshold voltage (Vthreshold) can be calculated using the formula Vth = -(R2 / R1) × Vcc1. By choosing appropriate resistor values, the threshold voltage of 5V can be achieved.

b) For an AC input signal of amplitude 1.6V and frequency 200Hz, the output of the comparator will be LOW (-14V) since the input falls below the threshold voltage.

c) For an AC input signal of amplitude 5.2V and frequency 400Hz, the output of the comparator will be HIGH (+14V) since the input exceeds the threshold voltage.

d) It is not necessary to use two 741 op-amps for this application. A single 741 op-amp can be used to function as both a comparator and a voltage amplifier, creating the DC threshold voltage.

a) Designing a simple comparator using a single 741 op-amp whose output goes from HIGH to LOW whenever the input vs(t) falls below Vthreshold = 5 V:

The threshold voltage can be calculated using the below formula,

Vth= -( R2 / R1 ) × Vcc1

b) The output voltage of the comparator if v(t) is AC of amplitude 1.6 V and frequency 200 Hz:

The given input is

vs(t) = 1.6 V,

f = 200 Hz

As the input is less than Vthreshold, the output of the comparator will be LOW.

Output voltage = -Vcc2

                         = -14 V

c) The output of the comparator if vs(t) is AC with a 5.2 V amplitude and 400 Hz frequency:

The given input is

vs(t) = 5.2 V,

f = 400 Hz

As the input is greater than Vthreshold, the output of the comparator will be HIGH.

Output voltage = Vcc2

                         = +14 V.

d) Is the engineer right or is it okay to use a single 741 op-amp only?

When creating a DC threshold voltage, it is not necessary to use two op-amps as claimed by the engineer. A single op-amp is enough to act as a comparator and provide a buffer for the threshold voltage. Thus, the engineer is not correct and a single 741 op-amp can be used.

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The number of joules per coulomb for 120-volt circuit is 120 joules/C.

The amount of energy transferred to each unit of charge is given by the voltage or potential difference between two points.

The unit of potential difference is the volt, which is equivalent to one joule per coulomb.

So if we have a 120-volt circuit, each coulomb of charge that flows between two points receives 120 joules of energy.

Energy per unit charge = Potential difference

= 120 volts

= 120 joules/coulomb

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Answer:

Answer choice B!

Explanation:

Study Island work

Answer:A

I DID THIS ON STUDYILSLAND

Answer:

M¹L¹T^-2

Explanation:

M¹L¹T^-2

.....

Answer:

velocity

Explanation:

I think i dont really know

Answer:

Explanation:

A capacitor is an electronic component that stores and releases electrical energy. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied across the plates, charge accumulates on them, creating an electric field between the plates.

The capacitance of a capacitor is a measure of its ability to store charge. It is typically represented by the symbol 'C' and is measured in farads (F). In your case, you mentioned a 55-μF (microfarad) capacitor, indicating its capacitance value.

When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The rate at which the capacitor charges and discharges depends on the capacitance and the resistance in the circuit

Since there is no figure provided in the text, I am unable to reference it for the specific details of the voltage waveform. However, I can explain the general behavior of a capacitor when a voltage waveform is applied.

When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The behavior of the capacitor is determined by its capacitance, which is given as 55 μF in this case.

As the voltage waveform varies, the capacitor stores and releases electrical charge. During the rising portion of the waveform, the capacitor charges and accumulates energy. During the falling portion, the capacitor discharges and releases the stored energy.

The exact behavior and characteristics of the voltage waveform and the charging/discharging process depend on the specific shape and frequency of the waveform. Without the specific details of the voltage waveform provided in the figure, it is challenging to provide a more detailed analysis.

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The scale will read 147N

The mass of the object, m = 15 kg

Since I am on the earth, the acceleration due to gravity on the earth is:

g = 9.8 m/s²

The scale will read the weight of the object, and is calculated below

The weight, W = mg

W = 15(9.8)

W = 147 N

Therefore, the scale will read 147N

Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

Friction and the applied force are not balanced. The 7 N push is countered by the frictional force of 3 N to push the box with a net force of 4 N.

The relay stick is moving at 7 km/h relative to Ingrid.

Ingrid is jogging at a speed of 9 km/h and tosses the relay stick at a speed of 16 km/h to her team mate who is standing still.

The relative velocity of the relay stick with respect to Ingrid can be calculated using the relative velocity formula.

The formula states that the relative velocity of the stick with respect to Ingrid is equal to the difference between the velocities of the stick and Ingrid.

Therefore, the relative velocity of the relay stick with respect to Ingrid is 16 km/h - 9 km/h, which is equal to 7 km/h.

This means that the relay stick is moving at 7 km/h relative to Ingrid.

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The surface of Mercury looks much like Earth's moon. ... On its dark side, Mercury gets very cold because it has almost no atmosphere to hold in heat and keep the surface warm. The temperature can drop down to minus 300 degrees Fahrenheit. Sunlight never reaches into the bottoms of some craters near Mercury's poles.

Answer: B

Because Mercury is the closest planet to the sun

Explanation:

Hope this helps

The work done by the force on the particle is 39J and  the angle between F and s is 19.7 degree.

An item with mass is pulled or pushed which alters its velocity. A material that has the ability to change a body's rest or motion state is referred to as an external force. It possesses a magnitude and a direction.

Force F = (Fx, Fy)

Displacement S = (Sx,Sy)

Fx=10N

Fy=-1N

Sx=4m

Sy=1m

F=(10,-1)N and S=(4,1)m

Work done is calculated by taking dot product of force and displacement vector:

W=F·S

W=10×4 + (-1)×1

W=40+(-1)=39J

W = 39 J

To find angle between F and s:

\(|F|=\sqrt{10^2+(-1)^2}\)

|F| = √101

|S| = √(4² + 1²)

|S| = √17

W  = |F| |S| cosθ

39 = √101 √17 cosθ

θ = 19.7.

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1. Electron

2. Neutron

3. Nucleus

4. Atom

5. Molecule

Answer:

A) v₁ = 5.66 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conservation before and after a collision.

The linear momentum is equal to the mass by the product of the Velocity.

P = m*v

where:

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now, to the right side of the equal sign will take the linear momentum before the collision and to the left side of the equal sign as after the collision.

Pbefore = Pafter

(m₁*v₁) - (m₂*v₂) = (m₁*v₃) + (m₂*v₄)

where:

m₁ = mass of the car = 1450 [kg]

v₁ = velocity of the car before the collision [m/s]

m₂ = mass of the shopping cart = 60 [kg]

v₂ = velocity of the shopping cart before the collision = -1.2 [m/s]

v₃ = velocity of the car after the collision = 5.13 [m/s]

v₄ = velocity of the shopping cart after the collision = 11.75 [m/s]

Now replacing:

(1450*v₁) - (60*1.2) = (1450*5.13) + (60*11.75)

1450*v₁ - 72 = 7438.5 + 705

1450*v₁  = 7438.5 + 705 + 72

1450*v₁ = 8215.5

v₁ = 5.66 [m/s]

Answer:

5.67 m/s

Just did it.

It's important to know that the wavelength and the frequency has inverse relationship, which means the longest is its wavelength, the more intense will be the frequency.

Answer:

child i dont even know the answer for this question

Explanation:

Answer:

1). average velocity= displacement/time

= here displacement is zero

= 0/1

= 0 m/s

2). average speed= total distance/time

=2πr/1

=(2×22/7×5/10)/1

22/7

3.14 km/h

hope it helps you

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Explanation:

Answer:

\(\sf \fbox{speed = 3.14 kmph}\)

Explanation:

Given:

Radius of circular field (r) = 0.5 Km

Time taken to complete one round of field (t)= 1 hour

To find:

Average speed for the whole journey=?

Solution:

To find the average speed we will have to find the actual distance covered in given time, & the actual distance covered would be equal to the

\( \sf \: perimeter \: of \: circular \: field = 2 \pi r \\ \sf 2 \pi r = 2 \times 3.14 \times 0.5 = 3.14 \: km\)

Distance covered in 1 hour is 3.14 km,

\(\small \sf Average \: speed = \frac{Distance}{Time} = \frac{3.14}{1} \\ \small \sf \fbox{speed = 3.14 kmph}\)

\( \small\sf \: Thanks \: for \: joining \: brainly \: community! \)

The activity occurring at an axon terminal involves the following labelled 1 - 6:

The transmission of nerve impulses between neurons, muscles cells or glands is known as nervous transmissions.

Axons are long slender projections of neurons which are responsible for nervous transmission.

Neurons use both electrochemical signals and chemicals known as neurotransmitters to transmit impulses from one neuron to the next.

The junction between two neurons or an effector cell is known as a synapse.

Neurotransmitters are packaged into synaptic vesicles at the axon end. When electrical signal reaches the end of the axon, influx of calcium ions through the calcium channel cause the the synaptic vessels to fuse with the presynaptic membrane and then release their contents into the synaptic cleft or space.

The neurotransmitters released then bind to the motor end plate resulting in another impulse transmission along the second neuron or an action by effector cells.

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Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

Answer:

output force is exerted on a machine

Answer:

output force is exerted in the machine , i guess